19/29

ta có 191919/292929= 19/29 nên phân số 191919/292929 rút gọn đc thành 19/29

t

\(\frac{2929-101}{2.1919+404}\)

\(=\frac{101.\left(29-1\right)}{101\left(2.19+4\right)}\)

\(=\frac{28}{38+4}\)

\(=\frac{28}{42}\)

\(=\frac{2}{3}\)

Ta có : 

\(\frac{2929-101}{2.1919+404}\)

\(=\frac{29.101-101}{2.19.101+4.101}=\frac{101\left(29-1\right)}{101\left(2.19+4\right)}=\frac{28}{38+4}=\frac{28}{42}=\frac{2}{3}\)

Ủng hộ mk nha !!! ^_^

dễ ma bạn

\(\frac{2929-101}{2.1919+404}=\frac{29.101-101}{2.19.101+101.4}=\frac{101.\left(29-1\right)}{101.\left(2.19+4\right)}=\frac{28}{42}=\frac{2}{3}\)

\(\frac{2}{3}\)

a) \(\frac{171717}{292929}=\frac{171717:10101}{292929:10101}=\frac{17}{29}\)

b) \(\frac{3344}{1212}=\frac{3344:4}{1212:4}=\frac{836}{303}\)

c) \(\frac{20192019}{20172017}=\frac{20192019:10001}{20172017:10001}=\frac{2019}{2017}\)

a)  17/29(chia cho 10101) 

B) 836/303( chia 4) 

C) 2019/2017(chia 10001) 

a) \(\frac{171717}{292929}=\frac{17}{29}\)

b) \(\frac{3344}{1212}=\frac{836}{303}\)

c) \(\frac{20192019}{20172017}=\frac{2019}{2017}\)

2929-101

___________

2.1919+404

   2929-101*1

=_____________

   2.1919+101*4

  2929-1*1

=____________ 

   2.1919+1*4

  2929-1

=__________

  2.1919+4

  2928

=_____

  6.1919

\(\dfrac{15}{27}=\dfrac{5}{9};\dfrac{35}{55}=\dfrac{7}{11};\dfrac{101}{909}=\dfrac{1}{9}\)

15/ 27 rút gọn thành 5/9

35/55 rút gọn thành 7/11

101/909 rút gọn thành 1/9

- Các phân số còn lại đều tối giản.

3/5 , 5/9 , 9/20 , 7/11 , 17/27 , 1/9

\(\frac{13.\left(2929-101\right)}{2.1919+404}=\frac{13\left(101.29-101\right)}{2.101.19+101.4}=\frac{13.101\left(29-1\right)}{2.101\left(19+2\right)}=\frac{13.28}{2.21}=\frac{13.2}{3}=\frac{26}{3}\)

\(\frac{26}{3}\)