ăn gian vì mày lấy câu hỏi ở violympic tao biết rồi

(25%:0.45+50%x50)x(0.15%-0.75x0.2%)=0

= 0 x 0,001125

= 0

A=2019

Các câu sai: a và d.

Sửa:

a) 50 + 50 x 8 = 50 + 400 = 450

d) 300 – 100 : 5 = 300 – 20 = 280

\(=25\%+25\%\times38+25\%\times50+25\%\times11\)

\(=25\%\times\left(1+38+50+11\right)=25\%\times100=25\)

\(\dfrac{25}{100}+\dfrac{1}{4}\times38+25\%\times50+0,25\times11\)

\(0,25+0,25\times38+0,25\times50+0,25\times11+1\)

\(0,25\times\left(38+50+11+1\right)\)

\(0,25\times100\)

\(25\)

a) Ta có: \(B=\dfrac{x^2}{5x+25}+\dfrac{2\left(x+5\right)}{x}+\dfrac{50+5x}{x\left(x+5\right)}\)

\(=\dfrac{x^2}{5\left(x+5\right)}+\dfrac{2\left(x+5\right)}{x}+\dfrac{50+5x}{x\left(x+5\right)}\)

\(=\dfrac{x^3}{5x\left(x+5\right)}+\dfrac{10\left(x+5\right)^2}{5x\left(x+5\right)}+\dfrac{250+25x}{5x\left(x+5\right)}\)

\(=\dfrac{x^3+10x^2+100x+250+250+25x}{5x\left(x+5\right)}\)

\(=\dfrac{x^3+10x^2+125x+500}{5x\left(x+5\right)}\)

\(=\dfrac{x^3+5x^2+5x^2+25x+100x+500}{5x\left(x+5\right)}\)

\(=\dfrac{x^2\left(x+5\right)+5x\left(x+5\right)+100\left(x+5\right)}{5x\left(x+5\right)}\)

\(=\dfrac{\left(x+5\right)\left(x^2+5x+100\right)}{5x\left(x+5\right)}\)

\(=\dfrac{x^2+5x+100}{5x}\)

b) Thay x=-2 vào biểu thức \(B=\dfrac{x^2+5x+100}{5x}\), ta được:

\(B=\dfrac{\left(-2\right)^2+5\cdot\left(-2\right)+100}{-5\cdot2}=\dfrac{4+100-10}{-10}=\dfrac{94}{-10}=-\dfrac{94}{10}=\dfrac{-47}{5}\)

Vậy: Khi x=-2 thì \(B=-\dfrac{47}{5}\)