a) \(3x-2=2x-3\)

\(\Leftrightarrow x+1=0\)

\(\Leftrightarrow x=-1\)

b) \(3-4y+24+6y=y+27+3y\)

\(\Leftrightarrow-2y=0\Leftrightarrow y=0\)

c) \(7-2x=22-3x\)

\(\Leftrightarrow x-15=0\)

\(\Leftrightarrow x=15\)

d) \(8x-3=5x+12\)

\(\Leftrightarrow3x-15=0\Leftrightarrow x=5\)

e) \(x-12+4x=25+2x-1\)

\(\Leftrightarrow3x-36=0\)

\(\Leftrightarrow x=12\)

f) \(x+2x+3x-19=3x+5\)

\(\Leftrightarrow3x-24=0\)

\(\Leftrightarrow x=8\)

a) \(PT\Leftrightarrow3x-2x=2-3\Leftrightarrow x=-1\)

Vậy: \(S=\left\{-1\right\}\)

b) \(PT\Leftrightarrow-2x+3x=-7+22\Leftrightarrow x=15\)

Vậy: \(S=\left\{15\right\}\)

c) \(PT\Leftrightarrow8x-5x=3+12\Leftrightarrow3x=15\Leftrightarrow x=5\)

Vậy: \(S=\left\{5\right\}\)

d) \(PT\Leftrightarrow x+4x-2x=12+25-1\Leftrightarrow3x=36\Leftrightarrow x=12\)

Vậy: \(S=\left\{12\right\}\)

e) \(PT\Leftrightarrow x+2x+3x-3x=19+5\Leftrightarrow3x=24\Leftrightarrow x=8\)

Vậy: \(S=\left\{8\right\}\)

a)3x-2=2x-3

=>x=-1

b)7-2x=22-3x

=>x=15

c)8x-3=5x+12

=>3x=15

=>x=5

d)x-12+4x=25+2x-1

=>3x=12

=>x=4

e)x+2x+3x-19=3x+5

=>3x=24

=>x=8

a)3x-2=2x-3

=>x=-1

b)7-2x=22-3x

=>x=15

c)8x-3=5x+12

=>3x=15

=>x=5

d)x-12+4x=25+2x-1

=>3x=36

=>x=12

e)x+2x+3x-19=3x+5

=>3x=24

=>x=8

a) 3x-2=2x-3

3x=2x-1

Bớt mỗi vế 2x

x=-1

b)3-4y+24+6y=y+27+3y

3-4y+6y=y+3+3y

3-4y+3y=y+3

<=> y=0

c.7-2x=22-3x

2x=15-3x

15=x

d.8x-3=5x+12

3x-3=12

3x=15

x=5

câu e hình như bạn thiếu đề

f)x+2x+3x-19=3x+5

6x-19=3x+5

3x-19=5

3x=24

<=>x=8

g)11=8x-3=5x-3+x

11=8x-3

11=6x-3

<=> x không tồn tại

h)4-2x+15=9x+4x-2x

4-2x+15=11x

<=> nghiệm trên có số thập phân vô hạn tuần hoàn nhé

T

Ngập mặt ~ 

Mình làm 1;2 câu thôi. Các câu sau bạn làm tương tự nhé.

a/ 3x - 2 = 2x - 3

<=> 3x - 2 - 2x + 3 = 0

<=> x + 1               = 0

<=> x                    = -1

b/ 3 - 4y + 24 + 6y = y + 27 + 3y

<=> 3 - 4y + 24 + 6y - y - 27 - 3y = 0

<=> -2y                                        = 0

<=>   y                                         = 0

mỏi mồm cũng không làm được hết

chắc bạn đưa bài mày nên cũng mỏi tay lắm

mà cũng chả ai giải hết cho đâu 

cùng lắm thì các bạn chỉ giải mấy câu dễ như a,b,c

đăng làm gì cho mất thời gian

a)X= 3 b)X= 5 c)X= 12

d)X= 8 e)X= 7 f)X= ?

