( x^2 -4 ) . ( x^2 -10) < 0
pls help
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pls help me
bài 2 : tìm X
X x ( X + 1 ) = 2 + 4 + 6 + 8 + 10 + 20
help me
\(x\)\(\times\)( \(x\) + 1) = 2 + 4 + 6 + 8 + 10 + 20
\(x\) \(\times\)(\(x\) + 1) = 50
\(x\) \(\times\)(\(x+1\)) = 2 \(\times\) 5 \(\times\) 5
Nếu \(x\) là số tự nhiên thì không tồn tại
Nếu \(x\) là số thực thì câu hỏi này không phù hợp lớp 5 em nhá
\(x\left(x+1\right)=2+4+6+8+10+20\\ \Leftrightarrow x^2+x-50=0\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-1-\sqrt{201}}{2}\\x=\dfrac{-1+\sqrt{201}}{2}\end{matrix}\right.\)
help me
-4/7-x=3/5-2x
3/7.x-2/3.x=10/21
\(-\dfrac{4}{7}-x=\dfrac{3}{5}-2x\\ \Rightarrow-x+2x=\dfrac{3}{5}+\dfrac{4}{7}\\ \Rightarrow x=\dfrac{21}{35}+\dfrac{20}{35}\\ \Rightarrow x=\dfrac{41}{35}\)
Vậy `x=41/35`
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\(\dfrac{3}{7}x-\dfrac{2}{3}x=\dfrac{10}{21}\\ \Rightarrow\left(\dfrac{3}{7}-\dfrac{2}{3}\right)x=\dfrac{10}{21}\\ \Rightarrow\left(\dfrac{9}{21}-\dfrac{14}{21}\right)x=\dfrac{10}{21}\\ \Rightarrow\dfrac{-5}{21}x=\dfrac{10}{21}\\ \Rightarrow x=\dfrac{10}{21}:\left(-\dfrac{5}{21}\right)\\ \Rightarrow x=-2\)
Vậy `x=-2`
a)
-4/7 - x = 3/5 - 2x
2x - x = 3/5 + 4/7
x = 41/35
Vậy x = 41/35
b)
3/7.x - 2/3.x = 10/21
x(3/7 - 2/3) = 10/21
x.(-5/21) = 10/21
x = 10/21 : (-5/21) = -2
Vậy x = -2
1)tính 2+(-4)+6+(-8)+....+(-2008)+2009
2)6(x-10)-2(x+6)=8
help me
TÌM X, BIẾT:
a) 3 . ( 1/2 - x ) + 1/3 = 7/6 - x
b) 4 . ( 1/2 - x ) - 5 . ( x - 3/10 ) = 7/4
c) -3/2 . ( 4/5 - 2/3 ) + x = 4 . ( x - 1/2 )
d) 2 . ( 3/2 - x ) - 1/3 = 7x - 1/4
e) 1/5 . ( -3/5 -10 ) + 5x = x - 2/3
f) -3/2 . ( 5 - 1/6 ) + 4 . ( x - 1/2 ) = 1
~ PLEASE HELP ME ~
Nguyễn Trà My
Phần a)
\(3\times\left(\frac{1}{2}-x\right)+\frac{1}{3}=\frac{7}{6}-x\)
\(32-3x+13=76-x\)
\(116-3x=76-x\)
\(116-76=3x-x\)
\(46=2x\)
\(x=46\div2\)
\(x=13\)
a) \(3.\left(\frac{1}{2}-x\right)+\frac{1}{3}=\frac{7}{6}-x\)
\(3.\left(\frac{1}{2}-x\right)+x=\frac{7}{6}-\frac{1}{3}\)
\(\Rightarrow\frac{3}{2}-3x+x=\frac{5}{6}\)
\(-3x+x=\frac{5}{6}-\frac{3}{2}\)
\(2x=-\frac{2}{3}\)
\(x=-\frac{2}{3}:2\)
\(x=-\frac{1}{3}\)
2 và 1/6 x 3 + 3 và 4/5 x 10 x10 x 9 và 1/10 = ?
HELP MEEEEEEEE..................!
GIÚP MIK VỚI
\(2\frac{1}{6}x3+3\frac{4}{5}x10x9\frac{1}{10}\)
\(=1+38x9\frac{1}{10}\)
\(=1+345,8\)
\(346,8\)
Bài 1:
555 - 5 x [ 409 - (2 mũ 3 x 3 - 21) mũ 2 - 310]
Bài 2:
a) 10x +187 = 617 mũ 10 : 617 mũ 9
b) 5 mũ 2 + x = 25 mũ 4
c) (2x + 17) chia hết (x + 4)
help me!
Tìm x, biết:
a) 3/(x+2)(x+5) + 5/(x+5)(x+10) + 7/ (x+10)(x+7) = x/(x+2)(x+17) với x thuộc {-2,-5,-10,-17}
b) 2/(x-1)(x-3 + 5/(x-3)(x-8) + 12/(x-8)(x-20) -1/x-20 =-3/4 với x thuộc {1,3,8,,20}
HELP ME!!!!
a: \(\Leftrightarrow\dfrac{1}{x+2}-\dfrac{1}{x+5}+\dfrac{1}{x+5}-\dfrac{1}{x+10}+\dfrac{1}{x+10}-\dfrac{1}{x+17}=\dfrac{x}{\left(x+2\right)\left(x+17\right)}\)
=>\(\dfrac{x+17-x-2}{\left(x+2\right)\left(x+17\right)}=\dfrac{x}{\left(x+2\right)\left(x+17\right)}\)
=>x=15
b: \(\Leftrightarrow-\dfrac{1}{x-1}+\dfrac{1}{x-3}-\dfrac{1}{x-3}+\dfrac{1}{x-8}-\dfrac{1}{x-8}+\dfrac{1}{x-20}-\dfrac{1}{x-20}=\dfrac{-3}{4}\)
=>1/x-1=3/4
=>x-1=4/3
=>x=7/3
Tìm số nguyên x sao cho:\(\left(x^2-1\right)\left(x^2-4\right)\left(x^2-7\right)\left(x^2-10\right)< 0\)
HELP ME