a: =>1/3:x=3/5-2/3=9/15-10/15=-1/15

=>x=-1/3:1/15=5

b: \(\Leftrightarrow x\cdot\dfrac{2}{3}-3=\dfrac{2}{5}\cdot\left(-10\right)=-4\)

=>x*2/3=-1

=>x=-3/2

c: =>2x+1=4 hoặc 2x+1=-4

=>x=3/2 hoặc x=-5/2

h: =>x-3=4

=>x=7

g: =>2x-1=3

=>2x=4

=>x=2

f: \(\Leftrightarrow x\cdot\left(\dfrac{3}{2}-\dfrac{7}{3}\right)=\dfrac{3}{2}-\dfrac{2}{3}\)

=>x*-5/6=5/6

=>x=-1

d: =>|2x-1|=3

=>2x-1=3 hoặc 2x-1=-3

=>x=-1 hoặc x=2

\(\Leftrightarrow2x+1=4\\ \Leftrightarrow x=\dfrac{3}{2}\)

a: x=15

c: \(\Leftrightarrow2x+1=3\)

hay x=1

a) \(\Rightarrow x=2021-2006=15\)

b) \(\Rightarrow2x-2016=64\Rightarrow2x=2016+64=2080\Rightarrow x=1040\)

c) \(\Rightarrow\left(2x+1\right)^3=81:3=27\Rightarrow2x+1=3\)

\(\Rightarrow2x=3-1=2\Rightarrow x=1\)

`a) x= 15`

`b) 2x-2016=16\(\times\)4`

`⇔ 2x-2016=64`

`⇔ 2x= 2080`

`⇔ x= 1040`

`c) 3(2x+1)^3 =81`

`⇔ (2x+1)^3 =27`

`⇔ (2x+1)^3 =3^3`

`⇔ 2x+1=3`

`⇔ x= 1`

3^2x+1=81 : 3=27

3^2x+1=3³

2x+1=3

2x=3-1

2x=2

x=2:2

x=1

vay x=1

k nha

ai giúp mik i

\(\frac{81}{3^{2x}+1}=3\)

=> 3.(3^2x + 1) = 81

=> 3^2x+1  = 27

=> 3^2x+1 = 3³

=> 2x + 1 = 3

=> 2x  = 2

=> x = 1

Đúng 100%

3^2x+1=27=3^3

2x+1=3

2x=2

x=1

Vậy x = 1

a, => 3^2x = 3^4

=>2x=4

=>x=2

b,=>2x+3x-3=17

=>5x-3=17

=>5x=17+3=20

=>x=4

c,=>x+15=(2x+3).2 = 4x+6

=>4x+6-(x+15)=0

=>4x+6-x-15=0

=>3x-9=0

=>3x=9

=>x=3

k mk nha

a,x=2

b,

a) 3^2x = 81

     3^2x = 3^4

     2x     = 4

       x      = 4:2

       x = 2

b) 2x + 3 . (x - 1) = 17

     2x + 3x - 3.1 = 17

     (2+3)x - 3 = 17

     5x              = 17 + 3

     5x              = 20

       x              = 20:5

       x              = 4

c) (x + 15) : 2 = 2x + 3

(x+15).1/2 = 2x + 3

(1/2)x + (1/2).15 = 2x + 3

(1/2)x + 15/2 = 2x + 3

(1/2)x - 2x = 3 - (15/2)

(1/2 - 2)x = -9/2

(-3/2)x = -9/2

x = (-9/2):(-3/2)

x = 3