3/ Tính hợp lí :
a/ (- 25).(- 125).(- 4). (- 8)
b/ (- 50).(- 80).(- 2).(- 9)
1. tính bằng cách hợp lí :
a. 5 . 125 . 2 . 41 . 8 = c. 8 . 12 . 125 . 2 =
b. 25 . 7 . 10 . 4 = d. 4 . 36. 25 . 50 =
a) 5 . 125 . 2 . 41 . 8
= (5 . 8) . (125 . 2) . 41
= 40 . 250 . 41
= 10 000 . 41
= 410 000
b) 25 . 7 . 10 . 4
= (25 . 4 ) . (10 . 7)
= 100 . 70
= 7000
Chúc bạn học tốt!! ^^
a,5.125.2.41.8=(125.8).(2.5).41=1000.10.41=410000
b,25.7.10.4=(25.4).70=100.70=7000
c,8.12.125.2=(8.125).12.2=100.24=2400
d,4.36.25.50=(4.25).(2.50).18=100.100.18=180000
c) 8 . 12 . 125
= (125 . 8) . 12
= 1000 . 12
= 12 000
d) 4 . 36 . 25 . 50
= (25 . 4) . (50 . 36)
= 100 . 1800
= 180 000
Chúc bạn học tốt!! ^^
Bài 2: Tính hợp lí
1) 125.(-24) + 24.225
2) 512.(2 – 128) – 128. (-512)
3) (187 -23) – (20 – 180)
4) (-37 – 17). (-9) + 35. (-9 – 11)
5) (-50 +19 +143) – (-79 + 25 + 48)
6) (-8).25.(-2). 4. (-5).125
7) 3784 + 23 – 3785 – 15
8) 215 +(-38) – (-58) –15
9) 5.(-3)2 –14.(-8)+(-40)
10) 215 + (-38) – (- 58) + 90 – 852)
Bài 3*: Tìm các cặp số nguyên (x;y) thỏa mãn xy2 + 2x – y2 =
1) 125.(-24) + 24.225.
\(=24\left(-125+225\right)=24.100=2400.\)
2) 512.(2 – 128) – 128. (-512).
\(=512\left(2-128+128\right)=512.2=1024.\)
1. Tính hợp lí nếu có thể :
a) 125 + 80 + 375 + 220
b) 25.11.8.4.125
c) 18.74 + 18.27 - 18
d) 75 . 23 + 75 . 77 - 500
e) 150 : [25.(18-42)]
f) 125 . 23 . 2 . 8 . 50
g) 235 + 88 + 165 + 12
h) 71 . 32 + 71 . 68 - 1100
i) 67 : 66 + 43 .2 - 240
j) 546 - 6. [158 : (30 + 72)]
k) 268 + 147 + 132 + 253
2. Tìm số tự nhiên x, biết :
a) 7 . x = 707
b) 6x + 5 = 47
c) 35 : (x+1) = 7
d) 12 + (29 - 3x) = 35
e) 2.4x + 101 = 138
f) 7 . x = 140
g) 7 . (15 - x) + 14 = 84
h) 3x . 5 - 15 = 390
3. Tìm số tự nhiên n , biết :
(n+11) chia hết cho (n+1)
1.
a) \(125+80+375+220\)
\(=\left(125+375\right)+\left(80+220\right)\)
\(=500+300\)
\(=800\)
b) \(25.11.8.4.125\)
\(=\left(25.4\right).\left(8.125\right).11\)
\(=100.1000.11\)
\(=1100000\)
c) \(18.74+18.27-18\)
\(=18.\left(74+27-1\right)\)
\(=18.100\)
\(=1800\)
d) \(75.23+75.77-500\)
\(=75.\left(23+77\right)-500\)
\(=75.100-500\)
\(=7500-500\)
\(=7000\)
e) \(150:\left[25.\left(18-4^2\right)\right]\)
\(=150:\left[25.\left(18-16\right)\right]\)
\(=150:\left[25.2\right]\)
\(=150:50\)
\(=3\)
f) \(125.23.2.8.50\)
\(=\left(125.8\right).\left(2.50\right).23\)
\(=1000.100.23\)
\(=2300000\)
g) \(235+88+165+12\)
\(=\left(235+165\right)+\left(88+12\right)\)
\(=400+100\)
\(=500\)
h) \(71.32+71.68-1100\)
\(=71.\left(32+68\right)-1100\)
\(=71.100-1100\)
\(=7100-1100\)
\(=6000\)
i) \(6^7:6^6+4^3.2-24^0\)
\(=6+64.2-1\)
\(=6+128-1\)
\(=133\)
j) \(546-6.\left[158:\left(30+7^2\right)\right]\)
\(=546-6.\left[158:\left(30+49\right)\right]\)
\(=546-6.\left[158:79\right]\)
\(=546-6.2\)
\(=546-12\)
\(=534\)
k) \(268+147+132+253\)
\(=\left(268+132\right)+\left(147+253\right)\)
\(=400+400\)
\(=800\)
2.
