tim x
5x+15=29-2x
tình x
5x(x - 7) – 30(x - 7) = 0
(2x – 4)(2x + 4) – x(x + 3) = 3x(x + 5)
a) \(5x\left(x-7\right)-30\cdot\left(x-7\right)=0\)
\(\Rightarrow\left(5x-30\right)\left(x-7\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}5x-30=0\\x-7=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=6\\x=7\end{matrix}\right.\)
b) \(\left(2x-4\right)\left(2x+4\right)-x\left(x+3\right)=3x\left(x+5\right)\)
\(\Rightarrow4x^2-16-x^2-3x=3x^2+15x\)
\(\Rightarrow-16=18x\Rightarrow x=-\dfrac{8}{9}\)
Nghiệm của phương trình 25 x - 2 3 - x 5 x + 2 x - 7 = 0 nằm trong khoảng nào sau đây?
A. (5;10)
B. (0;2)
C. (1;3)
D. (0;1)
5)tim x nguyen
a)5x + 15=29-2x
b)36-l2x+5l = 13
c)(x-2)(2x-6)=0
d)(x-5)(x+2)<0
e)(3-x)(x-1)>0
h)(x^2-3)(x^2-5)<0
Tim x biet : 29 - [ 3 ( x - 2 ) + 15 = 2
29 - [ 3 ( x - 2 ) + 15 ] = 2
[ 3 ( x - 2 ) + 15 ] = 29 - 2
[ 3 ( x - 2 ) + 15 ] = 27
3 ( x - 2 ) = 27 - 15
3 ( x - 2 ) = 12
( x - 2 ) = 12 : 3
( x - 2 ) = 4
x = 4 + 2
x = 6
29 - [ 3 ( x - 2 ) + 15 ] = 2
[ 3 ( x - 2 ) + 15 ] = 29 - 2
[ 3 ( x - 2 ) + 15 ] = 27
3 ( x - 2 ) = 27 - 15
3 ( x - 2 ) = 12
( x - 2 ) = 12 : 3
( x - 2 ) = 4
x = 4 + 2
x = 6
Ủng hộ nhé!
tim x,y biet
(2x - 1) (y - 3) = 29
\(\left(2x-1\right)\left(y-3\right)=29\)
\(\Rightarrow\orbr{\begin{cases}2x-1=29\\y-3=29\end{cases}\Rightarrow\orbr{\begin{cases}2x=30\\y=32\end{cases}\Rightarrow}\orbr{\begin{cases}x=15\\y=32\end{cases}}}\)
\(\Rightarrow\orbr{\begin{cases}x=15\\y=32\end{cases}}\)
\(=>\)\(\orbr{\begin{cases}2x-1=0\\y-3=0\end{cases}}\)\(=>\)\(\orbr{\begin{cases}x=\frac{1}{2}\\y=3\end{cases}}\)
VẬY \(x=\frac{1}{2}\)HOẶC \(y=3\). Hok tốt!!!
Chết mik làm nhầm
tim x biet
11-(15+11)=x-(29-9)
=>11-15 -11 = x - 20
-15+20 =x
5=x
hay x =5
Làm tính trừ các phân thức: x 5 x + 5 - x 5 x - 5
Tim x , : a)(2x-15)^5=(2x-15)^3
5x+15=29-2x
5x+15=29-2x
=>5x-(-2x)=29-15
=>5x+2x=14
=>7x=14=>x=2