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Chỗ 1/3/4 í

Sửa lại nhé

Lời giải:

a.

$x:27=-2:3,6=\frac{-5}{9}$

$x=27.\frac{-5}{9}=-15$

b.

$\frac{2x+1}{-27}=\frac{-3}{2x+1}$

$\Rightarrow (2x+1)^2=(-27)(-3)=81=9^2=(-9)^2$

$\Rightarrow 2x+1=9$ hoặc $2x+1=-9$

$\Rightarrow x=4$ hoặc $x=-5$

$-\dfrac{3}{x-2} = \dfrac45$

$4(x-2) = (-3).5$

$4x - 8 = -15$

$x = -\dfrac74$

\(\dfrac{-3}{x-2}=\dfrac{4}{5}\\ =>\left(x-2\right)\cdot4=-3\cdot5\\ =>\left(x-2\right)\cdot4=-15\\ =>x-2=-15:4\\ =>x-2=-3,75\\ =>x=-3,75+2\\ =>x=-1,75\)

x=7/2

x=7/2

\(=\frac{7}{2}\)

ủng hộ nha

P/s : Vì bạn lớp 7 nên mình giải chi tiết nha!

Có \(\frac{x-1}{x+2}=\frac{x-2}{x+3}\Leftrightarrow\left(x-1\right)\left(x+3\right)=\left(x+2\right)\left(x-2\right)\)

\(\Leftrightarrow x\left(x+3\right)-1\left(x+3\right)=x\left(x-2\right)+2\left(x-2\right)\)

\(\Leftrightarrow x^2+3x-x-3=x^2-2x+2x-4\)

\(\Leftrightarrow x^2+\left(3x-x\right)-3=x^2+\left(2x-2x\right)-4\)

\(\Leftrightarrow x^2+2x-3=x^2-4\Leftrightarrow x^2-x^2+2x=3-4=-1\)

\(=\left(x^2-x^2\right)+2x=-1\Leftrightarrow2x=1\Leftrightarrow x=1\div2=\frac{1}{2}\)

\(\frac{x-1}{x+2}=\frac{x-2}{x+3}\) đkxđ \(x\ne-2;-3\)

\(\Leftrightarrow\left(x+2\right)\left(x-2\right)=\left(x-1\right)\left(x+3\right)\)

\(\Leftrightarrow x^2-4=x^2+2x-3\)

\(\Leftrightarrow x^2-x^2+2x=-3+4\)

\(\Leftrightarrow2x=1\)

\(\Leftrightarrow x=\frac{1}{2}\)

\(\frac{x-1}{x-2}=\frac{x+3}{x+4}\)

\(\Rightarrow\left(x-1\right)\left(x+4\right)=\left(x-2\right)\left(x+3\right)\)

\(\Leftrightarrow x^2+4x-x-4=x^2+3x-2x-6\)

\(\Leftrightarrow x^2+4x-x-4-x^2-3x+2x+6=0\)

\(\Leftrightarrow2x+2=0\)

\(\Leftrightarrow2x=-2\)

\(\Leftrightarrow x=-1\)VẬY X=-1 LÀ NGHIỆM CỦA PHƯƠNG TRÌNH \(\frac{x-1}{x-2}=\frac{x+3}{x+4}\)

Ta có : \(\frac{x-1}{x-2}=\frac{x+3}{x+4}\)

\(\Rightarrow\left(x-1\right)\left(x+4\right)=\left(x-2\right)\left(x+3\right)\)

\(\Rightarrow x^2+4x-x-4=x^2+3x-2x-6\)

\(\Rightarrow3x-4=x+6\)

\(\Rightarrow3x-x=-4+6\)

\(\Rightarrow2x=-2\)

\(\Rightarrow x=-1\)

Cứ linh tinh đấy thì sao

X x 4 +119=235

hjhrhre

Gỉai:

a, x=0,5

b,55/6

\(\frac{7}{x-1}=\frac{x+1}{9}\)

\(\Rightarrow\left(x-1\right)\left(x+1\right)=7.9\)

\(\Rightarrow x^2-1=63\)

\(\Rightarrow x^2=64\)

\(\Rightarrow\orbr{\begin{cases}x=8\\x=-8\end{cases}}\)

\(\frac{x-1}{x+2}=\frac{x-2}{x+3}\)

\(\Rightarrow\left(x-1\right)\left(x+3\right)=\left(x+2\right)\left(x-2\right)\)

\(\Rightarrow x^2+2x-3=x^2-4\)

\(\Rightarrow2x-3=4\)

\(\Rightarrow2x=7\)

\(\Rightarrow x=\frac{7}{2}\)