x-3/-9 = -4/x-3

(x-3)^2=-9.-4=36

=>TH1 x-3= 6

   TH2  x-3 = -6

=> TH1: X= 9

     TH2: X=-3

=>(x-3)^2=36

=>x-3=6 hoặc x-3=-6

=>x=-3; x=9

đề bài là gì vậy

\(\dfrac{x-2014}{4}+\dfrac{x-2015}{3}=\dfrac{x-13}{2005}+\dfrac{x-14}{2004}\)

<=>\(\left(\dfrac{x-2014}{4}-1\right)+\left(\dfrac{x-2015}{3}-1\right)=\left(\dfrac{x-13}{2005}-1\right)+\left(\dfrac{x-14}{2004}-1\right)\)

<=>\(\dfrac{x-2018}{4}+\dfrac{x-2018}{3}=\dfrac{x-2018}{2005}+\dfrac{x-2018}{2004}\)

<=>\(\left(x-2018\right).\left[\dfrac{1}{4}+\dfrac{1}{3}-\dfrac{1}{2005}-\dfrac{1}{2004}\right]=0\)

<=>  \(x-2018=0\)

=>x=2018

Vậy S= {2018}

Chúc bạn học tốt!
#Yuii

thank

\(PT\Leftrightarrow\left(\frac{x-3}{2014}-1\right)+\left(\frac{x-2}{2015}-1\right)=\left(\frac{x-1}{1008}-2\right)+\left(\frac{x}{2017}-1\right)\)

\(\Leftrightarrow\frac{x-2017}{2014}+\frac{x-2017}{2015}=\frac{x-2017}{1008}+\frac{x-2017}{2017}\)

\(\Leftrightarrow\frac{x-2017}{2014}+\frac{x-2017}{2015}-\frac{x-2017}{1008}-\frac{x-2017}{2017}=0\)

\(\Leftrightarrow\left(x-2017\right)\left(\frac{1}{2014}+\frac{1}{2015}-\frac{1}{1008}-\frac{1}{2017}\right)=0\)

\(\Rightarrow x=2017\)