[ ( 6x - 39 ) : 7 ] . 4 = 12

=> ( 6x - 39 ) : 7 = 12 : 4

=> ( 6x - 39 ) : 7 = 3

=> 6x - 39 = 3.7

=> 6x - 39 = 21

=> 6x = 21+39

=> 6x = 60

=> x = 10.

( x : 3 - 4 ) . 5 = 15

=> x : 3 - 4 = 15 : 5

=> x : 3 - 4 = 3

=> x : 3 = 7

=> x = 7.3

=> x = 21

x - [ 42 + (-28) ] = -8

=> x - 14 = -8

=> x = -8 + 14

=> x = 6.

[ (6x - 39): 7] . 4=12

(6x-39) : 7=12:4

(6x -39) :7=3

(6x-39) =3 . 7

6x-39 =21

6x =21 +39

6x=20

x=10

(x :3 -4) .5 =15

(x : 3 -4) =15:5

x:3-4 =3

x : 3=3+4

x:3 =7

x=7 . 3

x=21

[(6x-39):3]  . 28 = 5628

(6x - 39) : 3 = 201

6x - 39 = 603

6x = 642

x = 107

a) 7.(x - 3) + 4 = 18

7. (x - 3) = 14

x - 3 = 2

x = 5

b) 2x - 13 = 201

2x = 214

x = 107

7×( x-3)=14 

X-3=2

X=5

Từ biểu thức, suy ra:

[(6x-39)÷3]÷28=5628

<=>(2x-13):28=5628

<=>2x-13=158584

<=>2x=157597

<=>x=78798,5

Vậy x=78798,5

[(6x-39)÷3]÷28=5628

=> [(6x-39):3]= 157584

=> 6x-39=472752

=> 6x=472791

=>x=78798,5

Vậy x= 78798,5

[(6x-39)÷3]÷28=5628

[(6x-39)÷3]=5628\(\times\)28

(6x-39)÷3=157584

(6x-39)=157584\(\times\)3

6x-39= 4727252

6x=472752

x= 472752:6

x=78792

1) \(8x^3-12x^2+6x-1=0\)

\(\Leftrightarrow\left(2x\right)^2-3\cdot\left(2x\right)^2\cdot1+3\cdot2x\cdot1^2-1^3=0\)

\(\Leftrightarrow\left(2x-1\right)^3=0\)

\(\Leftrightarrow2x-1=0\)

\(\Leftrightarrow2x=1\)

\(\Leftrightarrow x=\dfrac{1}{2}\)

2) \(x^3-6x^2+12x-8=27\)

\(\Leftrightarrow x^3-3\cdot x^2\cdot2+3\cdot2^2\cdot x-2^3=27\)

\(\Leftrightarrow\left(x-2\right)^3=27\)

\(\Leftrightarrow\left(x-2\right)^3=3^3\)

\(\Leftrightarrow x-2=3\)

\(\Leftrightarrow x=3+2\)

\(\Leftrightarrow x=5\)

3) \(x^2-8x+16=5\left(4-x\right)^3\)

\(\Leftrightarrow\left(x-4\right)^2=5\left(4-x\right)^3\)

\(\Leftrightarrow\left(4-x\right)^2=5\left(4-x\right)^3\)

\(\Leftrightarrow5\left(4-x\right)=1\)

\(\Leftrightarrow4-x=\dfrac{1}{5}\)

\(\Leftrightarrow x=4-\dfrac{1}{5}\)

\(\Leftrightarrow x=\dfrac{19}{5}\)

4) \(\left(2-x\right)^3=6x\left(x-2\right)\)

\(\Leftrightarrow8-12x+6x^2-x^3=6x^2-12x\)

\(\Leftrightarrow-12x+6x^2-6x^2+12x=8-x^3\)

\(\Leftrightarrow8-x^3=0\)

\(\Leftrightarrow x^3=8\)

\(\Leftrightarrow x^3=2^3\)

