=11111111....1111(có 99 so1)20000000000.......00000(có 500 số 9)

  có 500 số 0 mới đúng

Xin cảm ơn.!^_^

Bằng:1202339.043

1203792.304

sao ko nhân thêm 0 đi

(1/2 + 3/2 - 5/2) x ( 9/1000 - 8/1000 + 1/2019)

=( 4/2 - 5/2) x ( 1/1000 + 1/2019)

= (-1/2) x ...

=1000*1001/2

=500*1001

=500500

\(1+2+3+4+...+1000=\dfrac{\left[\left(1000-1\right):1+1\right].\left(1000+1\right)}{2}=\dfrac{1000.1001}{2}=500.1001=500500\)

a) \(\left(2y-1\right)^{1000}-\left(3+y\right)^{1000}=0\)

\(\Rightarrow\left(2y-1\right)^{1000}=\left(3+y\right)^{1000}\)

\(\Rightarrow2y-1=3+y\)

\(2y-y=3+1\)

\(y=4\)

b) \(\left(x-\frac{2}{9}\right)^3=\left(\frac{2}{3}\right)^6\)

\(\left(x-\frac{2}{9}\right)^3=\left(\left(\frac{2}{3}\right)^2\right)^3\)

\(\Rightarrow x-\frac{2}{9}=\left(\frac{2}{3}\right)^2\)

\(x-\frac{2}{9}=\frac{4}{9}\)

\(x=\frac{2}{3}\)

c) \(\left(2x-1\right)^6=\left(2x-1\right)^8\)

\(\left(\left(2x-1\right)^3\right)^2=\left(\left(2x-1\right)^4\right)^2\)

\(\Rightarrow\left(2x-1\right)^3=\left(2x-1\right)^4\)

\(8x^3-1=16x^4-1\)

\(16x^4-8x^3=0\)

\(8x^3\left(2x-1\right)=0\)

Nếu \(8x^3=0\) thì \(x^3=0\Rightarrow x=0\)

Nếu \(2x-1=0\)thì \(2x=1\Rightarrow x=\frac{1}{2}\)

Vậy x=0 và x=1/2

= 3629800

  Vì bài rất dài nên tớ chỉ ghi kết quả thôi

363880

1*2*3*4*5*6*7*8*9*10*1+1000=3529800

500500 đó Chi

Tổng bằng

(1000+1)x1000:2=500500

(1000+1)x(1000-1+1):2=500500