Tim U cua 7 ( so nguyen )
Tim U cua 24 ( so nguyen )
\(Ư\left(24\right)\in1;-1;2;-2;3;-3;4;-4;6;-6;8;-8;12;-12;24;-24\)
{-1,-2,-3,-4,-6,-8,-12,-24,1,2,3,4,6,12,24}
cho B=n/n-3(n thuoc Z , n khac 3)
tim tat ca cac gia tri nguyen cua n de B la so nguyen
CHo C= 3n+5.n+7(n thuoc Z, N khac -7)
tim tat ca cac gia tri nguyen cua n de C la so nguyen
a) ta có: \(B=\frac{n}{n-3}=\frac{n-3+3}{n-3}=\frac{n-3}{n-3}+\frac{3}{n-3}\)
Để B là số nguyên
\(\Rightarrow\frac{3}{n-3}\in z\)
\(\Rightarrow3⋮n-3\Rightarrow n-3\inƯ_{\left(3\right)}=\left(3;-3;1;-1\right)\)
nếu n -3 = 3 => n= 6 (TM)
n- 3 = - 3 => n = 0 (TM)
n -3 = 1 => n = 4 (TM)
n -3 = -1 => n = 2 (TM)
KL: \(n\in\left(6;0;4;2\right)\)
b) đề như z pải ko bn!
ta có: \(C=\frac{3n+5}{n+7}=\frac{3n+21-16}{n+7}=\frac{3.\left(n+7\right)-16}{n+7}=\frac{3.\left(n+7\right)}{n+7}-\frac{16}{n+7}=3-\frac{16}{n+7}\)
Để C là số nguyên
\(\Rightarrow\frac{16}{n+7}\in z\)
\(\Rightarrow16⋮n+7\Rightarrow n+7\inƯ_{\left(16\right)}=\left(16;-16;8;-8;4;-4;2;-2;1;-1\right)\)
rùi bn thay giá trị của n +7 vào để tìm n nhé ! ( thay như phần a đó)
tim 3 so nguyen to sao cho tich cua chung gap 7 lan tong cua cua chung.
Tim 3 so nguyen to sao cho tich cua chung gap 7 lan tong cua chung
tim gia tri nguyen cua x de bieu thuc:x^2+7/x+1 cung nhan gia tri la so nguyen
Đề bài có sai không bạn?
de bai sai hay sao ay
Bài lớp 8 hay sao ấy
tim so nguyen to biet rang so do bang tong cua 2 so nguyen to va bang hieu cua 2 so nguyen to
tim so nguyen to P sao cho P vua la tong cua hai so nguyen to vua la hieu cua hai so nguyen to
Tim so nguyen duong nho nhat thoa man:mot phan 2 cua no la so ching phuong,1/3 cua no bang lap phuong cua 1 so nguyen,1/5 cua no bang luy thua bac 5 cua 1 so nguyen.
tim so nguyen to,biet rang so do bang tong cua hai so nguyen to va bang hieu cua hai so nguyen to
Tham khảo :
https://olm.vn/hoi-dap/detail/63924859121.html
~Std well~
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