\(2.\left(5+3.x\right)+x=31\)
ai nhanh mk tick nha
Tìm GTNN của
a/A=\(a^2+5b^2-4ab-2b+5\)
b/B=\(\left(x-y\right)^2+\left(y-3^{ }\right)^2+\left(x-3\right)^2+2021\)
Ai giúp mk vs ạ ai nhanh mk tick nha :3
b: \(B\ge2021\forall x,y\)
Dấu '=' xảy ra khi x=y=3
\(3.x-7+2.\left(5-2.x\right)+5.x=19\)
ai nhanh mk tick nha mk đang cần gấp
\(3x-7+2\left(5-2x\right)+5x=19\)
\(\Leftrightarrow3x-7+10-4x+5x=19\)
\(\Leftrightarrow3x-4x+5x=19-10+7\)
\(\Leftrightarrow4x=16\)
\(\Leftrightarrow x=4\)
\(3.x-7+2.\left(5-2.x\right)+5.x=19\)
ai nhanh mk tick nha
Ta có : \(3x-7+2.\left(5-2x\right)+5x=19\)
\(\Rightarrow3x-7+10-4x+5x=19\)
\(\Rightarrow4x+3=19\)
\(\Rightarrow4x=16\)
\(\Rightarrow x=4\)
Tìm x\(\left(2x-1\right)^2-3.\left(x+2\right)^2=4.\left(x-2\right)-5.\left(x-1\right)^2\)
Ai nhanh mình tick cho mình cảm ơn , mk cần gấp vì chiều nộp rùi nên các bạn giúp mk với nha.
\(\left(2x-1\right)^2-3.\left(x+2\right)^2=4.\left(x-2\right)-5.\left(x-1\right)^2\)
\(\Leftrightarrow4x^2-4x+1-3\left(x^2+4x+4\right)=4x-8-5.\left(x^2-2x+1\right)\)
\(\Leftrightarrow4x^2-4x+1-3x^2-7x-12=4x-8-5x^2+10x-5\)
\(\Leftrightarrow x^2-11x-11=14x-13-5x^2\)
\(\Leftrightarrow6x^2-25x+2=0\)
Tự làm tiếp nha
~~~~~~~~~~~ai đi ngang qua nhớ để lại k ~~~~~~~~~~~~~
~~~~~~~~~~~~ Chúc bạn sớm kiếm được nhiều điểm hỏi đáp ~~~~~~~~~~~~~~~~~~~
~~~~~~~~~~~ Và chúc các bạn trả lời câu hỏi này kiếm được nhiều k hơn ~~~~~~~~~~~~
Giải tới đây pt có 2 ngiệm\(\hept{\begin{cases}x_1=\frac{25+\sqrt{577}}{12}\\x_2=\frac{25-\sqrt{577}}{12}\end{cases}}\)
1 Tìm x
\(\left(90:18\right)^2+x.\left(2^3\right)^{12}-2^2.7\)
\(2^{x.1}+3^3-5^2+2.3\)
Ai nhanh mk tick cho
nhanh nha ko mk :L mất
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1.
\(\left(\frac{5}{x+3}-2\right).4=7-\left(\frac{9}{x+3}+\frac{1}{2}\right).2\)
CÓ 1 BÀI THUI NHA, MONG MN GIẢI NHANH GIÚP MK
AI NHANH MK CHO 1 TICK, MK ĐANG RẤT CẦN ĐẤY
\(\left(\frac{5}{x+3}-2\right).4=7-\left(\frac{9}{x+3}+\frac{1}{2}\right).2\)
\(\Leftrightarrow\frac{20}{x+3}-8=7-\frac{18}{x+3}+1\)
\(\Leftrightarrow\frac{20}{x+3}-8=8-\frac{18}{x+3}\)
\(\Leftrightarrow\frac{20}{x+3}+\frac{18}{x+3}=8+8\)
\(\Leftrightarrow\frac{38}{x+3}=16\)
\(\Leftrightarrow x+3=2,375\)
\(\Leftrightarrow x=-0,625\)
\(\left(\frac{5}{x+3}-2\right).4=7-\left(\frac{9}{x+3}+\frac{1}{2}\right).2\)
\(\Leftrightarrow\frac{20}{x+3}-8=7-\left(\frac{18}{x+3}+1\right)\)
\(\Leftrightarrow\frac{20}{x+3}-8=7-\frac{18}{x+3}-1\)
\(\Leftrightarrow\frac{20}{x+3}+\frac{18}{x+3}=7-1+8\)
\(\Leftrightarrow\frac{38}{x+3}=14\)
\(\Leftrightarrow\left(x+3\right)14=38\)
\(\Leftrightarrow14x+42=38\)
\(\Leftrightarrow14x=-4\Leftrightarrow x=-\frac{4}{14}=-\frac{2}{7}\)
Vậy \(x=-\frac{2}{7}\)
Tìm x sao cho: \(\left(x-1\right)^3=\left(2x+1\right)^3+3\left(x+2\right)\)
Giải hộ mk nha!Thanks!
Ai nhanh mk tick!
\(\left(2x-1\right).\left(3x-2\right)-\left(6x-1\right).\left(x-3\right)=17\)
tìm X
ai nhanh mk tick nha thank
\(\left(2x-1\right)\left(3x-2\right)-\left(6x-1\right)\left(x-3\right)=17\)
\(\Rightarrow\left(6x^2-4x-3x+2\right)-\left(6x^2-18x-x+3\right)=17\)
\(\Rightarrow6x^2-4x-3x+2-6x^2+18x+x-3=17\)
\(\Rightarrow\left(6x^2-6x^2\right)+\left(18x-4x-3x+x\right)-\left(3+2\right)=17\)
\(\Rightarrow12x-1=17\)
\(\Rightarrow12x=18\)
\(\Rightarrow x=\frac{3}{2}\)
6x2 - 4x - 3x + 2 - 6x2 - 18x - x + 3 = 17
=>>> -27x + 5 = 17 =>>> -27x = 12 =>>> x = -4/7
Vậy: x = -4/7
Cho \(x+y+z=0\). CMR: \(10\left(x^7+y^7+z^7\right)=7\left(x^2+y^2+x^2\right)\left(x^5+y^5+z^5\right)\)
GIẢI CHI TIẾT RA NHA! AI NHANH MK TICK! THANKS!