1/1.2 + 1/2.3 + 1/3.4 + ... + 1/99.100

= 1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + ... + 1/99 - 1/100

= 1 - 1/100

= 99/100

v

Answer:

\(\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+...+\dfrac{1}{99.100}\)

\(=\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{99}-\dfrac{1}{100}\)

\(=1-\dfrac{1}{100}\)

\(=\dfrac{100}{100}-\dfrac{1}{100}\)

\(=\dfrac{99}{100}\)

hi bn

\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{99}-\dfrac{1}{100}=1-\dfrac{1}{100}=\dfrac{99}{100}\)

\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{99.100}=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{99}-\frac{1}{100}=1-\frac{1}{100}=\frac{99}{100}\)

1/(1.2)+1/(2.3)+1/(3.4)+...+1/(99.100)

=1-1/2+1/2-1-1/3+1/3-1/4+...+1/99-1/100

=1-1/100

=99/100

tôi không chép bài giang ho đai ca đâu nha.

=1-1/2+1/2-1/3+.....+1/99-1/100

=1-1/100

=99/100

= 99/100

1/1.2+1/2.3+1/3.4+......+1/99.100

=1-1/2+1/2-1/3+1/3-1/4+..........+1/99-1/100

=1-1/100

=99/100

A=1-1/2+1/2-1/3+1/3-1/4+.....+1/99-1/100

A=1/100-1

A=99/100

A=1/1-1/2+1/2-1/3+1/3-1/4+...............+1/99-1/100

A=1/1-1/100

A=100/100-1/100

A=99/100

Mk ko chép đề bài

\(A=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}.+.....+\frac{1}{99}-\frac{1}{100}\)

\(A=1-\frac{1}{100}\)

\(A==\frac{99}{100}\)

kết quả = 99/100 tick mik đúng nhé

1/1.2 + 1/2.3 + .................+ 1/99.100 =

1/1 - 1/2 + 1/2 - 1/3 +....................+ 1/99 - 1/100 =

1/1 - 1/100                                                         =   99/100

98.99/99.100

99/100

giúp vs

= 1- 1/2 + 1/2 - 1/3 + 1/3 - 1/4 +... + 1/99 - 1/100

= 1 - 99/100

= 1/100.

\(\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+...+\dfrac{1}{99.100}\)

=\(\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{99}-\dfrac{1}{100}\)

=\(\dfrac{1}{1}-\dfrac{1}{100}=\dfrac{100}{100}-\dfrac{1}{100}\)

=\(\dfrac{99}{100}\)