1.a)4x^4× (4x^4+2x^2)
b) 4x^4 - 2x^2×(3x^3+2x)
c) (3x^3-2y)×(5x^3+3y)
d) (a^3+3ab-b^2) ×(2a-b)
a,(3+1)(x-1)
b,5x(3x-2)
c,3x^2y+6xy^2-9xy):3xy
d,(3x^4-6x^3+4x^2):2x^y
e,(8x^4y^3-4x^3y^2+x^2y^2):2x^2y^2
a,4xy^2-3x^2y+2x^y2+3x^2y b,1/5xy+4/3xy^-2/5xy^+1/3xy c,3/4x^3y^-2/5xy^+2/5x^3y^+3/5x^3y^2 d,(-4/9xy^).(3/2xy^3)
giúp em nhanh với ạ làm ơn :(
a: \(=\left(4xy^2+2xy^2\right)+\left(3x^2y-3x^2y\right)=6xy^2\)
b: \(=xy\left(\dfrac{1}{5}+\dfrac{1}{3}\right)+xy^2\left(\dfrac{4}{3}-\dfrac{2}{5}\right)=\dfrac{8}{15}xy+\dfrac{14}{15}xy^2\)
d: \(=\dfrac{-4}{9}\cdot\dfrac{3}{2}\cdot xy^2\cdot xy^3=-\dfrac{2}{3}x^2y^5\)
thực hiện phép tính
a)(5x-3)(5x+3); b) (2x^2)-3x(4x^2-5x+6); c) 16x^3y^4:4x^2y^2
a: \(\left(5x-3\right)\left(5x+3\right)=25x^2-9\)
b: \(=2x^2-12x^3+15x^2-18x=-12x^3+17x^2-18x\)
c: \(\dfrac{16x^3y^4}{4x^2y^2}=4xy^2\)
3x^4 + 3x^2y^2 + 6x^3y - 27x^2
x^4 + x^3 - x^2 + x
2x^5 - 6x^4 - 2a^2x^3 - 6ax^3
x^5 + x^4 + x^3 + x^2 + x + 1
x^3 - 1 + 5x^2 - 5 + 3x - 3
1/4.(a + 1)^2 - 4/9.(a - 2)^2
12a^2b^2 - 3.(a^2b^2)^2
4x^2y^2 - (x^2 + y^2 - a^2)^2
(a + b + c)^2 + (a + b - c)^2 - 4c^2
x^3 - 1 + 5x^2 - 5 + 3x - 3
Chia đa thức cho đơn thức
a, (8x^4 - 4x^3 +x^2) : 2x^2
b, 2x^4 - x^3 + 3x^2) : (-1/3x^2)
c, (-18x^3y^5 + 12x^2y^2 - 6xy^3) : 6xy
d,(3/4x^3y^6 + 6/5x^4y^5 - 9/10x^5y) : (-3/5x^3y)
giúp mìn với ạ
\(a.\left(8x^4-4x^3+x^2\right):2x^2=4x^2-2x+\frac{1}{2}\)
\(b.\left(2x^4-x^3+3x^2\right):\left(-\frac{1}{3x^2}\right)=-6x^6+3x^5-9x^4\)
\(c.\left(-18x^3y^5+12x^2y^2-6xy^3\right):6xy=-3x^2y^4+2xy-y^2\)
\(d.\left(\frac{3}{4x^3y^6}+\frac{6}{5x^4y^5}-\frac{9}{10x^5y}\right):-\frac{3}{5x^3y}=-\frac{5}{4y^5}-\frac{2}{xy^4}-\frac{3}{2x^2}\)
a)(-6x^3y^4+4x^4y^3):2x^3y^3. b)(5x^4y^2-x^3y^2):x^3y^2. c)(27x^3y^5+9x^2y^4-6x^3y^3):(-3x^2y^3)
a: \(\dfrac{-6x^3y^4+4x^4y^3}{2x^3y^3}\)
\(=\dfrac{-6x^3y^4}{2x^3y^3}+\dfrac{4x^4y^3}{2x^3y^3}\)
\(=-3y+2x\)
b: \(\dfrac{5x^4y^2-x^3y^2}{x^3y^2}=\dfrac{5x^4y^2}{x^3y^2}-\dfrac{x^3y^2}{x^3y^2}\)
\(=5x-1\)
c: \(\dfrac{27x^3y^5+9x^2y^4-6x^3y^3}{-3x^2y^3}\)
\(=-\dfrac{27x^3y^5}{3x^2y^3}-\dfrac{9x^2y^4}{3x^2y^3}+\dfrac{6x^3y^3}{3x^2y^3}\)
\(=-9xy^2-3y+2x\)
a) \(\dfrac{-6x^3y^4+4x^4y^3}{2x^3y^3}\)
\(=\dfrac{2x^3y^3\cdot\left(-3y+2x\right)}{2x^3y^3}\)
\(=-3y+2x\)
\(=2x-3y\)
b) \(\dfrac{5x^4y^2-x^3y^2}{x^3y^2}\)
\(=\dfrac{5x\cdot x^3y^2-x^3y^2\cdot1}{x^3y^2}\)
