a; \(\dfrac{93}{17}\): \(x\) + (- \(\dfrac{21}{17}\)) : \(x\) + \(\dfrac{22}{7}\): \(\dfrac{22}{3}\) = \(\dfrac{5}{14}\)

   \(\dfrac{94}{17}\) \(\times\) \(\dfrac{1}{x}\) - \(\dfrac{21}{17}\) \(\times\) \(\dfrac{1}{x}\) + \(\dfrac{3}{7}\) = \(\dfrac{5}{14}\)

    \(\dfrac{72}{17}\) \(\times\) \(\dfrac{1}{x}\) + \(\dfrac{3}{7}\) = \(\dfrac{5}{14}\)

     \(\dfrac{72}{17x}\)        = \(\dfrac{5}{14}\) - \(\dfrac{3}{7}\)

      \(\dfrac{72}{17x}\)      = - \(\dfrac{1}{14}\)

      17\(x\)       = 72.(-14)

       17\(x\)     = - 1008

         \(x\)       = - 1008 : 17

         \(x\)       = - \(\dfrac{1008}{17}\)

Vậy \(x\) \(=-\dfrac{1008}{17}\)

b; - \(\dfrac{32}{27}\) - (3\(x\) - \(\dfrac{7}{9}\))³ = - \(\dfrac{24}{27}\)

          - \(\dfrac{32}{27}\)  + \(\dfrac{24}{27}\) = (3\(x\) - \(\dfrac{7}{9}\))³ 

          (3\(x-\dfrac{7}{9}\))³ = - \(\dfrac{8}{27}\)

         (3\(x-\dfrac{7}{9}\))³ = (- \(\dfrac{2}{3}\))³

           3\(x-\dfrac{7}{9}\) = - \(\dfrac{2}{3}\)

           3\(x\)        = - \(\dfrac{2}{3}\) + \(\dfrac{7}{9}\)
           3\(x\)        = \(\dfrac{1}{9}\)

             \(x\)        = \(\dfrac{1}{9}\) : 3

             \(x\)       = \(\dfrac{1}{27}\)

Vậy \(x=\dfrac{1}{27}\)

\(a,C1=744+186\\ =930\\ C2=93\times\left(8+2\right)\\ =93\times10=930\\ b,C1:=324+576\\ =900\\ C2=9\times\left(36+64\right)\\ =9\times100\\ =900\\ c,C1=456-399\\ =57\\ C2=57\times\left(8-7\right)\\ =57\)

\(a)\)\(93\times8+93\times2\)

\(=98\times\left(8+2\right)\)

\(=98\times10\)

\(=980\)

\(b)36\times9+64\times9\)

\(=9\times\left(36+64\right)\)

\(=9\times100\)

\(=900\)

\(c)57\times8+57\times7\)

\(=57\times\left(8-7\right)\)

\(=57\times1\)

\(=57\)

`#3107.101107`

A,

\(2\times32\times12+4\times6\times41+8\times27\times3\\ =24\times32+24\times41+24\times27\\ =24\times\left(32+41+27\right)\\ =24\times100\\ =2400\)

B,

\(\left(2006\times2005^{2016}-2005^{2016}\right)\div2005^{2017}\\ =\left[2005^{2016}\times\left(2006-1\right)\right]\div2005^{2017}\\ =\left(2005^{2016}\times2005\right)\div2005^{2017}\\ =2005^{2017}\div2005^{2017}\\ =1\)

Help

2 x 3 x 12 + 4 x 6 x 42 + 8 x 27 x 3

= 2 x 12 x 3 + 4 x 6 x 42 + 8 x 3 x 27

= 24 x 3 + 24 x 42 + 24 x 27

= 24 x ( 3 + 42 + 27 )

= 24 x 72

= 1728

Nho tick cho minh nhe ban😁

\(8,64\times93+8,64:0,5+8,64:0,25+8,64\)

\(=8,64\times93+8,64\times2+8,64\times4+8,64\times1\)

\(=8,64\times\left(92+4+2+1\right)\)

\(=8,64\times100\)

\(=864\)

giúp mh với mh đang cần gấp 

hứa mh sẽ tích

a) \(x+\left(-10\right)-\left[87+\left(-41\right)+\left(-20\right)-x\right]\)

\(=x-10-\left(87-41-20-x\right)=x-10-87+41+20+x\)

\(=\left(x-x\right)+\left(20-10\right)-\left(87-41\right)=10-46=-36\)

b) \(a+\left(250-186\right)-\left(270-186\right)=a+250-186-270+186\)

\(=a+\left(250-270\right)+\left(186-186\right)=a-20\)

c) \(b-\left(393+170\right)+\left(93+170\right)=b-393-170+93+170\)

\(=b+\left(170-170\right)-\left(393-93\right)=b-300\)

d) \(-\left(a-b+c\right)-\left(a+b+c\right)=-a+b-c-a-b-c=-2a-2c\)

@Vũ Cao Minh⁀ᶦᵈᵒᶫ Phèn=)

Cảm ơn nhìu lắm =)

a) x + (- 10) - [ 87 + ( - 41 ) + ( - 20 ) - x]

= x - 10 - 87 + 41 + 20 + x 

= 2x - 36 

b) a + ( 250 - 186 ) - ( 270 - 186 )

= a + 250 - 186 - 270 + 186 

= a - 20 

c) b - ( 393 + 170 ) + ( 93 + 170 )

=  b -  393 - 170  +  93 + 170 

= b - 300

 d) - ( a - b + c ) - ( a + b + c )

= - a + b - c - a - b - c

= - 2a - 2c

a, 64 x 7 + 81 x 93 + 17 x 7

= 7 x ( 64 + 17 ) + 81 x 93

= 7 x 81 + 81 x 93

= 81 x ( 93 + 7 )

= 81 x 100

= 8100

a) 64 x 7 + 81 x 93 + 17 x 7

= 7 x ( 64 + 17 ) + 81 x 93

= 7 x 81 + 81 x 93

= 81 x ( 7 + 93 )

= 81 x 100

= 8100

8100 ban nhe

64 x X + X + 32 x X + X x 3 = 805

(64+1+32+3) x X = 805

100 x X = 805

X = 805: 100

X = 8,05

2008 x 68 + 32 x 2008

= 2008 x (68 +32)

= 2008x100= 200800

64 x X + X + 32 x X + X x 3 = 805

X x ( 64 + 1 + 32 + 3 ) = 805

X x ( 65 + 35 ) = 805

X x 100 = 805

X = 805 : 100

X = 8,05

2008 x 68 + 32 x 2008

= 2008 x ( 68 + 32 )

= 2008 x 100

= 200800