472÷24+7x)+23=16
Tìm số tự nhiên x biết
a ( 2x -3).25=125
b 472: ( 24+5x) + 23 =16
a. 2x - 3 = 125 : 25
2x - 3 = 5
2x = 5 + 3
2x = 8
x = 8 : 2 = 4
b. 472 : ( 24 + 5x ) + 8 = 16
( 24 + 5x ) + 8 = 472 : 16
( 24 + 5x ) + 8 = 29,5
24 + 5x = 29,5 - 8
24 + 5x = 21,5
5x = 21,5 - 24
5x = -2,5
x = -2,5 : 5 = -0,5
a.
(2x - 3).25 =125
2x - 3 =125 : 25
2x - 3 = 5
2x =5 + 3
2x = 8
x = 8 :2
x =4
b.
472 : (24 +5x) + 2 mủ 3 =16
472 :(24 + 5x) + 8 = 16
472 :(24 + 5x) = 16 - 8
472 :(24 + 5x) = 8
24 + 5x = 472 : 8
24 + 5x =59
5x = 59 - 24
5x = 35
x =35:5
x = 7
5x =
c) (7x + x – 28) :100 – 38 = 9.
d) 936 – (4x + 5x ) = 900
e) 280 + 78 : (135 – x :7) =286
f) x – 18 :3 = 16 + 16 : 23.
g) (3x – 10) : 10 = 20.
h) (3x – 24 ).73= 2.74
i) 123 – 5.( x + 4) = 38.
k) [(6x – 72) :2 – 84].28 = 5628.
m) 2x – 138 = 23.32.
n) [(10 - x).2 + 7]:3 -2 = 3.
Trình bày kết quả rõ ràng nha cảm ơn mọi người rất nhiều❤❤❤
c) (7x + x – 28) :100 – 38 = 9
<=> 8x - 28 = 4700
<=> x = 591
d) 936 – (4x + 5x ) = 900
<=> 9x = 36
<=> x = 4
Thực Hiên Phép Tính :
472 +34 - ( 472 - 16 )
472 + 34 - ( 472 - 16 )
= 472 + 34 - 472 + 16
= ( 472 - 472 ) + ( 34 + 16 )
= 0 + 50
= 50
Học tốt nhé bạn !
472 +34 - ( 472 - 16 )
= (34 + 16 ) -( 472 - 472 )
= 50 - 0
= 50
472 + 34 - ( 472 - 16 )
= 472 + 34 - 472 - 16
= ( 472 - 472 ) + ( 34 - 16 )
= 0 + 18 = 18
Vậy 472 + 34 - ( 472 - 16 ) = 18
Chúc bạn hok tốt nhé !!! ^-^
1. (-39)+14+26+39
2. (-54)+16+(-6)+54
3. 45+23+(-35)+(-23)
4. 45.17-5.9.7
5. 24.(16-5)-16.(24-5)
1) -39 +14+26+39
= 39-39 + 40
=40
2) -54 +16 +(-6)+54
=54-54 +10
=10
3) 45 +23+(-35)+(-23)
= 45-35 +23 -23
=10+0
=10
4) 45 .17 - 5.9.7
=45.17 -45.7
=45.( 17-7)
=45 .10
=450
5) 24 ( 16-5) -16(24-5)
=24.16 -24.5 -16 .24 +16 .5
= 24.16 -16.24 +5 (16-24)
=0 +5 .(-8)
=-40
Chúc hok tốt!
1. ( - 39 ) + 14 + 26 + 39
= [ ( - 39 ) + 39 ] + ( 14 + 26 )
= 0 + 40
= 40
2. ( - 54 ) + 16 + ( - 6 ) + 54
= [ ( - 54 ) + 54 ] + [ 16 + ( - 6 ) ]
= 0 + 10
= 10
3. 45 + 23 + ( - 35 ) + ( - 23 )
= [ 45 + ( - 35 ) ] + [ 23 + ( - 23 ) ]
= 10 + 0
= 10
4. 45 . 17 - 5 . 9 . 7
= 45 . 17 - 45 . 7
= 45 . ( 17 - 7 )
= 45 . 10
= 450
5. 24 . ( 16 - 5 ) - 16 . ( 24 - 5 )
= 24 . 11 - 16. 19
= 264 - 304
= 264 + ( - 304 )
= - ( 304 - 364 )
= - 40
Chúc bạn học tốt !
