a) \(180=2^2.3^2.5\)

\(234=2.3^2.13\)

\(UCLN\left(180;234\right)=2.3^2=18\)

\(UC\left(180;234\right)=\left\{1;2;3;6;9;18\right\}\) (các phần tử thuộc N)

c) \(480=2^5.3.5\)

\(600=2^3.3.5^2\)

\(UCLN\left(480;600\right)=2^3.3.5=120\)

\(UC\left(480;600\right)=\left\{1;2;3;4;5;6;8;10;12;15;20;24;30;40;60;120\right\}\) (các phần tử thuộc N)

$UC\left(180;234\right)=\left\{1;2;3;6;9;18\right\}$ 

a) 16=2 mũ4

24=3.2 mũ 2

Suy ra ƯCLN (16,24) =2 mũ 2 =4

a) ƯCLN (16, 24) = 8, ƯC (16, 24) = {1; 2; 4; 8};

b) Ta có 180 = 22 .  32 . 5; 234 = 2 . 32 . 13;

ƯCLN (180, 234) = 2 .  32 = 18, ƯC (180, 234) = {1; 2; 3; 6; 9; 18};

c) Ta có 60 = 22 .  3 . 5; 90 = 2 . 32 . 5; 135 = 33 . 5. Do đó

ƯCLN (60, 90, 135) = 3 . 5 = 15; ƯC (60, 90, 135) = {1; 3; 5; 15}.

b)180 =3 mũ 2 nhân 2 mũ 2 nhân 5

234=13 nhân 3 mũ 2 nhân 2

suy ra ƯCLN(180,234)=3 mũ 2 nhân 2=18

a)UCLN(180;234)=18

=> UC(180,234)={1;2;3;6;9;18}

b)UCLN(60;90;135)=15

=>UC(60;90;135)={1;3;5;15}

a, 16= 2⁴

24= 2³.3

\(\Rightarrow\)ƯCLN (16; 24)= 2³= 8

\(\Rightarrow\)ƯC (16; 24)= Ư (8)= {1;2;4;8}

b, 180= 2².3².55

234= 2.3³.13

\(\Rightarrow\)ƯCLN (180; 234)= 2.3²= 18

\(\Rightarrow\)ƯC (180; 234)= Ư (18)= {1;2;3;6;9;18}

c, 60= 2².3.5

90= 3².2.5

135= 3³.5

\(\Rightarrow\)ƯCLN (60;90;135)= 3.5= 15

​​​\(\Rightarrow\)ƯC (60;90;135)= Ư (15)= {1;3;5;15}​

30 = 2.3.5

234 = 2.3^2.13 

UCLN = 2.3 = 6

nha bạn chúc bạn học tốt nha 

a) Ta có: 16=4^2=2^4

24=3.8=3.2^3

​ƯCLN(16,24)=2^3=8

Ư​C(16,24)=Ư(8)={1,2,4,8}

b) Ta có: 180=2^2.3^2.5

243=2.3^2.13

60=2^2.3.5

90=2.3^2.5

135=3^3.5

​ƯCLN(234,180,60,90,135)=3

Ư​C(234,180,60,90,135)=Ư(3)={1,3}

a) ƯCLN là 8             b) ƯCLN là 3                                                                

ngu thế! Dễ thế mà ko biết làm!

a) ƯCLN (16, 24) = 8, ƯC (16, 24) = {1; 2; 4; 8};

b) Ta có 180 = 2² . 3² . 5; 234 = 2 . 3² . 13;

ƯCLN (180, 234) = 2 . 3² = 18, ƯC (180, 234) = {1; 2; 3; 6; 9; 18};

c) Ta có 60 = 2² . 3 . 5; 90 = 2 . 3² . 5; 135 = 3³ . 5. Do đó

ƯCLN (60, 90, 135) = 3 . 5 = 15; ƯC (60, 90, 135) = {1; 3; 5; 15}.

a) ƯCLN (16, 24) = 8, ƯC (16, 24) = {1; 2; 4; 8};

b) Ta có 180 = 2² . 3² . 5; 234 = 2 . 3² . 13;

ƯCLN (180, 234) = 2 . 3² = 18, ƯC (180, 234) = {1; 2; 3; 6; 9; 18};

c) Ta có 60 = 2² . 3 . 5; 90 = 2 . 3² . 5; 135 = 3³ . 5. Do đó

ƯCLN (60, 90, 135) = 3 . 5 = 15; ƯC (60, 90, 135) = {1; 3; 5; 15}.

1

ta có

180=2².3².5

234=2.3².13

vậy UCLN(180;234)=2.3²=18

2

ta có

60=2².3.5

90=2.3².5

135=3³.5

vậy UCLN(60;90;135)=3.5=15

3

ta có

16=2⁴

80=2⁴.5

176=2⁴.11

vậy UCLN(16;80;176)=2⁴=16

4

ta có

18=2.3²

30=2.3.5

77=7.11

vậy UCLN(18;30;77)=1

18

15

16

1

a)

Ta có:

\(24=2^3.3\)

\(30=2.3.5\)

\(\RightarrowƯCLN\left(24;30\right)=2.3=6\)

\(\RightarrowƯC\left(24;30\right)=Ư\left(6\right)=\left\{1;2;3;6\right\}\)

b)

Ta có:

\(42=2.3.7\)

\(98=2.7^2\)

\(\RightarrowƯCLN\left(42;98\right)=2.7=14\)

\(\RightarrowƯC\left(42;98\right)=Ư\left(14\right)=\left\{1;2;7;14\right\}\)

c)

Ta có:

\(180=2^2.3^2.5\)

\(234=2.3^2.13\)
\(\RightarrowƯCLN\left(180;234\right)=2.3^2=18\)

\(\RightarrowƯC\left(180;234\right)=Ư\left(18\right)=\left\{1;2;3;6;9;18\right\}\)

a. ƯCLN(24;30) = 6

ƯC(24, 30) = {1; 2; 3; 6}

b. UCLN( 42 ; 98)= 14

ƯC(42;98) = \(\left\{1;2;7;14\right\}\)

c.UCLN( 180 ; 234 ) = 18 

ƯC(180;234) = \(\left\{1;2;;6;9;18\right\}\)