tính giá trị của biểu thức:
(3.4.2^16)^2/11.2^13.4^11-16^9
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(3.4.2^16)^2 . (11.2^13.4^11-16^9)=?
giúp mik cách giải nha
Tính bằng cách hợp lí
(3.4.2^16)/11.2^13.4^11-16^9 các bạn ơn giúp minh với minh đang gấp nhớ ghi cách giải cho minh với nhé
Tính:
A= ( 3.4.2^16)^2 / 11.2^13.4^11-16^9
bạn sai rồi
Oh
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\frac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)
\(=\frac{3^2.2^{36}}{11.2^{35}-2^{36}}\)
\(=\frac{3^2.3^{36}}{2^{35}.\left(11-2\right)}\)
\(=\frac{9.2}{9}=2\)
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\(A=\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(A=\frac{3^2.4^2.2^{32}}{11.2^{13}.4^{11}-16^9}\)
\(A=\frac{3^2.2^4.2^{32}}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)
\(A=\frac{3^2.2^{36}}{11.2^{13}.2^{22}-2^{36}}\)
\(A=\frac{3^2.2^{36}}{11.2^{35}-2.2^{35}}\)
\(A=\frac{3^2.2^{36}}{\left(11-2\right).2^{35}}\)
\(A=\frac{3^2.2}{9}=\frac{18}{9}=2\)
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Tính :
A=(3.4.2^16)^2 / 11.2^13.4^11-16^9
\(A=\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\frac{3^2.4^2.2^{32}}{11.2^{13}.4^{11}-16^9}\)
\(=\frac{3^2.\left(2^2\right)^2.2^{32}}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)
\(=\frac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)
\(=\frac{3^2.2^{36}}{11.2^{35}-2^{36}}\)
\(=\frac{3^2.2^{36}}{2^{35}.\left(11-2\right)}\)
\(=\frac{9.2}{2}=2\)
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Tính giá trị của biểu thức:
\(\frac{\left(3.4.2^{16}\right)^{^2}}{11.2^{13}.4^{11}-16^9}\)
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\frac{3^2.4^2.2^{32}}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)
\(=\frac{3^2.\left(2^2\right)^2.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)
\(=\frac{3^2.2^4.2^{32}}{11.2^{35}-2^{36}}\)
\(=\frac{3^2.2^{36}}{2^{35}.\left(11-2\right)}\)
\(=\frac{3^2.2^{36}}{2^{35}.9}=2\)
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(3.4.2^16)^2/11.2^13.4^11-16^9
\(\dfrac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\dfrac{3^2.\left(2^2\right)^2.\left(2^{16}\right)^2}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)
\(=\dfrac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)
\(=\dfrac{3^2.2^{36}}{11.2^{35}-2.2^{35}}\)
\(=\dfrac{3^2.2^{36}}{2^{35}.\left(11-2\right)}\)
\(=\dfrac{3^2.2^{36}}{2^{35}.9}\)
\(=\dfrac{3^2.2^{36}}{2^{35}.3^2}\)
\(=2\)
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(3.4.2^16)^2/11.2^13.4^11−16^9=3^2.(2^2)^2.(2^16)^2/11.2^13.(2^2)^11−(2^4)^9=3^2.2^4.2^32/11.2^13.2^22−2^36=3^2.2^36/11.2^35−2.2^35=3^2.2^36/2^35.(11−2)=3^2.2^36/2^35.9=3^2.2^36/2^35.3^2=2
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các bạn giúp mik với : (3.4.2^16)^2/11.2^13.4^11-16^9
thank mấy bạn nhak
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)\(=\frac{3^2.4^2.2^{32}}{11.2^{12}.2^{22}-2^{36}}\)\(=\frac{3^2.2^4.2^{32}}{11.2^{34}-2^{34}.2^2}\)\(=\frac{3^2.2^{34}.2^2}{2^{34}.\left(11-2^2\right)}\)\(=\frac{2^{34}.36}{2^{34}.7}=\frac{36}{7}\)
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(3.4.2^16)^2/11.2^13.4^11-16^9
(3.4.2^16)^2/11.2^13.4^11-16^9
=3^2.4^2.(2^16)^2/11.2^13.(2^2)^11-(2^4)^9
=3^2.(2^2)^2.2^32/11.2^13.2^12-2^36
=3^2.2^4.2^32/11.2^13.2^12-2^36
=3^2.2^32+4/11.2^13+12-2^36
=3^2.2^36/11.2^35-2^36
=3^2.2^35.2/11.2^35-2^35.2
=3^2.2^35.2/2^35.(11-2)
=3^2.2^35.2/2^35.9
=3^2.2/9
=9.2/9
=2
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(3.4.2^16)^2/11.2^13.4^11-16^9
goi y nhe ket qua bang 2
mau mau lay k nao
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