1/2=114.1/2.114=114/228

1/3=1.76/3.76=76/228

1/38=1.6/38.6=6/228

-1/12=-1.19/19.12=-19/228

\(\frac{-3}{8}=\frac{-9}{24}\)\(;\frac{-7}{12}=\frac{-14}{24};\frac{2}{3}=\frac{16}{24};\frac{5}{6}=\frac{20}{24}\)

Các số xếp thừ bứ đến lớn là: \(\frac{-14}{24};\frac{-9}{24};\frac{16}{24};\frac{20}{24}\)

HT

\(\frac{-9}{24}\); \(\frac{-14}{24}\); \(\frac{16}{24}\); \(\frac{20}{24}\)

=>\(\frac{-14}{24}\); \(\frac{-9}{24}\); \(\frac{16}{24}\); \(\frac{20}{24}\)

=>\(\frac{-7}{12}\); \(\frac{3}{-8}\); \(\frac{2}{3}\); \(\frac{5}{6}\)

k đúng cho mik đc ko

1. a) Ta có BCNN(12, 15) = 60 nên ta lấy mẫu chung của hai phân số là 60. 

Thừa số phụ:

60:12 =5; 60:15=4

Ta được:

\(\frac{5}{{12}} = \frac{{5.5}}{{12.5}} = \frac{{25}}{{60}}\)

\(\frac{7}{{15}} = \frac{{7.4}}{{15.4}} = \frac{{28}}{{60}}\)

 b) Ta có BCNN(7, 9, 12) = 252 nên ta lấy mẫu chung của ba phân số là 252. 

Thừa số phụ:

252:7 = 36; 252:9 = 28; 252:12 = 21

Ta được:

\(\frac{2}{7} = \frac{{2.36}}{{7.36}} = \frac{{72}}{{252}}\)

\(\frac{4}{9} = \frac{{4.28}}{{9.28}} = \frac{{112}}{{252}}\)

\(\frac{7}{{12}} = \frac{{7.21}}{{12.21}} = \frac{{147}}{{252}}\)

2. a) Ta có BCNN(8, 24) = 24 nên:

\(\frac{3}{8} + \frac{5}{{24}} = \frac{{3.3}}{{8.3}} + \frac{5}{{24}} = \frac{9}{{24}} + \frac{5}{{24}} = \frac{{14}}{{24}} = \frac{7}{{12}}\)

 b) Ta có BCNN(12, 16) = 48 nên:

\(\frac{7}{{16}} - \frac{5}{{12}} = \frac{{7.3}}{{16.3}} - \frac{{5.4}}{{12.4}} = \frac{{21}}{{48}} - \frac{{20}}{{48}} = \frac{1}{{48}}\).

a)

i.Ta có: BCNN(12, 30) = 60

60 : 12 = 5; 60 : 30 = 2. Do đó:

\(\frac{5}{{12}} = \frac{{5.5}}{{12.5}} = \frac{{25}}{{60}}\) và \(\frac{7}{{30}} = \frac{{7.2}}{{30.2}} = \frac{{14}}{{60}}.\)

ii.Ta có: BCNN(2, 5, 8) = 40

40 : 2 = 20; 40 : 5 = 8; 40 : 8 = 5. Do đó:

\(\frac{1}{2} = \frac{{1.20}}{{2.20}} = \frac{{20}}{{40}}\)

\(\frac{3}{5} = \frac{{3.8}}{{5.8}} = \frac{{24}}{{40}}\)

\(\frac{5}{8} = \frac{{5.5}}{{8.5}} = \frac{{25}}{{40}}\).

b)

i.Ta có: BCNN(6, 8) = 24

24 : 6 = 4; 24: 8 = 3. Do đó

\(\begin{array}{l}\frac{1}{6} + \frac{5}{8} = \frac{{1.4}}{{6.4}} + \frac{{5.3}}{{8.3}}\\ = \frac{4}{{24}} + \frac{{15}}{{24}} = \frac{{19}}{{24}}.\end{array}\)

ii. Ta có: BCNN(24, 30) = 120

120: 24 = 5; 120: 30 = 4. Do đó:

