Phần a bạn tự giải nhé, so ez mà.

b,

\(\left|6-x\right|\cdot\left(-8\right)=-16\\ \Leftrightarrow\left|6-x\right|=2\\ \Leftrightarrow\left[{}\begin{matrix}6-x=2\left(x\le6\right)\\6-x=-2\left(x>6\right)\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=4\left(t/m\right)\\x=8\left(t/m\right)\end{matrix}\right.\)

c, Bạn tự giải, so ez again.

d, Với x>14, hai BT trong dấu GTTĐ luôn dương. Do đó, ta có:

\(\left|2x\right|+\left|x-14\right|=61\\ \Leftrightarrow2x+x-14=61\\ \Leftrightarrow3x=75\\ \Leftrightarrow x=25\left(t/m\right)\)

Chúc bạn học tốt nha

a: =>3x+98=-2-x

=>4x=-100

=>x=-25

c: =>2-3+6x+8x-40=-42

=>14x-41=-42

=>14x=-1

=>x=-1/14

(-250).(-34) + (-25).68

=(-125).(-68) + 25 . (-68)

= 125 . 68 + (-25) . 68

= 68 . [125 + (-25)]

=68 . 100

= 6800

mình chỉ trả lời câu đầu thôi còn câu đó nếu giải đúng thì đánh đúng giùm nha

1) Tính nhanh:

\(\left(-250\right).\left(-34\right)+\left(-25\right).68\)

\(=\left(-125\right).\left(-68\right)+\left(-25\right).68\)

\(=125.68+\left(-25\right).68\)

\(=68.\left[125+\left(-25\right)\right]\)

\(=68.100\)

\(=6800\)

\(a,\Rightarrow12x-91=101\\ \Rightarrow12x=192\\ \Rightarrow x=16\\ b,\Rightarrow x:23+45=133\\ \Rightarrow x:23=88\\ \Rightarrow x=\dfrac{88}{23}\\ c,\Rightarrow\left(6x-39\right):7=3\\ \Rightarrow6x-39=21\\ \Rightarrow6x=60\\ \Rightarrow x=10\\ d,\Rightarrow3x-24=\dfrac{148}{73}\\ \Rightarrow3x=\dfrac{1900}{73}\\ \Rightarrow x=\dfrac{1900}{219}\\ e,\Rightarrow\left[{}\begin{matrix}x=0\\x=10\end{matrix}\right.\\ f,\Rightarrow\left[{}\begin{matrix}x=-1\\x=2\end{matrix}\right.\\ d,\left(9-x\right)^3=64=4^3\\ \Rightarrow9-x=4\\ \Rightarrow x=5\\ h,\Rightarrow x=27\\ i,\Rightarrow6x=312\cdot12=624\cdot6\\ \Rightarrow x=624\\ j,\Rightarrow\left(19x+104\right):14=25-42=-17\\ \Rightarrow19x+104=-238\\ \Rightarrow19x=-342\\ \Rightarrow x=-18\)

[ ( 6x - 39 ) : 7 ] . 4 = 12

=> ( 6x - 39 ) : 7 = 12 : 4

=> ( 6x - 39 ) : 7 = 3

=> 6x - 39 = 3.7

=> 6x - 39 = 21

=> 6x = 21+39

=> 6x = 60

=> x = 10.

( x : 3 - 4 ) . 5 = 15

=> x : 3 - 4 = 15 : 5

=> x : 3 - 4 = 3

=> x : 3 = 7

=> x = 7.3

=> x = 21

x - [ 42 + (-28) ] = -8

=> x - 14 = -8

=> x = -8 + 14

=> x = 6.

[ (6x - 39): 7] . 4=12

(6x-39) : 7=12:4

(6x -39) :7=3

(6x-39) =3 . 7

6x-39 =21

6x =21 +39

6x=20

x=10

(x :3 -4) .5 =15

(x : 3 -4) =15:5

x:3-4 =3

x : 3=3+4

x:3 =7

x=7 . 3

x=21

a) Ta có:

2.(3-6x)+8.(x-5)=-42

2.3-2.6x+8x-8.5=-42

6-12x+8x-40=-42

=>-12x+8x=-42+40-6

-12x+8x=-2-6

-12x+8x=-8

x(-12+8)=-8

x(-4)=-8

Mà 2(-4)=-8

Nên x=2

Vậy x=2

câu b) giải tương tự nha

câu a x = 2 

nhé

cảm ơn nhiều

kết bạn với minh không

a) \(\left(x+8\right)^2-2\left(x+8\right)\left(x-2\right)+\left(x-2\right)^2\)

\(=\left[\left(x+8\right)-\left(x-2\right)\right]^2\)

\(=\left(x+8-x+2\right)^2\)

\(=10^2\)

\(=2^2.5^2\)

b)\(x^3-4x^2-12x+27=\left(x^3+27\right)-\left(4x^2+12x\right)\)

\(=\left(x+3\right)\left(x^2-3x+9\right)-4x\left(x+3\right)\)

\(=\left(x+3\right)\left(x^2-3x+9-4x\right)\)

\(=\left(x+3\right)\left(x^2-7x+9\right)\)

c)\(x^3+6x^2+11x+6=x^3+x^2+5x^2+5x+6x+6\)

\(=x^2\left(x+1\right)+5x\left(x+1\right)+6\left(x+1\right)\)

\(=\left(x+1\right)\left(x^2+5x+6\right)\)

\(=\left(x+1\right)\left(x^2+2x+3x+6\right)\)

\(=\left(x+1\right)\left[x\left(x+2\right)+3\left(x+2\right)\right]\)

\(=\left(x+1\right)\left(x+2\right)\left(x+3\right)\)

d)\(x^3+6x^2-13x-42=x^3-3x^2+9x^2-27x+14x-42\)

\(=x^2\left(x-3\right)+9x\left(x-3\right)+14\left(x-3\right)\)

\(=\left(x-3\right)\left(x^2+9x+14\right)\)

\(=\left(x-3\right)\left(x^2+2x+7x+14\right)\)

\(=\left(x-3\right)\left[x\left(x+2\right)+7\left(x+2\right)\right]\)

\(=\left(x-3\right)\left(x+2\right)\left(x+7\right)\)