x.(\(\dfrac{1}{6}\)+\(\dfrac{1}{10}\)+\(\dfrac{1}{15}\)+\(\dfrac{1}{21}\)+\(\dfrac{1}{28}\)+\(\dfrac{1}{36}\)+\(\dfrac{1}{45}\)+\(\dfrac{1}{55}\)+\(\dfrac{1}{66}\)+\(\dfrac{1}{78}\))=\(\dfrac{220}{39}\)

x.\(\dfrac{20}{39}\)=\(\dfrac{220}{39}\)

x=\(\dfrac{220}{39}\):\(\dfrac{20}{39}\)

x=11

m

lppkokoko

mk sửa 2020 thành 220

???

x.(1/6+1/10+1/15+1/21+1/28+1/36+1/45+1/55+1/66+1/78)=220/39

x.20/39=220/39

x=220/39:20/39

x=11

(x/6+x/10+...+x/66+x/78)*2=220/39*2

x/12+x/20+...x/132+x/156=440/39

x/2-x/3+x/3-x/4+...+x/11-x/12+x/12-x/13=440/39

x/2-x/13=440/39

11x/26=440/39

33x/78=880/78

33x=880

x=880/33

x=80/3=26, (6)

\(x.\left(\dfrac{1}{6}+\dfrac{1}{10}+\dfrac{1}{15}+...+\dfrac{1}{78}\right)=\dfrac{220}{39}\)

\(x.\dfrac{20}{39}=\dfrac{220}{39}\)

\(x=\dfrac{220}{39}:\dfrac{20}{39}\)

x\(=11\)

⇔2x(13.4+14.5+..........+112.13)=22039

      \(\dfrac{x}{6}+\dfrac{x}{10}+\dfrac{x}{15}+\dfrac{x}{21}+\dfrac{x}{28}+\dfrac{x}{36}+\dfrac{x}{45}+\dfrac{x}{55}+\dfrac{x}{66}+\dfrac{x}{78}=\dfrac{220}{39}\)

⇔ \(x.\left(\dfrac{1}{6}+\dfrac{1}{10}+\dfrac{1}{15}+\dfrac{1}{21}+\dfrac{1}{28}+\dfrac{1}{36}+\dfrac{1}{45}+\dfrac{1}{55}+\dfrac{1}{66}+\dfrac{1}{78}\right)\) \(=\) \(\dfrac{220}{39}\)

⇔ \(x.\dfrac{20}{39}=\dfrac{220}{39}\)

⇔ \(x=11\)

( x + 1 ) + ( x + 4 ) + ( x + 7 ) + ......... + ( x + 28 ) = 155

<=>(x+x+x...+x)+(1+4+...+28)=155

=>10x+145=155

=>10x=155-145

=>10x=10

=>x=1

làm cách khác cho nhanh hơn đi

Sai bét

\(\frac{x}{6}+\frac{x}{10}+\frac{x}{15}+\frac{x}{21}+\frac{x}{28}+\frac{x}{39}=\frac{8}{9}.\)

\(\Rightarrow x.\left(\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+\frac{1}{28}+\frac{1}{39}\right)=\frac{8}{9}\)

\(\Rightarrow x.\frac{23}{52}=\frac{8}{9}\)

\(\Rightarrow x=\frac{426}{207}\)

Study well 

\(\frac{x}{6}+\frac{x}{10}+\frac{x}{15}+\frac{x}{21}+\frac{x}{28}+\frac{x}{39}=\frac{8}{9}\)

<=> x\(\left(\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+\frac{1}{28}+\frac{x}{39}\right)=\frac{8}{9}\)

<=> x = \(\frac{8}{9}:\frac{23}{52}\)

<=> x = \(\frac{416}{207}\)

Tứ chép đề bài :vv

\(\left(\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+\frac{1}{28}+\frac{1}{39}\right)x=\frac{8}{9}\)

\(\frac{23}{52}x=\frac{8}{9}\)

\(x=\frac{8}{9}:\frac{23}{52}\)

\(x=\frac{416}{207}\)

Vậy .....