làm tính nhân
a) 5x2.(3x2 - 7x + 2)
b) (2x2-3x).(5x2-5x +1)
Bài 1: Làm tính nhân
a. 3x2 (5x2 - 4x +3)
b. – 5xy(3x2y – 5xy +y2 )
c. (5x2 - 4x)(x -3)
d. (x – 3y)(3x2 + y2 +5xy)
Bài 2: Rút gọn các biểu thức sau.
a.(x-3)(x + 7) – (x +5)(x -1)
b. (x + 8)2 – 2(x +8)(x -2) + (x -2)2
c. x2 (x – 4)(x + 4) – (x2 + 1)(x2 - 1)
d. (x+1)(x2 – x + 1) – (x – 1)(x2 +x +1)
Bài 1:
\(a,=15x^4-12x^3+9x^2\\ b,=-15x^3y^2+25x^2y^2-5xy^3\\ c,=5x^3-15x^2-4x^2+12x=5x^3-19x^2+12x\\ d,=3x^3-9x^2y+xy^2-3y^3+5x^2y-15xy^2=3x^3-3y^3-4x^2y-14xy^2\)
Bài 2:
\(a,=x^2+4x-21-x^2-4x+5=-16\\ b,=x^2+16x+64-2x^2-12x+32+x^2-4x+4=100\\ c,=x^4-16x^2-x^4+1=1-16x^2\\ d,=x^3+1-x^3+1=2\)
Cứu với ạ
Làm tính chia
1) (x3 – 3x2 + x – 3) : (x – 3) 2) (2x4 – 5x2 + x3 – 3 – 3x) : (x2 – 3)
3) (x – y – z)5 : (x – y – z)3 4) (x2 + 2x + x2 – 4) : (x + 2)
5) (2x3 + 5x2 – 2x + 3) : (2x2 – x + 1) | 6) (2x3 – 5x2 + 6x – 15):(2x – 5) |
bài 1 phân tích các đa thức sau thành nhân tử
a) x2 + 4x +3 b) 16x - 5x2 - 3 c) 2x2 + 7x + 5
d) 2x2 + 3x -5 e) x3 - 3x2 + 1 - 3x f ) x2 - 4x - 5
g) (a2 + 1 )2 - 4a2 h) x3 - 3x2 - 4x + 12 i) x4 + x3 + x + 1
k) x4 - x3 - x2 + 1 l ) (2x + 1 )2 - ( x - 1 )
\(a,=\left(x+1\right)\left(x+3\right)\\ b,=-5x^2+15x+x-3=\left(x-3\right)\left(1-5x\right)\\ c,=2x^2+2x+5x+5=\left(2x+5\right)\left(x+1\right)\\ d,=2x^2-2x+5x-5=\left(x-1\right)\left(2x+5\right)\\ e,=x^3+x^2-4x^2-4x+x+1=\left(x+1\right)\left(x^2-4x+1\right)\\ f,=x^2+x-5x-5=\left(x+1\right)\left(x-5\right)\)
Bài 1. Làm tính nhân :
a) 3x2(5x2- 4x +3)
b) – 5xy(3x2y – 5xy +y2)
c) (5x2- 4x)(x -3)
d) (x – 3y)(3x2 + y2 +5xy)
\(a,=15x^4-12x^3+9x^2\\ b,=-15x^3y^2+25x^2y^2-5xy^3\\ c,=5x^3-19x^2+12x\\ d,=3x^3+xy^2+5x^2y-9x^2y-3y^3-15xy^2\\ =3x^3-3y^3-14xy^2-4x^2y\)
giúp mình bt này với ạ:a,x2-7x+13=0,b:-5x2+5x-1,25=0,C:x2-\2x-1=0,d:2x2+3x+1=0
a: x^2-7x+13=0
Δ=(-7)^2-4*1*13=49-52=-3<0
=>PTVN
b: -5x^2+5x-1.25=0
=>4x^2-4x+1=0
=>(2x-1)^2=0
=>2x-1=0
=>x=1/2
d: 2x^2+3x+1=0
=>(x+1)(2x+1)=0
=>x=-1 hoặc x=-1/2
GTNN:
A= x2+2x+5
B= x2_x+1
C= 5x2+5x+1
D= 3x2+4x+2
E= 1/2x2+x_1
F= 1/9x2+3x+2
\(A=x^2+2x+5=\left(x^2+2x+1\right)+4=\left(x+1\right)^2+4\ge4\)
Kl: MinA = 4
\(B=x^2-x+1=\left(x^2-2\cdot\dfrac{1}{2}x+\dfrac{1}{4}\right)+\dfrac{3}{4}=\left(x-\dfrac{1}{2}\right)^2+\dfrac{3}{4}\ge\dfrac{3}{4}\)
kl:.......
\(C=5x^2+5x+1=5\left(x^2+2\cdot\dfrac{1}{2}x+\dfrac{1}{4}\right)+1-\dfrac{5}{4}=5\left(x+\dfrac{1}{2}\right)^2-\dfrac{1}{4}\ge-\dfrac{1}{4}\)
kl:.......
\(D=3x^2+4x+2=3\left(x^2+2\cdot\dfrac{2}{3}x+\dfrac{4}{9}\right)+2-\dfrac{4}{3}=3\left(x+\dfrac{2}{3}\right)^2+\dfrac{2}{3}\ge\dfrac{2}{3}\)
kl:......
\(E=\dfrac{1}{2}\cdot x^2+x-1=\dfrac{1}{2}\left(x^2+2x+1\right)-1-\dfrac{1}{2}=\dfrac{1}{2}\left(x+1\right)^2+\dfrac{3}{2}\ge\dfrac{3}{2}\)
kl:............
\(F=\dfrac{1}{9}x^2+3x+2=\dfrac{1}{3}\left(x^2+2\cdot\dfrac{1}{2}x+\dfrac{1}{4}\right)+2-\dfrac{1}{12}=\dfrac{1}{3}\left(x+\dfrac{1}{2}\right)^2+\dfrac{23}{12}\ge\dfrac{23}{12}\)
kl:..........
Giải các phương trình sau:
a) 3 x + 1 − 2 x + 2 = 4 x + 5 x 2 + 3 x + 2 ;
b) 2 x 2 + x + 6 x 3 − 8 + 2 2 − x = 3 x 2 + 2 x + 4 .
(1) 5x2 (3x2 - 7x + 2); (2) (x + 3)(x2 + 3x - 5)