Bài 1: Tính

a) Ta có: \(\left(-25\right)\cdot68+\left(-34\right)\cdot\left(-250\right)\)

\(=-25\cdot68+\left(-340\right)\cdot\left(-25\right)\)

\(=-25\cdot\left(68-340\right)\)

\(=-25\cdot\left(-272\right)\)

\(=6800\)

b) Ta có: \(1999+\left(-2000\right)+2001+\left(-2002\right)\)

\(=1999-2000+2001-2002\)

\(=-1-1=-2\)

c) Ta có: \(515+\left[72+\left(-515\right)+\left(-32\right)\right]\)

\(=515+72-515-32\)

\(=40\)

d) Ta có: \(\left(2736-75\right)-2736+175\)

\(=2736-75-2736+175\)

\(=100\)

e) Ta có: \(-2020-\left(157-2020\right)-\left(-257\right)\)

\(=-2020-157+2020+257\)

\(=100\)

Bài 2: Tìm x

a) Ta có: \(x-\left|-2\right|=\left|-18\right|\)

\(\Leftrightarrow x-2=18\)

hay x=20

Vậy: x=20

b) Ta có: \(2x-\left|+14\right|=\left|-14\right|\)

\(\Leftrightarrow2x-14=14\)

\(\Leftrightarrow2x=28\)

hay x=14

Vậy: x=14

c) Ta có: \(\left|x+4\right|+5=20-\left(-12-7\right)\)

\(\Leftrightarrow\left|x+4\right|+5=20+12+7\)

\(\Leftrightarrow\left|x+4\right|=39-5=34\)

\(\Leftrightarrow\left[{}\begin{matrix}x+4=34\\x+4=-34\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=30\\x=-38\end{matrix}\right.\)

Vậy: x∈{30;-38}

d) Ta có: \(15-\left|2-x\right|=\left(-2\right)^2\)

\(\Leftrightarrow15-\left|2-x\right|=4\)

\(\Leftrightarrow\left|2-x\right|=11\)

\(\Leftrightarrow\left[{}\begin{matrix}2-x=11\\2-x=-11\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-9\\x=13\end{matrix}\right.\)

Vậy: x∈{-9;13}

e) Ta có: \(\left|15-x\right|+\left|-25\right|=\left|-55\right|\)

\(\Leftrightarrow\left|15-x\right|+25=55\)

\(\Leftrightarrow\left|15-x\right|=30\)

\(\Leftrightarrow\left[{}\begin{matrix}15-x=30\\15-x=-30\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-15\\x=45\end{matrix}\right.\)

Vậy: x∈{-15;45}

g) Ta có: \(\left|17-\left(-4\right)\right|+\left|-24-\left(-5\right)\right|=\left|-x+3\right|\)

\(\Leftrightarrow\left|17+4\right|+\left|-24+5\right|=\left|3-x\right|\)

\(\Leftrightarrow\left|3-x\right|=40\)

\(\Leftrightarrow\left[{}\begin{matrix}3-x=40\\3-x=-40\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-37\\x=43\end{matrix}\right.\)

Vậy: x∈{-37;43}

Câu 1:

a)\(1999+\left(-2000\right)+2001+\left(-2002\right)=1999-2000+2001-2002=-2\)

b)\(49-\left(-54\right)-23=49+54-23=80\)

c)\(\left(-25\right).68+\left(-34\right).\left(-250\right)=-1700+8500=6800\)

Câu 2:

a)x+7=3

\(\Rightarrow x=4\) Vậy x=4

b)\(\left|x\right|=7\Rightarrow x=\left\{\pm7\right\}\)mà x<0 nên x=-7 thì thỏa mãn đề bài

c) hình như thiếu điều kiện

1. Tính:

a) 1999 + ( - 2000 ) + 2001 + ( - 2002 )

= ( 1999 + 2001 ) + [ ( -2000 ) + ( -2002 ) ]

= 4000 + ( -4002 )

= -2

b) 49 - ( - 54 ) - 23

= 49 + 54 - 23

= ( 49 - 23 ) + 54

= 26 + 54

= 80

c) ( - 25 ) . 68 + ( -34 ) . ( - 250 )

= 1700 + 8500

= 6800

d) Tính tổng các giá trị x thuộc Z, biết: -3 < | x | < 4

=> | x | = 0, 1, 2; 3

=> | x | thuộc { ( - 3 ) + ( - 2 ) + ( -1) + 0 + 1 + 2 + 3 = 0

2. Tìm x thuộc Z

a) x + 7 = 3

=> x = 3 - 7

=> x = -4

b) | x | = 7 và x < 0

=> x = -7; 7

Mà x < 0

=> x = -7

c) | x | > x

=> | x | > x <=> x thuộc Z trừ

Bài 1. Tính hợp lý ( nếu có thể ) :

a) ( 509 - 42 ) - ( 509 + 158 )

= 509 - 42 - 509 - 158

=(509 - 509) - ( 42+ 158)

= 0 - 200

= -200

b) - ( 510 - 427 ) - 473 + 510

= -510 +427 -473 +510

= (510-510) + (427-473)

= 0 + (-46)

=-46

c) 1995 - (-2021 + 1994) - 1

= 1995 +2021 -1994 -1

=( 1995 -1994) + (2021-1)

= 1+2020

= 2021

d) 2020 - [ - 1079 -(-1179 + 3020 )]

= 2020 - [ -1079 +1179-3020]

= 2020 +1079 -1179 +3020

=(2020+3020) + (1079 - 1179)

= 5040 +(-100)

=4940

e) 12+(-47).12-6.(-12)

= 12.1 + (-47) .12 -(-6).12

= 12.1 -47 .12 +6 .12

= 12. (1-47+6)

=12.(-40)

=-480

g) 32.(132-247)-132.(32-247)

=32.132 -32.247 - (132.32 - 132.247)

= 32.132 -32.247 - 132.32 + 132.247

= ( 32.132 - 132.32) + ( 132.247 - 32.247)

= 0 + 247.(132-32)

= 247.100

= 24700

i) (-25) .68+(-34).(-250)

= ( -25) . ( -2) . ( -34) + ( -34) . ( -250)

= 50 . (-34) + ( -34) . (-250)

= (-34) . [ 50 + ( - 250) ]

= ( - 34 ) . ( -200)

= 6800

a) (2736-75)-2736                      

= 2736-75-2736

=(2736-2736)-75

=0-75

=-75

b)(-2002)-(57-2002)

=2002-57-2002

=(2002-2002)-57

=0-57

=-57

a) -75

b) -57

a)  (2736-75)-2736

= (2736-2736)-75

=0-75=-75

b) (-2002)-(57-2002)

=(-2002)-57+2002

=((-2002)+2002)-57

=0-57=-57

a, (2736-75)-2736

=2736-75-2736

=(2736-2736)-75

=0-75

=-75

b, (-2002)-(57-2002)

=[(-2002)-(-2002)]-57

=0-57

=-57

ai k mk rui mk k lai

a) (2736 - 75) - 2736

= 2736 - 75 - 2736

= (2736 - 2736) - 75

= 0 - 75

= -75

b) (-2002) - (57 - 2002)

= -2002 - 57 + 2002

= (-2002 + 2002) - 57

= 0 - 57

= -57

a)(2736-2736)-72

=0-72

=-72

b)(-2002)-(57-2002)

=(-2002+2002)-57

=0-57

=-57

đăng nhỏ câu hỏi ra bạn ơi, dài quá

a)(2736-75)-2736=(2736-3736) - 75

=0-75

=-75                        

b)(-2002)-(57-2002)=(-2002-2002)-57

=-4004-57

=-3947