May I have fried chicken, please?

fried

fry

???

Làm vậy r ai hiểu ??

- Các đường thẳng:

AB,AC,AD,BC,BD,CD.

`x/34 . 17/63=5/18`

`=> x/34 = 5/18 : 17/63`

`=> x/34 = 5/18 xx 63/17`

`=> x/34 =  35/34`

`=>x=35`

a: \(M=2\left(x+5\right)^2+5\left(x-2\right)^2-7\left(x+3\right)\left(x-3\right)\)

\(=2\left(x^2+10x+25\right)+5\left(x^2-4x+4\right)-7\left(x^2-9\right)\)

\(=2x^2+20x+50+5x^2-20x+20-7x^2+63\)

\(=113\)

b: \(H=\left(2x-3y\right)^2-\left(3y-2\right)\left(3y+2\right)-\left(1-2x\right)^2+4x\left(3y-1\right)\)

\(=4x^2-12xy+9y^2+12xy-4x-\left(9y^2-4\right)-\left(4x^2-4x+1\right)\)

\(=4x^2+9y^2-4x-9y^2+4-4x^2+4x-1\)

=3

c: \(N=\left(2x+3y\right)^2+\left(3x-2y\right)^2-13\left(x+y\right)\left(x-y\right)-26\left(y+1\right)\left(y-1\right)\)

\(=4x^2+12xy+9y^2+9x^2-12xy+4y^2-13\left(x^2-y^2\right)-26\left(y^2-1\right)\)

\(=13x^2+13y^2-13x^2+13y^2-26y^2+26\)

=26

d: \(K=\left(x^2y-3\right)^2-\left(2x-y\right)^3+xy^2\left(6-x^3\right)+8x^3-6x^2y-y^3\)

\(=x^4y^2-6x^2y+9+6xy^2-x^4y^2+8x^3-6x^2y-y^3-\left(2x-y\right)^3\)

\(=-12x^2y+9-y^3+6xy^2+8x^3-\left(8x^3-12x^2y+6xy^2-y^3\right)\)

\(=\left(8x^3-12x^2y+6xy^2-y^3\right)-\left(8x^3-12x^2y+6xy^2-y^3\right)+9\)

=9

e: \(P=\left(4x+3\right)\left(16x^2-12x+9\right)-\left(-23+64x^3\right)\)

\(=\left(4x\right)^3+3^3+23-64x^3\)

\(=64x^3+27+23-64x^3\)

=50

h: \(Q=\left(x+5y\right)\left(x^2-5xy+25y^2\right)+\left(x-5y\right)\left(x^2+5xy+25y^2\right)-\dfrac{1}{2}\left(4x^3-7\right)\)

\(=x^3+125y^3+x^3-125y^3-2x^3+\dfrac{7}{2}\)

=7/2

=>ac-a^2+bc-ab=ac-bc+a^2-ab

=>-2a^2+2bc=0

=>a^2-bc=0

=>a^2=bc

=>a/b=c/a

=>ĐPCM

Hãy so sánh 4³⁰ và 3.24¹⁰

                       Giải:

Ta có:

430 = 230 ∙ 230 = 230 ∙ (22)15 = 230 ∙ 415 = 230 ∙ 411 ∙ 44 

3 ∙ 2410 = 3 ∙ (3.23)10 = 3 ∙ 310 ∙ 230 = 311 ∙ 230

Mà 411 ∙ 44 > 311 nên 430 > 3 ∙ 2410 .

\(4^{30}=\left(4^3\right)^{10}=64^{10}=\left(\dfrac{8}{3}\right)^{10}.24^{10}\\ Vì:\left(\dfrac{8}{3}\right)^{10}>3\Rightarrow\left(\dfrac{8}{3}\right)^{10}.24^{10}>3.24^{10}\\ \Rightarrow4^{30}>3.24^{10}\)

thanks bn