Câu 1: 

1:A

2:C

Câu 1:

3:D

4:C

Câu 1: 

5:C

6:D

a, \(P=\left(\sqrt{x}-\dfrac{x+2}{\sqrt{x}+1}\right):\left(\dfrac{\sqrt{x}}{\sqrt{x}+1}-\dfrac{\sqrt{x}-4}{1-x}\right)\)

\(=\left(\dfrac{x+\sqrt{x}}{\sqrt{x}+1}-\dfrac{x+2}{\sqrt{x}+1}\right):\left[\dfrac{\sqrt{x}\left(\sqrt{x}-1\right)}{\left(\sqrt{x}+1\right)\left(\sqrt{x}-1\right)}+\dfrac{\sqrt{x}-4}{\left(\sqrt{x}+1\right)\left(\sqrt{x}-1\right)}\right]\)

\(=\dfrac{\sqrt{x}-2}{\sqrt{x}+1}:\dfrac{x-4}{\left(\sqrt{x}+1\right)\left(\sqrt{x}-1\right)}\)

\(=\dfrac{\sqrt{x}-2}{\sqrt{x}+1}.\dfrac{\left(\sqrt{x}+1\right)\left(\sqrt{x}-1\right)}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-2\right)}\)

\(=\dfrac{\sqrt{x}-1}{\sqrt{x}+2}\)

b, \(P< \dfrac{1}{2}\Leftrightarrow\dfrac{\sqrt{x}-1}{\sqrt{x}+2}< \dfrac{1}{2}\)

\(\Leftrightarrow2\sqrt{x}-2< \sqrt{x}+2\)

\(\Leftrightarrow\sqrt{x}< 4\)

\(\Leftrightarrow0\le x< 16\)

Vậy \(0\le x< 16;x\ne1;x\ne4\).

a: ta có: \(P=\left(\sqrt{x}-\dfrac{x+2}{\sqrt{x}+1}\right):\left(\dfrac{\sqrt{x}}{\sqrt{x}+1}+\dfrac{\sqrt{x}-4}{x-1}\right)\)

\(=\dfrac{x+\sqrt{x}-x-2}{\left(\sqrt{x}+1\right)}:\dfrac{x-\sqrt{x}+\sqrt{x}-4}{\left(\sqrt{x}+1\right)\left(\sqrt{x}-1\right)}\)

\(=\dfrac{\sqrt{x}-2}{1}\cdot\dfrac{\sqrt{x}-1}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}\)

\(=\dfrac{\sqrt{x}-1}{\sqrt{x}+2}\)

Rewrite the sentence ,use the word in parentheses:

There are two fridges,a table,four chairs in Thuong's  kitchen. - ............Thuong's kitchen has 2 fridges, a table,  four chairs..............

=> Thuong's kitchen has two fridges , a table , four chairs .

Thuong*s kitchen has two fridges, a table, four chairs.

đúng đó bn ạ

2 nha bn

1 + 1 = 2 nha bạn. Kết bạn với mk đi nha!

1+1=2

mk nha

Bạn viết lại rồi đăng lên lại giùm nhé !

Minhf ko vieets ddc daaus banj owi!

help me!

1 The Temple of Literature is about 10 minutes away from Hoan Kiem Lake

2 There are five courtyards

3 It''s used for street signs of Ha Noi

4 We can find the stone tablets above tortoise backs with thenames of doctors in the third courtyard

EX4 

1 : My town was visited by hundreds of tourists last year

lỗi 

lx

lx

|x+1|-x+2=3-x

|x+1|       = 3 - x - 2 + x 

|x+1|       = 1

\(\Rightarrow\orbr{\begin{cases}x+1=1\\x+1=-1\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=0\\x=-2\end{cases}}\)

Vậy x \(\in\left\{0;-2\right\}\)

Hok tốt !

\(|x+1|-x+2=3-x\)

\(\Leftrightarrow|x+1|-x+2-3+x=0\)

\(\Leftrightarrow|x+1|-1=0\)

\(\Leftrightarrow|x+1|=1\)

\(\Leftrightarrow\orbr{\begin{cases}x+1=1\\x+1=-1\end{cases}\Leftrightarrow\orbr{\begin{cases}x=0\\x=-2\end{cases}}}\)

\(|x+1|-x+2=3-x\)

\(x+1-x+2=3-x\)

\(x-x+x=3-1-2\)

\(x=0\)