Lời giải chi tiết

10        10       10    10       10      10     10     10    10      5     9     8     7     6   10    1     2     3    4    0

9+1+1+6+0+9+8+7+6+7+6+9+7+54+90+87+890=?

1 + 9 = 10     2 + 8 = 10     3 + 7 = 10     4 + 6 = 10     5 + 5 = 10

10 - 1 = 9     10 - 2 = 8     10 - 3 = 7     10 - 4 = 6     10 - 5 = 5

6 + 4 = 10     7 + 3 = 10     8 + 2 = 10     9 + 1 = 10     10 + 0 = 10

10 - 6 = 4     10 - 7 = 3     10 - 8 = 2     10 - 9 = 1     10 - 0 = 10

=10 , =9,8,7,6,5, =10

1 + 9 = 10     2 + 8 = 10     3 + 7 = 10     4 + 6 = 10     5 + 5 = 10

10 - 1 = 9     10 - 2 = 8     10 - 3 = 7     10 - 4 = 6     10 - 5 = 5

6 + 4 = 10     7 + 3 = 10     8 + 2 = 10     9 + 1 = 10     10 + 0 = 10

10 - 6 = 4     10 - 7 = 3     10 - 8 = 2     10 - 9 = 1     10 - 0 = 10

1: =72/90+65/90=137/90

2: =24/56-77/56=-53/56

3: =-7/10+4/5=1/10

4: =15/100-4/100=11/100

5: =4/6-5/6=-1/6

6: =10/40-15/40-76/40=-81/40

7: =-9/10+7/18

=-81/90+35/90=-46/90=-23/45

8: =27/90-55/90=-28/90=-14/45

9: =36/60-50/60-35/60=-49/60

10: =-4/9+5/6-3/8

=-32/72+60/72-27/72

=1/72

\(1,\dfrac{4}{5}+\dfrac{13}{18}=\dfrac{72}{90}+\dfrac{65}{90}=\dfrac{137}{90}\)

\(2,\dfrac{3}{7}-\dfrac{11}{8}=\dfrac{24}{56}-\dfrac{77}{56}=\dfrac{-53}{56}\)

\(3,-\dfrac{7}{10}-\left(-\dfrac{4}{5}\right)=-\dfrac{7}{10}-\left(-\dfrac{8}{10}\right)=\dfrac{1}{10}\)

\(4,\dfrac{3}{20}-\dfrac{1}{25}=\dfrac{75}{500}-\dfrac{20}{500}=\dfrac{55}{500}=\dfrac{11}{100}\)

\(5,\dfrac{2}{3}-\dfrac{5}{6}=\dfrac{12}{18}-\dfrac{15}{18}=-\dfrac{3}{18}=-\dfrac{1}{6}\)

\(6,\dfrac{1}{4}+\left(-\dfrac{3}{8}\right)-\dfrac{19}{10}=\dfrac{8}{32}+\left(-\dfrac{12}{32}\right)-\dfrac{19}{10}=-\dfrac{4}{32}-\dfrac{19}{10}\)

\(=-\dfrac{1}{8}-\dfrac{19}{10}=-\dfrac{10}{80}-\dfrac{152}{80}=-\dfrac{162}{80}=-\dfrac{81}{40}\)

\(7,-\dfrac{9}{10}-\left(-\dfrac{7}{18}\right)=-\dfrac{162}{180}-\left(-\dfrac{70}{180}\right)=-\dfrac{92}{180}=-\dfrac{23}{45}\)

\(8,\dfrac{3}{10}-\dfrac{11}{18}=\dfrac{54}{180}-\dfrac{110}{180}=-\dfrac{56}{180}=-\dfrac{14}{45}\)

\(9,\dfrac{3}{5}-\dfrac{5}{6}+\left(-\dfrac{7}{12}\right)=\dfrac{18}{30}-\dfrac{25}{30}+\left(-\dfrac{7}{12}\right)=-\dfrac{7}{30}+\left(-\dfrac{7}{12}\right)\)