a) 7 + 2x = 22 – 3x⇔ 2x + 3x = 22 – 7⇔ 5x = 15⇔ x = 3

b) 8x – 3 = 5x + 12⇔ 8x – 5x = 12 + 3⇔ 3x = 15⇔ x = 5

c) x – 12 + 4x = 25 + 2x -1⇔x + 4x – 2x = 25 -1 + 12⇔ 3x = 36⇔ x = 12

d) x + 2x + 3x- 19 = 3x + 5⇔ x + 2x + 3x – 3x = 19 + 5⇔ 3x = 24⇔ x = 8

e) 7 – (2x = 4) = -(x+4)⇔ 7 – 2x – 4 = -x – 4 -2x + x = 4 – 7 – 4⇔ -x = -7⇔ x = 7

f) (x – 1) – (2x – 1) = 9 – x⇔ x – 1 – 2x + 1 = 9 – x⇔ x – 2x + x = 9 + 1 – 1⇔ 0x = 9<-->Phương trình vô nghiệm

Gọi a,b,c,... cho dễ nhé!

a,\(7+2x=22-3x\)

\(\Leftrightarrow2x+3x=22-7\)

\(\Leftrightarrow5x=15\)

\(\Leftrightarrow x=3\)

Vậy...

b,\(x-12+4x=25+2x-1\)

\(\Leftrightarrow x+4x-2x=25-1+12\)

\(\Leftrightarrow3x=36\)

\(\Leftrightarrow x=12\)

Vậy...

c,\(7-\left(2x+4\right)=-\left(x+4\right)\)

\(\Leftrightarrow7-2x-4=-x-4\)

\(\Leftrightarrow-2x+x=-4+4-7\)

\(\Leftrightarrow-x=-7\)

\(\Leftrightarrow x=7\)

Vậy...

d,\(8x-3=5x+12\)

\(\Leftrightarrow8x-5x=12+3\)

\(\Leftrightarrow3x=15\)

\(\Leftrightarrow x=5\)

Vậy...

e,\(x+2x+3x-19=3x+5\)

\(\Leftrightarrow x+2x+3x-3x=5+19\)

\(\Leftrightarrow3x=24\)

\(\Leftrightarrow x=8\)

Vậy...

f,\(\left(x-1\right)-\left(2x-1\right)=9-x\)

\(\Leftrightarrow x-1-2x+1=9-x\)

\(\Leftrightarrow x-2x+x=9-1+1\)

\(\Leftrightarrow0x=9\) (Vô lý)

Vậy...

a, \(7+2x=22-3x\)

\(\Rightarrow7+2x-22+3x=0\)

\(\Rightarrow5x-15=0\)

\(\Rightarrow5x=15\Rightarrow x=3\)

b, \(x-12+4x=25+2x-1\)

\(\Rightarrow3x-12-24-2x=0\)

\(\Rightarrow x-36=0\Rightarrow x=36\)

c, \(7-\left(2x+4\right)=-\left(x+4\right)\)

\(\Rightarrow7-2x-4=-x-4\)

\(\Rightarrow3-2x+x+4=0\)

\(\Rightarrow-x=-7\Rightarrow x=7\)

d, \(8x-3=5x+12\)

\(\Rightarrow8x-3-5x-12=0\)

\(\Rightarrow3x-15=0\)

\(\Rightarrow3x=15\Rightarrow x=5\)

e, \(x+2x+3x-19=3x+5\)

\(\Rightarrow6x-19-3x-5=0\)

\(\Rightarrow3x-24=0\)

\(\Rightarrow3x=24\Rightarrow x=8\)

f, \(\left(x-1\right)-\left(2x-1\right)=9-x\)

\(\Rightarrow x-1-2x+1-9+x=0\)

(hình như câu này bị sai đề rồi, bạn xem lại đề nhé)

Chúc bạn học tốt!