1. (-39)+14+26+39
\(=\left[\left(-39\right)+39\right]+\left(14+26\right)\)
\(=0+40\)
\(=40\)
2. (-54)+16+(-6)+54
\(=\left[\left(-54\right)+54+\left[16+\left(-6\right)\right]\right]\)
\(=0+10\)
\(=10\)
3. 45+23+(-35)+(-23)
\(=\left(45+\left(-35\right)\right)+\left(23+\left(-23\right)\right)\)
\(=10+0\)
\(=10\)
4. 45.17-5.9.7
\(=45.17-45.7\)
\(=45.\left(17-7\right)\)
\(=45.10\)
\(=450\)
5. 24.(16-5)-16.(24-5)
\(=24.16-24.5-16.24+16.5\)
\(=24.\left(16-16\right)+5.\left(-24+16\right)\)
\(=24.0+5.\left(-8\right)\)
\(=0+\left(-40\right)\)
\(=-40\)
Tính hợp lí
(-37) + 14 + 26 + 37
(-24) + 6 + 10 + 24
15 + 23 + (-25) + (-23)
60 + 33 + (-50) + (-33)
(-16) + (-209) + (-14) + 209
(-12) + (-13) + 36 + (-11)
-16 + 24 + 16 – 34
25 + 37 – 48 – 25 – 37
2575 + 37 – 2576 – 29
34 + 35 + 36 + 37 – 14 – 15 – 16 – 17
Câu a:
Ta thấy 37 - 37 = 0
nên nhóm lại kết quả là 14 + 26 = 40
Câu b:
tương tự, kết quả là 6 + 10 = 16
Các câu còn lại như vậy
( -37)+14 +26 +37
=( -37 )+ 37 + (14 + 26 )
=0 +40 = 40
- 24 + 6 +10 +24
=( -24 ) + 24 +( 6 + 10 )
=0 + 16 = 16
15 + 23 + (-25 ) + ( -23 )
= 15 + ( -25 ) + 23 +( -23 )
= -10 + 0
= - 10
60 + 33 + ( -50 ) + ( 33 )
= 60 + (- 50 ) + 33 + ( -33)
= 10 + 0 = 10
( -16) +(-209) + ( -14 ) + 2009
= ( -16 ) + ( -14 ) + ( -209 ) + 209
= -30 + 0
= -30
( -12 ) + ( -13 ) + 36 + (- 11 )
= ( -12 ) + (- 13 ) + ( -11 ) + 36
= - 25 + ( - 11 ) + 36
= -36 + 36
= 0
A×345-34-(63:7-453+666)×{23-[63+(472-453)]}=??????/.
Bài 1. Tính hợp lý
1) (–12) +6.(–3)
2) (36 -2020) + (2019 -136) – 27
3) (144 – 97) – (244 – 197)
4) (–24).13 – 24.( –3)
5) 54+55+56+57+58-(64+65+66+67+68)
6) 24(16 – 5) – 16(24 – 5)
7) 47.(23 + 50) – 23.(47 + 50)
8) (-31). 47 + (-31). 52 + (-31)
Bài 2: Tìm số nguyên x, biết:
1)-17-(2x-5)=-6
2) 10-2(4-3x)=-4
3)-12+3(-x+7)=-18
4)-45:[5.(-3-2x)]=3
5) x.(x+3)=0
6) (x-2).(x+4)=0
7) x.(x+1).(x-3)=0
Bài 1:
1) Ta có: \(\left(-12\right)+6\cdot\left(-3\right)\)
\(=-12-18\)
=-30
2) Ta có: \(\left(36-2020\right)+\left(2019-136\right)-27\)
\(=36-2020+2019-136-27\)
\(=1-100-27\)
\(=-126\)
3) Ta có: \(\left(144-97\right)-\left(244-197\right)\)
\(=144-97-244+197\)
\(=-100+100=0\)
4) Ta có: \(\left(-24\right)\cdot13-24\cdot\left(-3\right)\)
\(=-24\cdot13+24\cdot3\)
\(=24\cdot\left(-13+3\right)\)
\(=24\cdot\left(-10\right)=-240\)
5) Ta có: \(54+55+56+57+58-\left(64+65+66+67+68\right)\)
\(=54+55+56+57+58-64-65-66-67-68\)
\(=\left(54-64\right)+\left(55-65\right)+\left(56-66\right)+\left(57-67\right)+\left(58-68\right)\)
\(=\left(-10\right)+\left(-10\right)+\left(-10\right)+\left(-10\right)+\left(-10\right)\)
=-50
6) Ta có: \(24\cdot\left(16-5\right)-16\cdot\left(24-5\right)\)