\(\Leftrightarrow x=2\)

5) \(\left(x+1\right)^3-\left(x-1\right)^3-6\left(x-1\right)^2=-10\)

\(\Leftrightarrow x^3+3x^2+3x+1-x^3+3x^2-3x+1-6\left(x^2-2x+1\right)=-10\)

\(\Leftrightarrow\left(x^3-x^3\right)+\left(3x-3x\right)+\left(3x^2+3x^2\right)+\left(1+1\right)-6x^2+12x-6=-10\)

\(\Leftrightarrow0+0+0+\left(6x^2-6x^2\right)+12x-4=-10\)

\(\Leftrightarrow12x-4=-10\)

\(\Leftrightarrow12x=-10+4\)

\(\Leftrightarrow12x=-6\)

\(\Leftrightarrow x=\dfrac{-6}{12}\)

\(\Leftrightarrow x=-\dfrac{1}{2}\)

6) \(\left(3-x\right)^3-\left(x+3\right)^3=36x^2-54x\)

\(\Leftrightarrow27-27x+9x^2-x^3-x^3-9x^2-27x-27=36x^2-54x\)

\(\Leftrightarrow-54x-2x^3=36x^2-54x\)

\(\Leftrightarrow-2x^3=36x^2\)

\(\Leftrightarrow-2x^3-36x^2=0\)

\(\Leftrightarrow-2x^2\left(x+18\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}-2x^2=0\\x+18=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-18\end{matrix}\right.\)

a) Tìm MTC:

\(\text{2x + 6 = 2(x + 3)}\)

\(\text{x2 – 9 = (x – 3)(x + 3)}\)

\(\text{MTC = 2(x – 3)(x + 3) = 2(x2 – 9)}\)

Nhân tử phụ:

\(\text{2(x – 3)(x + 3) : 2(x + 3) = x – 3}\)

\(\text{2(x – 3)(x + 3) : (x2 – 9) = 2}\)

Qui đồng:

b) Tìm MTC:

a)

720 : (x - 17) = 12

x – 17 = 60

x = 60 + 17

x = 77

b)

(x - 28) : 12 = 8

x – 28 = 8 . 12

x – 28 = 96

x = 124

c)

26 + 8x = 6x + 46

8x – 6x = 46 – 26

2x == 20

x = 10

d)                 

3600 : [(5x + 335) : x] = 50

(5x + 335) : x = 72

5x + 335 = 72x

67x = 335

x = 5

a) Đặt A = 1 + 4 + 7 + ..... + 100

Số số hạng của A là : 

           (100 - 1) : 3 + 1 = 34 

Tổng A có giá trị là  :

           (100 + 1) x 34 : 2 = 1717

Thay A vào đề bài ta có : x + 1717 = 1996

=> x = 1996 - 1717

=> x = 279

b) 786 + (x + 2 + 4 + ......... + 48 + 50) = 2007

Đặt B = 2 + 4 + ......... + 50

Số số hạng của B là : 

                (50 - 2) : 2 + 1 = 25 (số)

Tổng B có giá trị là : 

               (50 + 2) x 25 : 2 = 650 

Thay B vào đề bài ta có : 786 + x + 650 = 2007

=> x + 1436 = 2007

=> x = 571 

Vậy x = 571

2) [ ( 6x - 39) : 3 ] . 28 = 84

( 6x - 39 ) : 3 = 84 : 28

( 6x - 39 ) : 3 = 3

 6x - 39  = 3 . 3 

 6x - 39 = 9

 6x = 9 + 39

 6x = 48

x = 48 : 6

x = 8

3) 20 - [ 7 . (x - 3) + 4 ] = 2

7 . (x - 3) + 4 = 20 - 2

7 . (x - 3) + 4 = 18

7 . (x - 3) = 18 - 4

7 . (x - 3) = 14

x - 3 = 14 : 7

x - 3 = 2

x = 2 + 3

x = 5