\(216:x-117:x+18:x=9\)

\(\Rightarrow\left(216-117+18\right):x=9\)

\(\Rightarrow117:x=9\)

\(\Rightarrow x=117:9\)

\(\Rightarrow x=13\)

Vậy x=13

a) \(216:x-117:x+18:x=9\)

\(\dfrac{216}{x}-\dfrac{117}{x}+\dfrac{18}{x}=9\)

\(\dfrac{1}{x}.\left(216-117+18\right)=9\)

\(\dfrac{117}{x}=9\)

\(x=117:9=13\)

\(...\left(256-215\right).x=29643\)

\(41.x=29643\)

\(x=29643:41=723\)

Dấu . là dấu nhân

mà dấu * mới là dấu nhân nhé trí

ai nhanh nhanh giải giúp mk bài này với huhu

cho tớ hỏi đề câu a là:6^2x+5  hay là 6^2x+5

làn sau bn ghi rõ đề nhé,để mình suy ngĩ nữa

Ghi lại đề cho mình,mình nháp cho

ko đảm bảo ra đâu

\(a,6^{2x+5}=216^3.36^3\)

\(6^{2x}.6^5=\left(6^3\right)^3.\left(6^2\right)^3\)

\(6^{2x}.6^5=6^9.6^6\)

\(6^{2x}.6^5=6^{15}\)

\(6^{2x}=6^{10}\)

\(2x=10\)

\(x=10:2\)

\(\Rightarrow x=5\)

ý b ko có dấu ngoặc rõ ràng nên .Đề sai ( xem lại nhé !!!)

theo đề bài ta có

(a + 2) x b = 175

=>a*b+2b=175

mà a*b=105=>b=(175-105):2=30

vi b=30 =>a=75

vay a=70,b=30

tớ ghi dấu nhân là *

          \(\frac{x+5}{105}+\frac{x+1}{109}=-\frac{x+113}{3}-\frac{x+117}{7}\)

\(\Leftrightarrow\)\(\frac{x+5}{105}+1+\frac{x+1}{109}+1=-\frac{x+113}{3}+1-\frac{x+117}{7}+1\)

\(\Leftrightarrow\)\(\frac{x+110}{105}+\frac{x+110}{109}=-\frac{x+110}{3}-\frac{x+110}{7}\)

\(\Leftrightarrow\)\(\frac{x+110}{105}+\frac{x+110}{109}+\frac{x+110}{3}+\frac{x+110}{7}=0\)

\(\Leftrightarrow\)\(\left(x+110\right)\left(\frac{1}{105}+\frac{1}{109}+\frac{1}{3}+\frac{1}{7}\right)=0\)

\(\Leftrightarrow\)\(x+110=0\)  (do  1/105 + 1/109 + 1/3 + 1/7 # 0)

\(\Leftrightarrow\)\(x=-110\)

Vậy,...

`#3107`

`a)`

`(x - 20)^3 = -64`

`\Rightarrow (x - 20)^3 = (-4)^3`

`\Rightarrow x - 20 = -4`

`\Rightarrow x = -4 + 20`

`\Rightarrow x = 16`

Vậy, `x = 16.`

`b)`

`9(x + 1) - 11(x + 7) = 105 - 1`

`\Rightarrow 9(x + 1) - 11(x + 7) = 104`

`\Rightarrow 9x + 9 - 11x - 77 = 104`

`\Rightarrow (9 - 11)x + (9 - 77) = 104`

`\Rightarrow -2x - 68 = 104`

`\Rightarrow -2x = 104 + 68`

`\Rightarrow -2x = 172`

`\Rightarrow x = 172 \div (-2)`

`\Rightarrow x = -86`

Vậy,` x = -86.`

a) Ta có ( x - 20 )³ = -64 = ( -4 )³

⇒ x - 20 = -4

⇒ x = 20 + ( -4 ) = 16

b) Ta có 9 ( x + 1 ) - 11 ( x + 7 ) = 105 - 1

⇒ 9x + 9 - 11x - 77 = 104

⇒ ( -2 ) . x - 68 = 104

⇒ ( -2 ) . x = 104 - 68 = 36

⇒ x = 36 : ( -2 ) = -18

a)

\(\left(x-20\right)^3=-64\)

\(\left(x-20\right)^3=-4^3\)

\(\Rightarrow x-20=-4\)

\(\Rightarrow x=-4+20=16\)

b)

\(9\left(x+1\right)-11\left(x+7\right)=105-1\)

\(9\left(x+1\right)-11\left(x+1+6\right)=104\)

\(9\left(x+1\right)-11\left(x+1\right)+66=104\)

\(\left(x+1\right).\left(9-11\right)=104-66\)

\(\left(x+1\right).\left(-2\right)=38\)

\(x+1=38:\left(-2\right)\)

\(x+1=-19\)

\(x=-19-1\)

\(x=-20\)

c: =117-89-223-71+105+111+223

=6-160

=-154

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