\(=24\cdot16-24\cdot5-16\cdot24+16\cdot5\)
\(=-24\cdot5+16\cdot5\)
\(=5\cdot\left(-24+16\right)\)
\(=-5\cdot8=-40\)
7) Ta có: \(47\cdot\left(23+50\right)-23\cdot\left(47+50\right)\)
\(=47\cdot23+47\cdot50-23\cdot47-23\cdot50\)
\(=47\cdot50-23\cdot50\)
\(=50\cdot\left(47-23\right)\)
\(=50\cdot24=1200\)
8) Ta có: \(\left(-31\right)\cdot47+\left(-31\right)\cdot52+\left(-31\right)\)
\(=-31\cdot\left(47+52+1\right)\)
\(=-31\cdot100=-3100\)
Bài 2:
1) Ta có: \(-17-\left(2x-5\right)=-6\)
\(\Leftrightarrow-17-2x+5+6=0\)
\(\Leftrightarrow-2x-6=0\)
\(\Leftrightarrow-2x=6\)
hay x=-3
Vậy: x=-3
2) Ta có: \(10-2\left(4-3x\right)=-4\)
\(\Leftrightarrow10-8+6x+4=0\)
\(\Leftrightarrow6x+6=0\)
\(\Leftrightarrow6x=-6\)
hay x=-1
Vậy: x=-1
3) Ta có: \(-12+3\left(-x+7\right)=-18\)
\(\Leftrightarrow-12-3x+21+18=0\)
\(\Leftrightarrow-3x+27=0\)
\(\Leftrightarrow-3x=-27\)
hay x=9
Vậy: x=9
4) Ta có: \(-45:\left[5\cdot\left(-3-2x\right)\right]=3\)
\(\Leftrightarrow5\cdot\left(-3-2x\right)=-15\)
\(\Leftrightarrow-2x-3=-3\)
\(\Leftrightarrow-2x=0\)
hay x=0
Vậy: x=0
5) Ta có: x(x+3)=0
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-3\end{matrix}\right.\)
Vậy: \(x\in\left\{0;-3\right\}\)
6) Ta có: (x-2)(x+4)=0
\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\x+4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-4\end{matrix}\right.\)
Vậy: \(x\in\left\{2;-4\right\}\)
7) Ta có: \(x\left(x+1\right)\left(x-3\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+1=0\\x-3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-1\\x=3\end{matrix}\right.\)
Vậy: \(x\in\left\{0;-1;3\right\}\)
Bài 1:
1) Ta có: (−12)+6⋅(−3)(−12)+6⋅(−3)
=−12−18=−12−18
=-30
2) Ta có: (36−2020)+(2019−136)−27(36−2020)+(2019−136)−27
=36−2020+2019−136−27=36−2020+2019−136−27
=1−100−27=1−100−27
=−126
Tớ chcs cậu học thật giỏi nha !
tính (rút gọn ) : 1/(9x-18)+(16-7x)/(72-18x)+5/(12x+24)
Tính hợp lí
a. (-24) + 6 + 10 + 24
b. 15 + 23 + (-25) + (-23)
c. 60 + 33 + (-50) + (-33)
d. (-16) + (-209) + (-14) + 209
e. (-12) + (-13) + 36 + (-11)
f. -16 + 24 + 16 - 34
g. 25 + 37 - 48 - 25 - 37
h. 2575 + 37 - 2576 - 29
a)-24+6+10+24
=(-24+24)+6+10=0+6+10=16
b)15+23+(-25)+(-23)
=[15+(-25)]+[23+(-23)]
=-10+0=-10
c)60+33+(-50)+(-33)
=[60+(-50)]+[33+(-33)]
=10+0=10
d)-16+(-209)+(-14)+209
=[-16+(-14)]+(-209+209)
=-30+0=-30
e)-12+(-13)+36+(-11)
=[-12+(-13)+(-11)]+36
=-36+36=0
f)-16+24+16-34
=(-16+16)+(24-34)
=0+(-10)=-10
g)25+37-48-25-37
=(25-25)+(37-37)-48
=0+0-48=-48
h)2575+37-2576-29
=(2575-2576)+(37-29)
=-1+8=7
a/ [(-24)+24]+6+10=0+6+10=16
b/ [15+(-25)]+[23+(-23)]=-10+0=-10
c/[60+(-50)]+[33+(-33)]=10+0=10
Mệt quá phú =_=" Sao nhìu quớ zậy? @_@ Lé mắt rùi