Ta có:

a/b =c/d

⟹a/c=b/d

Áp dụng tính chất dãy tỉ số bằng nhau ta có

a/c=b/d=5a+2b/5c+2b=5a-2b/5c-2d

Vì 5a=2b/5c=2d=5a-2b/5c-2d

⟹5a+2b/5a-2b=5c+2d/5c-2d

Ta có: \(\frac{a}{b}=\frac{c}{d}\Rightarrow\frac{a}{c}=\frac{b}{d}.\)

\(\Rightarrow\frac{5a}{5c}=\frac{2b}{2d}.\)

Áp dụng tính chất dãy tỉ số bằng nhau ta được:

\(\frac{5a}{5c}=\frac{2b}{2d}=\frac{5a+2b}{5c+2d}\) (1)

\(\frac{5a}{5c}=\frac{2b}{2d}=\frac{5a-2b}{5c-2d}\) (2)

Từ (1) và (2) \(\Rightarrow\frac{5a+2b}{5c+2d}=\frac{5a-2b}{5c-2d}\)

\(\Rightarrow\frac{5a+2b}{5a-2b}=\frac{5c+2d}{5c-2d}\left(đpcm\right).\)

Chúc bạn học tốt!

\(\frac{a}{b}=\frac{c}{d}\Rightarrow\frac{a}{c}=\frac{b}{d}=\frac{4a}{4c}=\frac{2b}{2d}=\frac{4a-2b}{4c-2d}=\frac{5a}{5c}=\frac{2b}{2d}=\frac{5a+2b}{5c+2d}\)

Suy ra \(\frac{4a-2b}{4c-2d}=\frac{5a+2b}{5c+2d}\)Suy ra điều phải chứng minh: \(\frac{4a-2b}{5a+2b}=\frac{4c-2d}{5c+2d}\)

Ta có : \(\frac{a}{b}=\frac{c}{d}\Rightarrow\frac{a}{c}=\frac{b}{d}\)

\(\frac{a}{c}=\frac{b}{d}=\frac{3a}{3c}=\frac{5a}{5c}=\frac{2b}{2d}=\frac{3a-2b}{3c-2d}=\frac{5a+2b}{5c+2d}\)

\(\Rightarrow\frac{3a-2b}{5a+2b}=\frac{3c-2d}{2c+2d}\) ( đpcm )

a) a/b=c/d =>a/b+1=c/d+1=>a+b/b=c+d/d

b)a/b=c/d=>a/c=b/d=(a+b)/(c+d)=(2a+2b)/(2c+2d)                 1

  a/c=b/d=(a-b)/(c-d)=(5a-5b)/(5c-5d)                                   2

Từ 1 và 2 ,ta có:

(2a+2b)/(2c+2d)=(5a-5b)/(5c-5d)

a) \(\hept{\begin{cases}\frac{a}{b}=\frac{c}{d}\Rightarrow\frac{a}{c}=\frac{b}{d}=\frac{5a}{5c}=\frac{3b}{3d}=\frac{5a-3b}{5c-3d}\\\frac{a}{c}=\frac{b}{d}\Rightarrow\frac{3a}{3c}=\frac{2b}{2d}=\frac{3a+2b}{3c+2d}\end{cases}}\)

\(\Rightarrow\frac{5a-3b}{5c-3d}=\frac{3a+2b}{3c+2d}\)

\(\Rightarrow\frac{5a-3b}{3a+2b}=\frac{5c-3d}{3c+2d}\)

b) Chứng minh tương tự 

ko biet nghen

\(\frac{a}{b}=\frac{c}{d}\)

=> \(\frac{a}{c}=\frac{b}{d}=\frac{3a}{3c}=\frac{2b}{2d}=\frac{3a-2b}{3c-2d}=\frac{3a+2b}{3c+2d}\)

=> \(\frac{3a-2b}{3c-2d}=\frac{3a+2b}{3c+2d}\)

=> \(\frac{3a-2b}{3a+2b}=\frac{3c-2d}{3c+2d}\) (Đpcm)