\(\begin{array}{l}\frac{{11}}{{24}} - \frac{7}{{30}} = \frac{{11.5}}{{24.5}} - \frac{{7.4}}{{30.4}}\\ = \frac{{55}}{{120}} - \frac{{28}}{{120}} = \frac{{27}}{{120}} = \frac{9}{{40}}\end{array}\)

Ta có 2=2

         3=3

         38=2.19

         12=3.\(2^2\)

\(\Rightarrow BCNN\left(2;3;38;12\right)=2^2.3.19\)=228

\(\frac{1}{2}=\frac{1\cdot114}{2\cdot114}=\frac{114}{228}\)

\(\frac{1}{3}=\frac{1\cdot76}{3\cdot76}=\frac{76}{228}\)

\(\frac{1}{38}=\frac{1\cdot6}{38\cdot6}=\frac{6}{228}\)

\(-\frac{1}{12}=-\frac{1\cdot19}{12\cdot19}=-\frac{19}{228}\)

ta có mẫu số chung : 228

QĐMS các phân số : \(\frac{1}{2}\); \(\frac{1}{3}\);\(\frac{1}{38}\);\(\frac{-1}{12}\)

                          = \(\frac{114}{228}\);\(\frac{76}{228}\);\(\frac{6}{228}\);\(\frac{-19}{228}\)

k cho mình nha! thanks! ^_^

Thank Miyuki Misaki nha !

@#@...

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rzddddddfg

a) Ta có: \(12 = 2^2 . 3; 15 = 3.5\)

\(BCNN(12, 15) = 2^2.3.5 = 60\) nên chọn mẫu chung là 60.

\(\begin{array}{l}\frac{9}{{12}} = \frac{{9.5}}{{12.5}} = \frac{{45}}{{60}}\\\frac{7}{{15}} = \frac{{7.4}}{{15.4}} = \frac{{28}}{{60}}\end{array}\)

b) Ta có: \(10 = 2.5; 4 = 2^2; 14=2.7\)

\(BCNN(10, 4, 14) =2^2.5.7= 140\) nên chọn mẫu chung là 140.

\(\begin{array}{l}\frac{7}{{10}} = \frac{{7.14}}{{10.14}} = \frac{{98}}{{140}}\\\frac{3}{4} = \frac{{3.35}}{{4.35}} = \frac{{105}}{{140}}\\\frac{9}{{14}} = \frac{{9.10}}{{14.10}} = \frac{{90}}{{140}}\end{array}\)

a, \(\frac{5}{6};\frac{11}{12}\)

Giữ nguyên phân số \(\frac{11}{12}\)

Quy đồng: \(\frac{5}{6}=\frac{5\cdot2}{6\cdot2}=\frac{10}{12}\)

b, \(\frac{3}{5};-2\)

Giữ nguyên phân số \(\frac{3}{5}\)

Quy đồng: \(-2=\frac{-2\cdot5}{5}=-\frac{10}{5}\)

c, \(-\frac{1}{4};\frac{3}{8};\frac{7}{12}\)

Quy đồng: \(-\frac{1}{4}=\frac{-1\cdot6}{4\cdot6}=-\frac{6}{24};\frac{3}{8}=\frac{3\cdot3}{8\cdot3}=\frac{9}{24};\frac{7}{12}=\frac{7\cdot2}{12\cdot2}=\frac{14}{24}\)

d, \(-\frac{8}{9};\frac{17}{18};\frac{5}{-6}\)

Giữ nguyên phân số \(\frac{17}{18}\)

Quy đồng: \(-\frac{8}{9}=\frac{-8\cdot2}{9\cdot2}=-\frac{16}{18};\frac{5}{-6}=\frac{5\cdot3}{-6\cdot3}=\frac{15}{-18}=-\frac{15}{18}\)