2 phan x = x phan 8
Tim so nguyen x , biet : 1 phan 6 = x phan 18 ; x phan 8 = -1 phan 4 ; 4 phan -5 = x phan 10 ; 11 phan 5 = -22 phan x ; x phan 8 = 8 phan x ; x phan -11 = -11 phan x
\(\frac{1}{6}=\frac{x}{18}\Rightarrow x=3\)
\(\frac{x}{8}=-\frac{1}{4}\Rightarrow x=-2\)
\(\frac{4}{-5}=\frac{x}{10}\Rightarrow x=-8\)
\(\frac{11}{5}=-\frac{22}{x}\Rightarrow x=-10\)
\(\frac{x}{8}=\frac{8}{x}\Rightarrow x^2=64\Rightarrow x=8\)
\(\frac{x}{-11}=-\frac{11}{x}\Rightarrow x^2=121\Rightarrow x=11\)
#H
1 phan 4 :(x phan 4 + (-2) phan 7 + 2 phan 8)=(-1) phan 14
\(\frac{1}{4}:\left(\frac{x}{4}+\frac{\left(-2\right)}{7}+\frac{2}{8}\right)=\frac{\left(-1\right)}{14}\)
\(\frac{1}{4}:\left(\frac{x}{4}+\frac{\left(-1\right)}{28}\right)=\frac{\left(-1\right)}{14}\)
\(\frac{x}{4}+\frac{\left(-1\right)}{28}=\frac{1}{4}:\frac{\left(-1\right)}{14}\)
\(\frac{x}{4}+\frac{\left(-1\right)}{28}=\frac{-7}{2}\)
\(\frac{x}{4}=\frac{-7}{2}-\frac{\left(-1\right)}{28}\)
\(\frac{x}{4}=\frac{-97}{28}\)
\(\frac{7x}{28}=\frac{-97}{28}\)
\(\Rightarrow7x=-97\)
\(\Rightarrow x=-97:7\)
\(\Rightarrow x=\frac{-97}{7}\)
Váy \(x=\frac{-97}{7}\)
Nhớ k cho mk nha Le Ha Trang
x + x +1 phan 2 + x + 8 phan 10 = 136 .Tim x
tính phep nhan x phan x +2-x^3 phan x^3+8 . x^2-2x+4 phần x^2 -4
\(\dfrac{x}{x+2}-\dfrac{x^3}{x^3+8}\cdot\dfrac{x^2-2x+4}{x^2-4}\\ =\dfrac{x}{x+2}-\dfrac{x^3}{\left(x+2\right)\left(x^2-2x+4\right)}\cdot\dfrac{x^2-2x+4}{\left(x-2\right)\left(x+2\right)}\\ =\dfrac{x}{x+2}-\dfrac{x^3}{\left(x+2\right)^2\left(x-2\right)}\\ =\dfrac{x\left(x^2-4\right)-x^3}{\left(x+2\right)^2\left(x-2\right)}=\dfrac{x^3-4x-x^3}{\left(x+2\right)^2\left(x-2\right)}=\dfrac{-4x}{\left(x+2\right)^2\left(x-2\right)}\)
1 phan 5 nhan 8 cong 1 phan 8 nhan 11 cong 1 phan 11 nhan 14 +..........+1 phan x nhan (x+3)=101 phan 1540
1 phan 5 nhan 8 cong 1 phan 8 nhan 11 cong 1 phan 11 nhan 14 +..........+1 phan x nhan (x+3)=101 phan 1540
\(\frac{1}{5.8}+\frac{1}{8.11}+...+\frac{1}{x.\left(x+3\right)}=\frac{101}{1540}\)
\(\frac{3}{5.8}+\frac{3}{8.11}+...+\frac{3}{x.\left(x+3\right)}=\frac{303}{1540}\)
\(\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{x}-\frac{1}{x+3}=\frac{303}{1540}\)
\(\frac{1}{5}-\frac{1}{x+3}=\frac{303}{1540}\)
\(\frac{1}{x+3}=\frac{1}{308}\)
\(\Rightarrow x+3=308\)
\(x=305\)
1 phan 5 nhan 8 cong 1 phan 8 nhan 11 cong 1 phan 11 nhan 14 +..........+1 phan x nhan (x+30+101 phan 1540
\(\frac{1}{5.8}+\frac{1}{8.11}+\frac{1}{11.14}+...+\frac{1}{x.\left(x+30+\frac{101}{1540}\right)}\)
Phải gì không .
ghi nham la the nay
1 phan 5 nhan 8 cong 1 phan 8 nhan 11 cong 1 phan 11 nhan 14 +..........+1 phan x nhan (x+3)=101 phan 1540
tim x, y thuoc Z biet 3/x/ phan 2 +5/y/ phan 3=8
2 phan 5 mu x-2=8 phan 12
\(\frac{2}{5^{x-2}}\)=\(\frac{8}{12}\)
=>2.12=8.5x-2
24 =8.5x-2
mà số nào nhân với 5 cũng cón số hàng đơn vị là 5 và 0
mà 8.5x-2=24
=> x\(\in\)tập hợp rỗng