1 sickness - disability

2 opposition

3 pride

4 professional

5 unemployed

6 Poverty

7 deafened

8 

9 photographing

10 education

1 sickness - disability

2 opposition

3 pride

4 professional

5 unemployed

6 Poverty

7 deafened

8

9 photographing

10 education

Cho xin một like đi các dân chơi à.

1. sickness/ disabilities

2. opposition

3. pride

4. professional

5. unemployed

6. poverty

7. deafened

8. severity

9. photography

10. education

\(\dfrac{12x4x72}{36x2x9}=\dfrac{48x72}{72x9}=\dfrac{48}{9}=\dfrac{16}{3}\)

a: \(AO=\dfrac{1}{2}AC\)(O là trung điểm của AC)

nên AO=AD

hay ΔAOD cân tại A

\(11,\\ a,M=\dfrac{1+\sqrt{a}}{\sqrt{a}\left(\sqrt{a}-1\right)}\cdot\dfrac{\left(\sqrt{a}-1\right)^2}{\sqrt{a}+1}=\dfrac{\sqrt{a}-1}{\sqrt{a}}\\ b,M=\dfrac{\sqrt{a}-1}{\sqrt{a}}=1-\dfrac{1}{\sqrt{a}}< 1\left(\dfrac{1}{\sqrt{a}}>0\right)\)

\(9,\\ a,=\left|2-\sqrt{7}\right|=\sqrt{7}-2\\ b,=5\sqrt{3}+4\sqrt{3}-10\sqrt{3}=-\sqrt{3}\\ c,=3-4+2=1\\ d,=6\sqrt{3a}-4\sqrt{3a}=2\sqrt{3a}\\ 10,\)

a, Áp dụng HTL: \(x=\sqrt{9\cdot25}=15\)

b, Áp dụng HTL: \(\left\{{}\begin{matrix}8^2=10x\\y^2=x\left(x+10\right)\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=6,4\\y=\sqrt{6,4\cdot16,4}\approx10,245\end{matrix}\right.\)

Bài 1:

a) \(\left(2x+y\right)^2-\left(y-2x\right)^2=\left(2x+y-y+2x\right)\left(2x+y+y-2x\right)=8xy\)

b) \(\left(x-y\right)^2+2\left(x^2-y^2\right)+\left(x+y\right)^2\\ =x^2-2xy+y^2+2x^2-2y^2+x^2+2xy+y^2\\ =4x^2\)

c) \(\left(x-2y\right)\left(x+2y\right)=x^2-4y^2\)

d) \(\left(y-\dfrac{1}{2}\right)\left(y+\dfrac{1}{2}\right)=y^2-\dfrac{1}{4}\)

Bài 1: 

a: \(\left(2x+y\right)^2-\left(y-2x\right)^2\)

\(=4x^2+4xy+y^2-y^2+4xy-4x^2\)

=8xy

b: Ta có: \(\left(x-y\right)^2+2\left(x^2-y^2\right)+\left(x+y\right)^2\)

\(=\left(x-y+x+y\right)^2\)

\(=\left(2x\right)^2\)

\(=4x^2\)

c: \(\left(x-2y\right)\left(x+2y\right)=x^2-4y^2\)

d: \(\left(y-\dfrac{1}{2}\right)\left(y+\dfrac{1}{2}\right)=y^2-\dfrac{1}{4}\)

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