Tìm x
a) 7/x=x/28
b) 10+x/17+x=3/4
c)40+x/77-x=6/7
cho mình hỏi :(tìm số nguyên x)
a,10+x/17+x =3/1
b,40+x/77-x=6/7
(giúp mình với)
tìm x,biết:
a) 2√2x-5√8x+7√18x=28
b)√4x-20+√x-5-1/3√9x-45=4
c)√\(x^2\) -4-√x-2=0
a: \(\Leftrightarrow2\sqrt{2x}-10\sqrt{2x}+21\sqrt{2x}=28\)
=>\(13\sqrt{2x}=28\)
=>căn 2x=28/13
=>2x=784/169
=>x=392/169
b: \(\Leftrightarrow2\sqrt{x-5}+\sqrt{x-5}-\sqrt{x-5}=4\)
=>2*căn x-5=4
=>căn x-5=2
=>x-5=4
=>x=9
c: =>\(\sqrt{x-2}\left(\sqrt{x+2}-1\right)=0\)
=>x-2=0 hoặc x+2=1
=>x=-1 hoặc x=2
Tìm x
1/a) \(\frac{10+x}{17+x}=\frac{3}{4}\)
b) \(\frac{40+x}{77-x}=\frac{6}{7}\)
Ta có :\(\frac{40+x}{77-x}=\frac{6}{7}\)
\(\Rightarrow7\left(40+x\right)=\left(77-x\right).6\)
\(\Leftrightarrow280+7x=462-6x\)
\(\Rightarrow7x+6x=462-280\)
\(\Rightarrow13x=182\)
\(\Rightarrow x=14\)
Ta có : \(\frac{10+x}{17+x}=\frac{3}{4}\)
\(\Rightarrow4\left(10+x\right)=3\left(17+x\right)\)
\(\Leftrightarrow40+4x=51+3x\)
\(\Rightarrow4x-3x=51-40\)
\(\Rightarrow x=11\)
\(\frac{40+x}{77-x}=\frac{6}{7}\)
\(\Rightarrow7\left(40+x\right)=\left(77-x\right).6\)
Tim x biet:
a,10+x / x+17=3 / 4
b'40+x / 77-x=6/7
Lam nhanh va cach lam day du minh se tick
Tim x biet:
a,10+x / x+17=3 / 4
b'40+x / 77-x=6/7
Nho viet ca cach lam nua nhe ,ai lam day du minh se tick!
1.tìm x thuộc Z, biết :
a) x - 3 / x + 7 = -5/-6
b) x - 7 / x + 3 = 4/3
c) x - 10 / 6 = -5/18
d) x - 2 / 4 = 25 / x-2
e) 7/x = x/28
f) 40 + x / 77-x = 6/7
2.tìm x,y thuộc Z, biết
x - y = 4 và x - 7 / y+ 6=7/6
1a) \(\frac{x-3}{x+7}=\frac{-5}{-6}\)
=> \(\frac{x-3}{x+7}=\frac{5}{6}\)
=> (x - 3).6 = 5.(x + 7)
=> 6x - 18 = 5x + 35
=> 6x - 5x = 35 + 18
=> x = 53
b) \(\frac{x-7}{x+3}=\frac{4}{3}\)
=> (x - 7). 3 = (x + 3). 4
=> 3x - 21 = 4x + 12
=> 3x - 4x = 12 + 21
=> -x = 33
=> x = -33
c) \(\frac{x-10}{6}=-\frac{5}{18}\)
=> (x - 10) . 18 = -5 . 6
=> 18x - 180 = -30
=> 18x = -30 + 180
=> 18x = 150
=> x = 150 : 18 = 25/3
d) \(\frac{x-2}{4}=\frac{25}{x-2}\)
=> (x - 2)(x - 2) = 25 . 4
=> (x - 2)2 = 100
=> (x - 2)2 = 102
=> \(\orbr{\begin{cases}x-2=10\\x-2=-10\end{cases}}\)
=> \(\orbr{\begin{cases}x=12\\x=-8\end{cases}}\)
e) \(\frac{7}{x}=\frac{x}{28}\)
=> 7 . 28 = x . x
=> 196 = x2
=> x2 = 142
=> \(\orbr{\begin{cases}x=14\\x=-14\end{cases}}\)
f) \(\frac{40+x}{77-x}=\frac{6}{7}\)
=> (40 + x) . 7 = (77 - x).6
=> 280 + 7x = 462 - 6x
=> 280 - 462 = -6x + 7x
=> -182 = x
=> x = -182
Tìm thừa số (theo mẫu).
Mẫu: ? x 5 = 35 35: 5 = 7. |
a) ? x 4 = 28
b) ? x 3 = 12
c) 6 x ? = 24
a) ? × 4 = 28
28 : 4 = 7
Vậy 7 × 4 = 28.
b) ? × 3 = 12
12 : 3 = 4
Vậy 4 × 3 = 12.
c) 6 × ? = 24
24 : 6 = 4
Vậy 6 × 4 = 24.
1, (2+4+6+...+100)
2, 10-(3-x)=-10+17
3, 17-(3+x)=2-(7-8)
4, (5+x)-(15-31)=-20
5, 17-(3+x)+15-3=2
6, (41-x)-(13-17)=40-50
7, -(52-x)+(40-42)=-57+13
Tim cac so nguyen x; y biet
a. \(\frac{10+x}{17+x}=\frac{3}{4}\)
b. \(\frac{40+x}{77-x}=\frac{6}{7}\)
\(1-\frac{10+x}{17+x}=1-\frac{3}{4}\)
\(\frac{7}{17+x}=\frac{1}{4}\)
\(\frac{7}{17+x}=\frac{7}{28}\Rightarrow17+x=28\)
\(x=28-17=11\)
6.(77-x)=7.(40+x) do đó 462-6x=280+7x hay x=14