Câu 1:

a) 1 + x = 0

c) 1 - 2t = 0

d) 3y = 0

câu 1 bạn tự làm nha

câu 2:

a) 4x-20=0

<=> 4x =20

<=>x =\(\dfrac{20}{4}\)

<=> x=5

b) 2x+x+12=0

<=>3x+12=0

<=>3x =-12

<=>x =\(\dfrac{-12}{3}\)

<=> x=-4

c) x-5=3-x

<=>x+x=3+5

<=>2x=8

<=>x =\(\dfrac{8}{2}\)

<=>x=4

d) 7-3x=9-x

<=>-3x+x =9-7

<=>-2x=2

<=>x=\(\dfrac{2}{-2}\)

<=>x=-1

a) \(7+2x=22-3x\)

\(\Leftrightarrow5x=15\Leftrightarrow x=3\)

b) \(8x-3=5x+12\)

\(\Leftrightarrow3x=15\Leftrightarrow x=5\)

c) \(x-12+4x=25+2x-1\)

\(\Leftrightarrow3x=36\Leftrightarrow x=12\)

d) \(x+2x+3x-19=3x+5\)

\(\Leftrightarrow3x=24\Leftrightarrow x=8\)

e) \(7-\left(2x+4\right)=-\left(x+4\right)\)

\(\Leftrightarrow x=7\)

f) \(\left(x-1\right)-\left(2x-1\right)=9-x\)

\(\Leftrightarrow0x=9\) ( vô lí )

Copy có khác, ko đọc đc j!!! ʌl

Câu 3:

1)

a) Ta có:

hay x=-1

Vậy: x=-1

b) Ta có:

hay y=0

Vậy: y=0

c) Ta có:

hay x=15

Vậy: x=15

d) Ta có:

Vì 3≠0

nên x-5=0

hay x=5

Vậy: x=5

a) 3x - 2 = 2x - 3

\(\Leftrightarrow\) 3x - 2 - 2x + 3 = 0

\(\Leftrightarrow\) x + 1 = 0

\(\Rightarrow\) x = -1

b) 3 - 4y + 24 + 6y = y + 27 + 3y

\(\Leftrightarrow\) 3 - 4y + 24 + 6y - y - 27 - 3y = 0

\(\Leftrightarrow\) -2y = 0

\(\Rightarrow\) y = 0

c)7 - 2x = 22 - 3x

\(\Leftrightarrow\) 7 - 2x - 22 + 3x = 0

\(\Leftrightarrow\) -15 + x = 0

\(\Rightarrow\) x = 15

d) 8x - 3 = 5x + 12

\(\Leftrightarrow\) 8x - 3 - 5x - 12 = 0

\(\Leftrightarrow\)3x -15 = 0

\(\Leftrightarrow\) 3x = 15

\(\Rightarrow\) x = 5

e) x - 12 + 4x = 25 + 2x - 1

\(\Leftrightarrow\) x - 12 + 4x - 25 - 2x + 1 = 0

\(\Leftrightarrow\) 3x - 36 = 0

\(\Leftrightarrow\) 3x = 36

\(\Rightarrow\) x = 12

f ) x + 2x + 3x - 19 = 3x + 5

\(\Leftrightarrow\) x + 2x + 3x - 19 - 3x - 5 = 0

\(\Leftrightarrow\)3x - 24 = 0

\(\Leftrightarrow\) 3x = 24

\(\Rightarrow\) x = 8

g) 11+ 8x - 3 = 5x - 3 +x

\(\Leftrightarrow\)8x + 8 = 6x - 3

\(\Leftrightarrow\)8x - 6x = -3 - 8

\(\Leftrightarrow\)2x = -11

\(\Rightarrow\)x = \(-\frac{11}{2}\)

h) 4 - 2x +15 = 9x + 4 -2

\(\Leftrightarrow\)19 - 2x = 7x + 4

\(\Leftrightarrow\)-2x - 7x = 4 - 19

\(\Leftrightarrow\)-9x = -15

\(\Rightarrow\)x = \(\frac{15}{9}\) = \(\frac{5}{3}\)

