\(\frac{x+1}{x+2}=\frac{0,8}{1,2}\)

\(\Rightarrow1,2\left(x+1\right)=0,8\left(x+2\right)\)

\(1,2x+1,2=0,8x+0,16\)

\(1,2x-0,8x=0,16-1,2\)

\(0,4x=-1,04\)

\(x=-2,6\)

\(\frac{1}{4}x+5-\frac{2}{5}x=1-x\)

\(0,85x=-4\)

\(x=-\frac{80}{17}\)

Bài 1:

a) b) c) sẽ có bạn giải cho em thôi vì nó dễ tính tay cũng đc

d) \(\frac{4}{2.5}+\frac{4}{5.8}+...+\frac{4}{23.26}\)

\(=\frac{4}{3}.\left(\frac{3}{2.5}+\frac{3}{5.8}+...+\frac{3}{23.26}\right)\)

\(=\frac{4}{3}.\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+...+\frac{1}{23}-\frac{1}{26}\right)\)

\(=\frac{4}{3}.\left(\frac{1}{2}-\frac{1}{26}\right)\)

\(=\frac{4}{3}.\frac{6}{13}\)

\(=\frac{8}{13}\)

 Bài 2:

a) b) c) 

d)\(|\frac{5}{8}x+\frac{6}{7}|-\frac{4}{7}=\frac{10}{7}\)

\(\Leftrightarrow|\frac{5}{8}x+\frac{6}{7}|=2\)

\(\Leftrightarrow\orbr{\begin{cases}\frac{5}{8}x+\frac{6}{7}=2\\\frac{5}{8}x+\frac{6}{7}=-2\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}\frac{5}{8}x=\frac{8}{7}\\\frac{5}{8}x=\frac{-20}{7}\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{64}{35}\\x=\frac{-32}{7}\end{cases}}}\)

Vậy \(x\in\left\{\frac{64}{35};\frac{-32}{7}\right\}\)

Bài 1 :

a) \(\left(\frac{2}{5}-\frac{5}{8}\right):\frac{11}{30}+\frac{1}{8}\)

\(=\frac{-9}{40}:\frac{11}{30}+\frac{1}{8}\)

\(=\frac{-27}{44}+\frac{1}{8}\)

\(=\frac{-43}{88}\)

Bài 1 :

b) \(\frac{4}{9}+\frac{7}{12}:\frac{3}{8}-\left(\frac{-5}{6}\right)\)

\(=\frac{4}{9}+\frac{14}{9}+\frac{5}{6}\)

\(=\frac{17}{6}\)

\(\frac{3x-7}{5}=\frac{2x-1}{3}\)

\(\Leftrightarrow9x-21=10x-5\)

\(\Leftrightarrow-x=16\Leftrightarrow x=-16\)

\(\frac{4x-7}{12}-x=\frac{3x}{8}\)

\(\Leftrightarrow\frac{4x-7-12x}{12}=\frac{3x}{8}\)

\(\Leftrightarrow\frac{-7-8x}{12}=\frac{3x}{8}\)

\(\Leftrightarrow-56-64x=36x\)

\(\Leftrightarrow-56=100x\Leftrightarrow x=\frac{-14}{25}\)

\(\frac{x-2009}{1234}+\frac{x-2009}{5678}-\frac{x-2009}{197}=0\)

\(\Leftrightarrow\left(x-2019\right)\left(\frac{1}{1234}+\frac{1}{5678}-\frac{1}{197}\right)=0\)

Vì \(\left(\frac{1}{1234}+\frac{1}{5678}-\frac{1}{197}\right)\ne0\)nên x - 2019 = 0

Vậy x = 2019

\(\frac{5x-8}{3}=\frac{1-3x}{2}\)

\(\Leftrightarrow10x-16=3-9x\)

\(\Leftrightarrow19x=19\Leftrightarrow x=1\)

\(\frac{x-5}{6}-\frac{x-9}{4}=\frac{5x-3}{8}+2\)

\(\Rightarrow\frac{4x-20-6x+54}{24}=\frac{5x-3+16}{8}\)

\(\Rightarrow\frac{-2x+34}{24}=\frac{5x+13}{8}\)

\(\Rightarrow-16x-272=120x+312\)

\(\Leftrightarrow-136x=584\Leftrightarrow x=\frac{-73}{17}\)

a) \(\frac{x+\frac{2\left(3-x\right)}{5}}{14}-\frac{5x-4\left(x-1\right)}{24}=\frac{7x+2+\frac{9-3x}{5}}{12}+\frac{2}{3}\)

<=> \(\frac{5x+2\left(3-x\right)}{70}-\frac{5x-4\left(x-1\right)}{24}=\frac{35x+10+9-3x}{60}+\frac{2}{3}\)

<=> \(12\left(5x+6-2x\right)-35\left(5x-4x+4\right)\)

<=> \(14\left(35x+10+9-3x\right)+280.2\) <=> \(12\left(3x+6\right)-35\left(x+4\right)\)

<=> \(14\left(32x+19\right)+560\)

<=> \(36x+72-35x-140=448x+226+560\)

<=> \(-447x=894\)

<=> x = -2

Bài 1:

a) Ta có:

\(3,2\cdot x+\left(-1,2\right)\cdot x+2,7=-4,9\)

\(\Rightarrow\left[3,2+\left(-1,2\right)\right]\cdot x=\left(-4,9\right)-2,7\)

\(\Rightarrow2x=-7,6\)

\(\Rightarrow x=\left(-7,6\right):2\)

\(\Rightarrow x=-3,8\)

Vậy \(x=-3,8\)

b) Ta có:

-5,6.x+2,9.x-3,86=-9,8

=>[(-5,6)+2,9].x=(-9,8)+3,86

=>(-2,7).x=-5,94

=>x=(-5,94):(-2,7)

=>x=2,3

Vậy x=2,2

Dễ mà. ấn máy tính cũng ra

a,3,25+0,9-x=0,97

4,15-x=0,97

x=4,15-0,97

x=3,18

b,4,4-9,2+x=1,2

-4,8+x=1,2

x=1,2-(-4,8)

x=6

c,7/5+x-2/5=4

7/5+x=4+2/5

7/5+x=22/5

x=22/5-7/5

x=15/5

x=3

d,1 3/4+x-7/8=5

7/4+x-7/8=5

7/4+x=5+7/8

7/4+x=47/8

x=47/8-7/4

x=47/8-14/8

x=33/8

a,3,25+0,9-x=0,97

4,15-x=0,97

x=4,15-0,97

x=3,18

b,4,4-9,2+x=1,2

-4,8+x=1,2

x=1,2-(-4,8)

x=6

c,7/5+x-2/5=4

7/5+x=4+2/5

7/5+x=22/5

x=22/5-7/5

x=15/5

x=3

d,1 3/4+x-7/8=5

7/4+x-7/8=5

7/4+x=5+7/8

7/4+x=47/8

x=47/8-7/4

x=47/8-14/8

x=33/8

(3,25 -2/3x):(-7/4)=-3 tim x