a)  \(6^2:4\times3+2\times5^2\)

\(=36:4\times3+2\times25\)

\(=9\times3+50\)

\(=27+50\)

\(=77\)

b)   \(125+70+375+230\)

\(=\left(125+375\right)+\left(70+230\right)\)

\(=500+300\)

\(=800\)

c)   \(150:\left[25\times\left(18-4^2\right)\right]\)

\(=150:\left[25\times\left(18-16\right)\right]\)

\(=150:\left[25\times2\right]\)

\(=150:50\)

\(=3\)

Cảm ơn bạn nhiều

alo 

 

 

Bài 2: Tính nhanh

 

a) 29 + 132 + 237 + 868 + 3

 = 29+(132+858)+(237+3)

=29+990+240

=1259

 

29+132+237+868+3

29+(132+868)+(237+3)

29+1000+240

29+(1000+240)

29+1240

1269

bài 2 :

a) 29 + 132 + 237 + 868 + 3

= 29 +(132 + 868)+(237 + 3)

= 29 + 1000 + 240

=1269

b) 35 . 34 + 35 . 86 + 65 . 75 + 65 . 5
= 35 .(34 + 86)+ 65 .(75 + 5)

= 35 . 120 + 65 . 80

= 4200 + 5200

= 9400

c) 3 . 25 . 8 + 4 . 37 . 6 + 2 . 38 .12

khum bít làm hehe

d) 12 . 53 + 53 . 172 - 53 . 84

= 53 . (12 + 172 - 84)

= 53 . 100

= 5300

Bài 3:

a) 4 . 52 - 18 : 32 hình như câu này sai đề

b) 32 . 22 - 32 . 19

= 32 . (22 - 19)

= 32 . 3

= 96

 c) 24 . 5 - [131- (13 - 4)^2]   = 24 . 5 - [131 - 9^2]   = 24. 5 - [131 - 81]   = 24 . 5 - 50   = 120 - 50   = 70   d) 5871: [928 – ( 247 - 82) . 5] + 21750   = 5871 : [928 - 165 . 5] + 21750 = 5871 : [928 - 825] + 21750 = 5871 : 103 + 21750 = 57 + 21750  = 21807

Lời giải:
$A=(1+2-3-4)+(5+6-7-8)+(9+10-11-12)+....+(297+298-299-300)+301+302-303$

$=(-4)+(-4)+(-4)+....+(-4)+300$

Số lần xuất hiện của $-4$ là:

$[(300-1):1+1]:4=75$

$A=(-4),75+300=0$

\(\dfrac{16^3.3^{10}+120.6^9}{4^6.3^{12}+6^{11}}=\dfrac{\left(2^4\right)^3.3^{10}+3.5.2^3.\left(2.3\right)^9}{\left(2^2\right)^6.3^{12}+\left(2.3\right)^{11}}\)

\(=\dfrac{2^{12}.3^{10}+3.5.2^3.2^9.3^9}{2^{12}.3^{12}+2^{11}.3^{11}}=\dfrac{2^{12}.3^{10}+5.2^{12}.3^{10}}{2^{12}.3^{12}+2^{11}.3^{11}}\)

\(=\dfrac{2^{12}.3^{10}\left(1+5\right)}{2^{11}.3^{11}.\left(2.3+1\right)}\)\(=\dfrac{2^{12}.3^{10}.6}{2^{11}.3^{11}.7}=\dfrac{2.2}{7}=\dfrac{4}{7}\)