\(\left(5^2\times2^3-7^3\times2\right)\div2\times6-7\div2^5\)

\(=\left(25\times8-343\times2\right)\div2\times6-7\div32\)

\(=\left(200-686\right)\div2\times6-7\div32\)

\(=-486\div2\times6-7\div32\)

\(=-1458-0,21875\)

\(=-1458,21875\)

[(27^4:9^5)+(625^3:125^4)]-2^3

=[(531441:59049)+(244140625:244140625)]-8

=[9+1]-8

=10-8

=2

Nếu dk thì cko mik nhoa

(24*5-5^2*2):(5*2)-3

=(120-50)/10-3

=7-3=4

\(\left(5^2.2^3-7^3.2\right):\left(2.6-7:2^5\right)\\ =\left(25.8-343.2\right):\left(12-7:32\right)\\ =\left(200-686\right):\left(12-\dfrac{7}{32}\right)\\ =-486:\dfrac{377}{32}=-486.\dfrac{32}{377}=-\dfrac{15552}{377}\)

(5^2*2^3-7^3*2):2*6-7:2^5

=(25*8-343*2):3-7/32

=-162-7/32=-5191/32

\(\left(5.2^2-20\right):\left(5+3^2:6\right)\\ =\left(5.4-20\right):\left(5+9:6\right)\\ =\left(20-20\right):\left(5+\dfrac{3}{2}\right)\\ =1:\dfrac{13}{2}=\dfrac{2}{13}\)

(5*2^2-20):5+3^2/6

=(20-20):5+9/6

=3/2

Như vậy phải ko bạn?

72 : {[(2³.6 – 2⁵ + 2) + 6] – 5}

\(36\cdot4-4\cdot\left[82-7\cdot11\right]^2:4-2016^0\)

=9-1-5^2

=8-25=-17

=2^4.5-{131-(13-4)^2}

=80-{131-9^2}

=80-50

=30

HT

=16.5-{131-9^2}

=80-{131-81}

=80-50

=30

__HT__

Theo đề bài ta có : 

`2^4 xx 5 - {131-(13-4)^2}`

`=16 xx5 - { 131 - 9^2 }`

`= 16 xx5 -{131-81}`

`=16xx5-50`

`=80-50`

`=30`