\(=\dfrac{x^3y^2\cdot\left(5x-1\right)}{x^3y^2}\)
\(=5x-1\)
c) \(\dfrac{27x^3y^5+9x^2y^4-6x^3y^3}{-3x^2y^3}\)
\(=\dfrac{-3x^2y^3\cdot-9xy^2+-3x^2y^3\cdot-3y+-3x^2y^3\cdot2x}{-3x^2y^3}\)
\(=\dfrac{-3x^2y^3\cdot\left(-9xy^2-3y+2x\right)}{-3x^2y^3}\)
\(=-9xy^2-3x+2x\)
Bài 1:Tìm x,y biết
a. 3x = 2y và 2x + y = 3
b. x/3 = 3y/4 và 3x - y = 4
c.4x = 5y và x + 2y = 3
d.3x =2y và 3x- y =1
e.2x=1y và 4x+y=6
f.x/3=3y/2 và x+6y=5
g.2x/5=y/6 và 5x+y=3
\(\hept{\begin{cases}3x=2y\\2x+y=3\end{cases}\Leftrightarrow\hept{\begin{cases}y=\frac{3}{2}.x\\2x+\frac{3}{2}.x=3\end{cases}\Leftrightarrow}\hept{\begin{cases}y=\frac{3}{2}.x\\\frac{7}{2}.x=3\end{cases}\Leftrightarrow}\hept{\begin{cases}x=\frac{6}{7}\\y=\frac{9}{7}\end{cases}}}\)
\(\hept{\begin{cases}\frac{x}{3}=\frac{3y}{4}\\3x-y=4\end{cases}\Leftrightarrow\hept{\begin{cases}4x=9y\\3x-y=4\end{cases}\Leftrightarrow}\hept{\begin{cases}x=\frac{9y}{4}\\\frac{3.9}{4}y-y=4\end{cases}\Leftrightarrow}\hept{\begin{cases}x=\frac{9}{4}.y\\\frac{23}{4}.y=4\end{cases}\Leftrightarrow}\hept{\begin{cases}x=\frac{9}{4}.y\\y=\frac{16}{23}\end{cases}\Leftrightarrow}\hept{\begin{cases}x=\frac{36}{23}\\y=\frac{16}{23}\end{cases}}}\)
Các phần sau làm tương tự nhé
Thu gọn biểu thức a)x^2-4x(3x-4)+7x-5 b)7x(x^2-5)-3x^2y(xy-6y^2) c)(5x+4)(2x-7) d)4x(2x-3)-5x(x-2)+x^2(3-x)
a: Ta có: \(x^2-4x\left(3x-4\right)+7x-5\)
\(=x^2-12x^2+16x+7x-5\)
\(=-11x^2+23x-5\)
b: Ta có: \(7x\left(x^2-5\right)-3x^2y\left(xy-6y^2\right)\)
\(=7x^3-35x-3x^3y^2+18x^2y^3\)
c: Ta có: \(\left(5x+4\right)\left(2x-7\right)\)
\(=10x^2-35x+8x-28\)
\(=10x^2-27x-28\)
Thực hiện phép chia:
a. (-2x^5+3x^2-4x^3):2x^2
b .(x^3-2x^2y+3xy^2):(-1/2x)
c. (3x^2y^2+6x^2y^3-12xy^2):3xy
d. (4x^3-3x^2y+5xy^2):0,5x
e. (18x^3y^5-9x^2y^2+6xy^2):3xy^2
f. (x^4+2x^2y^2+y^4):(x^2+y^2)
sau bạn đăng tách ra cho mn cùng giúp nhé
a, \(\left(-2x^5+3x^2-4x^3\right):2x^2=-x^3+\frac{3}{2}-2x\)
b, \(\left(x^3-2x^2y+3xy^2\right):\left(-\frac{1}{2}x\right)=-\frac{x^2}{2}+xy-\frac{3y^2}{2}\)
c, \(\left(3x^2y^2+6x^3y^3-12xy^2\right):3xy=xy+2x^2y^2-4y\)
d, \(\left(4x^3-3x^2y+5xy^2\right):\frac{1}{2}x=2x^2-\frac{3xy}{2}+\frac{5y^2}{2}\)
e, \(\left(18x^3y^5-9x^2y^2+6xy^2\right):3xy^2=6x^2y^3-3x+2\)
f, \(\left(x^4+2x^2y^2+y^4\right):\left(x^2+y^2\right)=\left(x^2+y^2\right)^2:\left(x^2+y^2\right)=x^2+y^2\)