Câu 1:

 \(\frac{1}{3}+\frac{3}{35}<\frac{x}{210}<\frac{4}{7}+\frac{3}{5}+\frac{1}{3}\)

\(\Rightarrow\frac{44}{105}<\frac{x}{210}<\frac{158}{105}\)

\(\Rightarrow\frac{88}{210}<\frac{x}{210}<\frac{316}{210}\)

\(\Rightarrow x\in\left\{89;90;91;92;...;310;311;312;313;314;315\right\}\)

Câu 3: 

\(\frac{5}{3}\)\(+\frac{-14}{3}\)\(<\)\(x\)\(<\)\(\frac{8}{5}+\frac{18}{10}\)

\(\Rightarrow\)\(-9\)\(<\)\(x\)\(<\)\(3,4\)

Mà \(x\in Z\)

\(\Rightarrow x\in\left\{-8;-7;-6;-5;...;1;2;3\right\}\)

Câu 4:

\(\frac{1}{2}+\frac{3}{4}+\frac{5}{6}\)\(<\)\(x\)\(<\)\(\frac{3}{2}+\frac{5}{4}+\frac{7}{6}\)

\(\Rightarrow\frac{25}{12}\)\(<\)\(x\)\(<\)\(\frac{47}{12}\)

Nhân cả 3 vế với 12, ta có:

\(\Rightarrow\)\(25<12\)\(x<\)\(47\)

Từ 25 đến 47 có duy nhất số 36 chia hết cho 12

\(\Rightarrow12x=36\)

\(\Rightarrow x=3\)

Bài 1: 

1: =-5/24+16/27+3/4

=-5/24+18/24+16/27

=13/24+16/27

=117/216+128/216=245/216

2: =-1/3+1/3+6/7=6/7

3: \(=\dfrac{1}{2}-\dfrac{7}{12}+\dfrac{1}{2}=1-\dfrac{7}{12}=\dfrac{5}{12}\)

4: \(=-\dfrac{5}{8}+\dfrac{14}{25}-\dfrac{6}{10}=\dfrac{-125+112-120}{200}=\dfrac{-133}{200}\)

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

a) \(\frac{18}{45}-\frac{4}{12}-\frac{6}{9}-\frac{21}{35}=\frac{2}{5}-\frac{1}{3}-\frac{2}{3}-\frac{3}{5}\)

\(=\left(\frac{2}{5}-\frac{3}{5}\right)-\left(\frac{1}{3}+\frac{2}{3}\right)\)

\(=\frac{-1}{3}-1\)

\(=\frac{-4}{3}\)

b) \(\frac{4}{3}+\frac{3}{5}+\frac{7}{3}+\frac{2}{5}+\frac{1}{3}=\left(\frac{4}{3}+\frac{7}{3}+\frac{1}{3}\right)+\left(\frac{3}{5}+\frac{2}{5}\right)\)

\(=4+1=5\)

c) \(\frac{1}{3}.\frac{4}{5}.\frac{1}{3}.\frac{6}{5}=\frac{8}{75}\)

d) \(\frac{6}{7}.\frac{8}{13}+\frac{6}{7}.\frac{9}{13}-\frac{3}{13}.\frac{6}{7}\)

\(=\frac{6}{7}.\left(\frac{8}{13}+\frac{9}{13}-\frac{3}{13}\right)\)

\(=\frac{6}{7}.\frac{14}{13}\)

\(=\frac{12}{13}\)

a: \(\dfrac{1}{3}+\dfrac{3}{35}< \dfrac{x}{210}< \dfrac{4}{7}+\dfrac{3}{5}+\dfrac{1}{2}\)

\(\Leftrightarrow\dfrac{70}{210}+\dfrac{18}{210}< \dfrac{x}{210}< \dfrac{120}{210}+\dfrac{126}{210}+\dfrac{105}{210}\)

\(\Leftrightarrow88< x< 441\)

b: Ta có: \(\dfrac{5}{3}+\dfrac{-14}{3}< x< \dfrac{8}{5}+\dfrac{18}{10}\)

\(\Leftrightarrow\dfrac{5}{3}-\dfrac{14}{3}< x< \dfrac{8}{5}+\dfrac{9}{5}\)

=>-9/3<x<17/5

=>-3<x<3,4

mà x là số nguyên

nên \(x\in\left\{-2;-1;0;1;2;3\right\}\)

a: =>x=3/7+3/5=15/35+21/35=36/35

b: =>x/35=4/5-5/7=28/35-25/35=3/35

=>x=3

c: =>x<3/4+8/4=11/4

=>\(x\in\left\{0;1;2;3\right\}\)

d: =>5/3<x<5/6+24/6=29/6

=>\(x\in\left\{2;3;4\right\}\)

e: =>x<10/12-9/12=1/12

=>x=0

f: =>2/3<x<12/6-5/6=7/6

=>x=1

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