2)

a) \(5-\left(x-6\right)=4\cdot\left(3-2\right)\)

\(\Leftrightarrow5-x+6=12-8\)

\(\Leftrightarrow11-x=4\)

\(\Rightarrow x=7\)

b) \(2x\cdot\left(x+2\right)^2-8x^2=2\cdot\left(x-2\right)\cdot\left(x^2+2x+4\right)\)

\(\Leftrightarrow2x\cdot\left(x^2+4x+4\right)-8x^2=2\cdot\left(x^3-8\right)\)

\(\Leftrightarrow2x^3+8x^2+8x-8x^2-2x^3+16=0\)

\(\Leftrightarrow8x+16=0\)

\(\Rightarrow x=-2\)

c) \(7-\left(2x+4\right)=-\left(x+4\right)\)

\(\Leftrightarrow7-2x-4=-x-4\)

\(\Leftrightarrow-2x+x=-4-3\)

\(\Leftrightarrow-x=-7\)

\(\Rightarrow x=7\)

d) \(\left(x-2\right)^3+\left(3x-1\right)\cdot\left(3x+1\right)=\left(x+1\right)^3\)

\(\Leftrightarrow x^3-6x^2+12x-8+9x^2-1-x^3-3x^2-3x-1=0\)

\(\Leftrightarrow9x-10=0\)

\(\Rightarrow x=\frac{10}{9}\)

e)\(\left(x+1\right)\cdot\left(2x-3\right)=\left(2x-1\right)\cdot\left(x+5\right)\)

\(\Leftrightarrow2x^3-3x+2x-3-2x^2-10x+x+5=0\)

\(\Leftrightarrow2-10x=0\)

\(\Rightarrow x=\frac{2}{10}=\frac{1}{5}\)

f)\(\left(x-1\right)^3-x\cdot\left(x+1\right)^2=5x\cdot\left(2-x\right)-11\cdot\left(x+2\right)\)

\(\Leftrightarrow x^3-3x^2+3x-1-x^3-2x^2-x-10x+5x^2+11x+22=0\)

\(\Leftrightarrow3x+21=0\)

\(\Rightarrow x=-7\)

g)\(\left(x-1\right)-\left(2x-1\right)=9-x\)

\(\Leftrightarrow x-1-2x+1-9+x=0\)

\(\Leftrightarrow-9=0\)

\(\Rightarrow\) Phương trình vô nghiệm

h)\(\left(x-3\right)\cdot\left(x+4\right)-2\cdot\left(3x-2\right)=\left(x-4\right)^2\)

\(\Leftrightarrow x^2+4x-3x-12-6x+4=x^2-8x+16\)

\(\Leftrightarrow x^2-5x-8=x^2-8x+16\)

\(\Leftrightarrow x^2-5x-8-x^2+8x-16=0\)

\(\Leftrightarrow3x-24=0\)

\(\Rightarrow x=8\)

i)\(x\cdot\left(x+3\right)^2-3x=\left(x+2\right)^3+1\)

\(\Leftrightarrow x^3+6x^2+9x-3x=x^3+6x^2+12x+8+1\)

\(\Leftrightarrow x^3+6x^2+6x=x^3+6x^2+12x+9\)

\(\Leftrightarrow x^3+6x^2+6x-x^3-6x^2-12x-9=0\)

\(\Leftrightarrow-6x-9=0\)

\(\Rightarrow x=-\frac{3}{2}\)

j)\(\left(x+1\right)\cdot\left(x^2-x+1\right)-2x=x\cdot\left(x+1\right)\cdot\left(x-1\right)\)

\(\Leftrightarrow\left(x^3+1\right)-2x=x\left(x^2-1\right)\)

\(\Leftrightarrow x^3+1-2x-x^3+x=0\)

\(\Leftrightarrow1-x=0\)

\(\Rightarrow x=1\)