a) \(7x=707\)
\(x=707:7\)
\(x=101\)
b) \(6x+5=47\)
\(6x=47-5\)
\(6x=42\)
\(x=42:6\)
\(x=7\)
c) \(35:\left(x+1\right)=7\)
\(x+1=35:7\)
\(x+1=5\)
\(x=5-1\)
\(x=4\)
d) \(12+\left(29-3x\right)=35\)
\(29-3x=35-12\)
\(29-3x=23\)
\(3x=29-23\)
\(3x=6\)
\(x=6:3\)
\(x=2\)
e) \(2.4^x+10^1=138\)
\(2.4^x=138-10\)
\(2.4^x=128\)
\(4^x=128:2\)
\(4^x=64=4^3\)
\(\Rightarrow x=3\)
f) \(7x=140\)
\(x=140:7\)
\(x=20\)
g) \(7\left(15-x\right)+14=84\)
\(7\left(15-x\right)=84-14\)
\(7\left(15-x\right)=70\)
\(15-x=70:7\)
\(15-x=10\)
\(x=15-10\)
\(x=5\)
h) \(3^x.5-15=390\)
\(3^x.5=390+15\)
\(3^x.5=405\)
\(3^x=405:5\)
\(3^x=81=3^4\)
\(\Rightarrow x=4\)
3.
Ta có:
\(\Rightarrow n+11⋮n+1\)
\(\Rightarrow n+1+10⋮n+1\)
\(\Rightarrow10⋮n+1\) hay \(n+1\inƯ\left(10\right)=\left\{-10;-5;-2;-1;1;2;5;10\right\}\)
\(\Rightarrow\) \(n\in\left\{-11;-6;-3;-2;0;1;4;9\right\}\)
Vì \(n\in N\) nên \(n\in\left\{0;1;4;9\right\}\)
tính 1 cách hợp lí
A=-25*(35+147)+35*(25+147)
B=125*9*(-4)*(-8)*25*7
tính hợp lí nếu có thể :
A = [-506 + 732 - (-2000) - (506 - 1732)
C = (125 . 73 - 125 . 75) : (-25 . 2)
E = 125 . 9 . (-4) . (-8) . 25 . 7
B = 1037 + {743 - [1031 - (+57)]}
D = -25 . (35 + 147) + 35 . (25 + 147)
G = (-3)2 + (-5)3 : |-5|
Tính hợp lí:
a) 125. ( -24 ) + 24 . 225
b) 24. ( -125 ) - 125. ( -36 )
c) 512. ( 2- 128 ) - 128. ( -512 )
d) ( -8 ). 25 .( -2 ). 4 .( -5 ). 125
a. 24 x (-125 + 225)
= 24 x 100
=2400
b. -125 x ( 24 -36 )
= -125 x -12
= 1500
c. 512 x (2 -128+128)
= 512 x 2
= 1024
d. \([4.25].\left[\left(-2\right).\left(-5\right)\right].\left[125.\left(-8\right)\right]\)
= 100.10.(-1000)
= -1000000
a. 24 x (-125 + 225)
= 24 x 100
=2400
b. -125 x ( 24 -36 )
= -125 x -12
= 1500
c. 512 x (2 -128+128)
= 512 x 2
= 1024
d.
= 100.10.(-1000)
= -1000000
tính 1 cách hợp lí nếu có thể :
A = - [ - 506 + 732 - ( - 2000 ) ] - ( 506 - 1732 )
B = 1037 + { 743 - [ 1031 - ( + 57 ) ] }
C = ( 125 .73 - 125 . 75 ) : ( - 25 .2 )
D = - 25 . ( 35 + 147 ) + 35 . ( 25 + 147 )
E = 125 . 9 . ( - 4 ) . ( - 8 ) . 25 . 7
G = ( -3 )2 + ( - 5 )3 : I - 5 I .
A=-506+732+2000-506-1732
A=(-506-506)+(2000-1732)+2000
A=0+268+2000
=>A=2268
Tính bằng cách hợp lí
a, A = 2*3*4*8:25:125
B = 32*547*906*16
Tính một cách hợp lí giá trị biểu thức:
a,A=(-8) x 25 x (-2) x (-5) x 125
b,B=19 x 25+9 x 25+19x30