2:

a: 27(x-45)=0

=>x-45=0

=>x=45

b: (x-47)-115=0

=>x-47=115

=>x=162

d: x-105:21=15

=>x-5=15

=>x=20

1:

a: =35*(34+86)+65*(75+45)

=120*35+120*65

=120*100=12000

b: \(=39\left(53+47\right)-21\left(53+47\right)\)

=18*100=1800

Vì 27<x<31 nên x={28,29,30}

27<x<31.

=> x=28;29;30

Vậy : x=28;29;30.

#Hoc tot.

x = 28,29,30

a) (x - 12). 105 = 0

    x-12= 0 : 105

    x - 12 = 0

   x = 0+ 12

   x = 12

b) (47.(27 - x) = 94

    27-x =94 : 47

    27 - x = 2

    x = 27 - 2

    x = 25

c) 2x + 69 .2 = 69.5

   2x = 69.5 - 69.2

   2x = 69 . (5 - 2)

   2x = 69.3

   2x = 207

   x = 207 : 2

   x = 103,5

a) x : 13 = 41

x=41.13

x=533
b) 4x : 17 = 0

⇒4x=0

⇒x=0
c) 8(x - 3) = 0

⇒x-3=0

x=0+3

x=3

a) 533

b)0

c) 3

a. x : 13 = 41

<=> x = 41 . 13

<=> x = 533

b. 4x : 17 = 0

<=> 4x = 0

<=> x = 0

c. 8(x - 3) = 0

<=> 8x - 24 = 0

<=> 8x = 24

<=> x = 3

\(48⋮x.và.72⋮x\\48=3.2^4;72=3^2.2^3\\ \Rightarrow ƯCLN\left(48;72\right)=2^3.3=24\\ Vậy:x\inƯ\left(24\right)=\left\{1;2;3;4;6;8;12;24\right\}\\ ---\\ 105⋮x;147⋮x.và.126⋮x\\ 105=3.5.7\\ 147=3.7^2\\ 126=2.3^2.7\\ \RightarrowƯCLN\left(105;147;126\right)=3.7=21\\ Vậy:x\inƯ\left(21\right)=\left\{1;3;7;21\right\}\)

\(c,70⋮x;84⋮x\\ 70=2.5.7;84=2^2.3.7\\ \RightarrowƯCLN\left(70;84\right)=2.7=14\\ Ư\left(14\right)=\left\{1;2;7;14\right\}\\ Mà:x>8\Rightarrow x=14\\ ----\\ d,80⋮x;60⋮x;40⋮x\\ 80=2^4.5;60=2^2.3.5;40=2^3.5\\ \RightarrowƯCLN\left(40;60;80\right)=2^2.5=20\\ Ư\left(20\right)=\left\{1;2;4;5;10;20\right\}\\ Mà:x< 10\Rightarrow x\in\left\{1;2;4;5\right\}\)

a, x : 13 = 41

x = 41 x 13

x = 533

 Vậy x = 533

b, 1428 : x = 14

x = 1428 : 14

x = 102

 Vậy x = 102

c, 4x : 17 = 0

4x = 0 x 17

4x = 0

x = 4 : 0

x =0

 Vậy x = 0

a)   Ta có:   \(2x-2\)\(⋮\)\(x-2\)

\(\Leftrightarrow\)\(2\left(x-2\right)+2\)\(⋮\)\(x-2\)

Ta thấy  \(2\left(x-2\right)\)\(⋮\)\(x-2\)

nên   \(2\)\(⋮\)\(x-2\)

hay  \(x-2\)\(\inƯ\left(2\right)=\left\{\pm1;\pm2\right\}\)

Ta lập bảng sau:

  \(x-2\)    \(-2\)      \(-1\)         \(1\)           \(2\)

\(x\)                   \(0\)          \(1\)          \(3\)            \(4\)

Vậy   \(x=\left\{0;1;3;4\right\}\)

0,1,2,3,4 nha nha

a,x/9=5/3 = x=15

b,17/x=85/105 = x = 21

c,6/8=15/x = x =  20

d,x/8=2/3 = x = 6

 e,3/x-7=27/135 =x= 22