tim x:( 5-X)x3
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tim x biet ( 13/4- x x8/5) x3=4
nhanh lên mik tích cho mình gấp lắm
\(\left(\frac{13}{4}-x.\frac{8}{5}\right).3=4\)
\(\left(\frac{13}{4}-x\cdot\frac{8}{5}\right)=4:3\)
\(\frac{13}{4}-x\cdot\frac{8}{5}=\frac{4}{3}\)
\(x\cdot\frac{8}{5}=\frac{13}{4}-\frac{4}{3}\)
\(x\cdot\frac{8}{5}=\frac{23}{12}\)
\(x=\frac{23}{12}:\frac{8}{5}\)
\(x=\frac{115}{96}\)
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Cau 1:
Tim x, biet: 1-4+7-10+.............-x=-75
Cau 2:
Cho x1, x2, x3, x4, x5 thuộc Z
Biết x1+ x2 + x3 + x4 + x5=0
và x1 + x2=x3+ x4= x4 + x5 =2
Tinh x3, x4 , x5
Cau 3: Tim x biet
(x+7+1) chia het cho (x+7)
Tim X
3) -12 + (2x – 9) + x= 0
4) 11 + (15 - x) = 1
5) 4 - (27 - 3) = x - (13 - 4)
6) 8 - (x - 10) = 23 - (- 4 +12)
7) 105 – 5(10 – 5x) = -20
8) (x -1)(8-2x)(3x+123) = 0
9) (x2 - 25)(x+ 10) = 0
10) x(x2+5) =
3) \(-12+2x-9+x=0\\ -21+3x=0\\ 3x=21\\ x=7\)
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4)
\(11+\left(15-x\right)=1\)
\(15-x=1-11\)
\(15-x=-10\)
\(x=15-\left(-10\right)\)
\(x=25\)
5)
\(4-\left(27-3\right)=x-\left(13-4\right)\)
\(4-24=x-9\)
\(x-9=-20\)
\(x=-20+9\)
\(x=-11\)
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\(3.-12+\left(2x-9\right)+x=0.\)
\(\Leftrightarrow-12+2x-9+x=0.\Leftrightarrow3x=21.\Leftrightarrow x=7.\)
Vậy \(x=7.\)
\(4.11+\left(15-x\right)=1.\Leftrightarrow11+15-x=1.\Leftrightarrow26-x=1.\Leftrightarrow x=25.\)
Vậy \(x=25.\)
\(5.4-\left(27-3\right)=x-\left(13-4\right).\Leftrightarrow4-24=x-9.\Leftrightarrow-20=x-9.\Leftrightarrow x=-11.\)
Vậy \(x=-11.\)
\(6.8-\left(x-10\right)=23-\left(-4+12\right).\Leftrightarrow8-x+10=23-8.\Leftrightarrow18-x=15.\Leftrightarrow x=3.\)
Vậy \(x=3.\)
\(7.105-5\left(10-5x\right)=-20.\Leftrightarrow105-50+25x=-20.\Leftrightarrow25x=-75.\Leftrightarrow x=-3.\)
Vậy \(x=-3.\)
\(8.\left(x-1\right)\left(8-2x\right)\left(3x+123\right)=0.\)
\(\Leftrightarrow\left[{}\begin{matrix}x-1=0.\\8-2x=0.\\3x+123=0.\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1.\\x=4.\\x=-41.\end{matrix}\right.\)
Vậy \(x\in\left\{1;4;-41\right\}.\)
\(9.\left(x^2-25\right)\left(x+10\right)=0.\)
\(\Leftrightarrow\left(x-5\right)\left(x+5\right)\left(x+10\right)=0.\)
\(\Leftrightarrow\left[{}\begin{matrix}x-5=0.\\x+5=0.\\x+10=0.\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5.\\x=-5.\\x=-10.\end{matrix}\right.\)
Vậy \(x\in\left\{5;-5;-10\right\}.\)
\(10.x\left(x^2+5\right)=0.\Leftrightarrow x=0.\)
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Tim nghien cua da thuc
a)A(x)=-4x-5 h)K(x)=/3x-2/+/4-6x/
b)B(x)=3(2x-1)-2(x + 1) i)M(x)=/x-1/+(x2-1)2
c)C(x)=(2x2-8)(-x2+1) j)N(x)=4x2-3x+7
d)D(x)=3x-x3 k)Pk(x)=7x2-2x-9
l)Q(x)=5x2-11x+6
e)E(x)=2x3+4x
f)G(x)=x3-x2+x-1
a) Đặt A(x)=0
\(\Leftrightarrow-4x-5=0\)
\(\Leftrightarrow-4x=5\)
hay \(x=-\dfrac{5}{4}\)
b) Đặt B(x)=0
\(\Leftrightarrow3\left(2x-1\right)-2\left(x+1\right)=0\)
\(\Leftrightarrow6x-3-2x-2=0\)
\(\Leftrightarrow4x=5\)
hay \(x=\dfrac{5}{4}\)
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tim x
X x3+ X :3 = X + 2/3
\(x\cdot3+x:3=x+\frac{2}{3}\)
\(x\cdot3+x\cdot\frac{1}{3}-x=\frac{2}{3}\)
\(x\left(3+\frac{1}{3}-1\right)=\frac{2}{3}\)
\(x\cdot\frac{7}{3}=\frac{2}{3}\)
\(x=\frac{2}{7}\)
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bài 1: tim x, biết
a,x.(x - 2) + x - 2 = 0
b,x3 + x + x + 1 = 0
c,5x.(x - 4) = 2x + 8
d,(5x - 4)2 - 49x2 = 0
a,x(x-2)+x-2=0
⇔ (x-2)(x+1)=0
⇔ x=2;x=-1
b,x3+x2+x+1=0
⇔ x2(x+1)+x+1=0
⇔ (x+1)(x2+1)=0
⇔ x=-1
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Bai 1: Tim ab ; biet ab = b x 9
Bai 2 : Tim ab, biet :
a) ab x 5 = 2ab b) ab = 4ab / 9.
Bai 3 : Tim ab, biet : a 2 = b x 5
Bai 4 : Tim cac so ab biet :
a) a x3 = bx9 b) a x4 = b x6.
Bai 5 :
a) Tim abc, biet a , b , c khac nhau va : a x bc = 91.
b) Tim a , b , c khac nhau biet aa x bc = 1001
(1/4xX-1/8)x3/4=1/4
Tim x
(1/4x X -1/8 ) x 3/4 =1/4 1/4 x X -1/8 = 1/4 : 3/4 ( tìm thừa số ) 1/4 x X - 1/8 = 1/3 1/4 x X = 1/3 + 1/8 ( tìm số hạng ) 1/4 x X = 11/24 X = 11/24 : 1/4 ( tìm thừa số ) X = 11/6
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3 + 4 + 5 + 6 + 7 + 8 + 9 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 0 x 3 x 3 x 3 x 3 x 3 x3 x3 x3 x3 x33 x3 x3 x3 =
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3 + 4 + 5 + 6 + 7 + 8 + 9 x3 x 3 x 3 x 3 x 3x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 0 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 33 x 3 x 3 x 3=0
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