\(=-\dfrac{84}{360}+\left(-\dfrac{210}{360}\right)=-\dfrac{294}{360}=-\dfrac{49}{60}\)

\(10,-\dfrac{4}{9}-\dfrac{-5}{6}-\dfrac{3}{8}=-\dfrac{24}{54}-\dfrac{-45}{54}-\dfrac{3}{8}\)

\(=\dfrac{21}{54}-\dfrac{3}{8}=\dfrac{7}{18}-\dfrac{3}{8}=\dfrac{56}{144}-\dfrac{54}{144}=\dfrac{2}{144}=\dfrac{1}{72}\)

`@mt`

Lời giải chi tiết:

2=1+1          6=2+4          8=5+3          10=8+2

3=1+2          6=3+3          8=4+4          10=7+3

4=3+1          7=6+1          9=8+1          10=6+4

4=2+2          7=5+2          9=7=2          10=5+5

5=4+1          7=4+3         9=6+3           10=10+0

5=3+2          8=7+1         9=5=4           10=0+10

6=5+1          8=6=2         10=9+1         1=0+1

cop hết mạng kìa

b) Tính theo thứ tự từ trái sang phải.

4 + 5 - 7 = 2     6 - 4 + 8 = 10     10 - 9 + 6 = 7     9 - 4 - 3 = 2

1 + 2 + 6 = 9     3 + 2 + 4 = 9     8 - 2 + 4 = 10     8 - 4 + 3 = 7

3 - 2 + 9 = 10     7 - 5 + 3 = 5     3 + 5 - 6 = 2     2 + 5 - 4 = 3

b)

1 + 9 = 10     2 + 8 = 10     3 + 7 = 10     4 + 6 = 10     5 + 5 = 10

10 - 1 = 9     10 - 2= 8     10 - 3 = 7     10 - 4 = 6     10 - 5 = 5

10 - 9 = 1     10 - 8 = 2     10 - 7 = 3     10 - 6 = 4     10 - 0 = 10

TÍNH J

ủa phép tính đâu

mik quên số nào lớn hơn 1

Lời giải chi tiết:

Bài 7:

Số phần kẹo Hùng đã cho Hà và Hồng là:

\(\dfrac{2}{7}+\dfrac{1}{7}=\dfrac{3}{7}\left(phần\right)\)

Hùng còn lại số phần của gói kẹo là:

\(\dfrac{6}{7}-\dfrac{3}{7}=\dfrac{3}{7}\left(phần\right)\)

1:

 2 3/4

5 6/5

3 3/9

7 6/8

2:

1/3 + 2/3 + (3/4 + 1/4) = 2

=2

= 4 5/10

1:

\(2+\dfrac{3}{4}=\dfrac{8}{4}+\dfrac{3}{4}=\dfrac{11}{4};5+\dfrac{6}{5}=\dfrac{25}{5}+\dfrac{6}{5}=\dfrac{31}{5};\dfrac{3}{9}+3=\dfrac{1}{3}+\dfrac{9}{3}=\dfrac{10}{3}\)

2: 

a: \(=\left(\dfrac{1}{3}+\dfrac{2}{3}\right)+\left(\dfrac{3}{4}+\dfrac{1}{4}\right)\\ =1+1=2\)

b: \(=\left(\dfrac{3}{4}+\dfrac{2}{8}\right)+\left(\dfrac{3}{5}+\dfrac{4}{10}\right)\\ =\left(\dfrac{6}{8}+\dfrac{2}{8}\right)+\left(\dfrac{6}{10}+\dfrac{4}{10}\right)\\ =1+1=2\)

c:\(=\left(\dfrac{1}{10}+\dfrac{9}{10}\right)+\left(\dfrac{2}{10}+\dfrac{8}{10}\right)+\left(\dfrac{3}{10}+\dfrac{7}{10}\right)+\left(\dfrac{4}{10}+\dfrac{6}{10}\right)+\dfrac{5}{10}\\ =1+1+1+1+\dfrac{5}{10}=4\dfrac{5}{10}\)