Thay x = 25 vào C, ta có: 

\(C=25^7-26\cdot25^6+27\cdot25^5-47\cdot25^4-77\cdot25^3+50\cdot25^2+25-24=-28144\)

P=x3+y3+2xy=(x+y)3−3xy(x+y)+2xy=2013−601xy" role="presentation" style="border:0px; direction:ltr; display:inline-block; float:none; font-size:16.38px; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; padding:1px 0px; position:relative; white-space:nowrap; word-spacing:normal; word-wrap:normal" class="MathJax_CHTML mjx-chtml">P=x3+y3+2xy=(x+y)3−3xy(x+y)+2xy=2013−601xy

S=xy=x(201−x)" role="presentation" style="border:0px; direction:ltr; display:inline-table; float:none; font-size:16.38px; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; padding:1px 0px; position:relative; white-space:nowrap; word-spacing:normal; word-wrap:normal" class="MathJax_CHTML mjx-chtml">S=xy=x(201−x)

1≤x≤200" role="presentation" style="border:0px; direction:ltr; display:inline-block; float:none; font-size:16.38px; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; padding:1px 0px; position:relative; white-space:nowrap; word-spacing:normal; word-wrap:normal" class="MathJax_CHTML mjx-chtml">1≤x≤200

S=200−(x−1)(x−200)≥0⇒Smin=200" role="presentation" style="border:0px; direction:ltr; display:inline-block; float:none; font-size:16.38px; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; padding:1px 0px; position:relative; white-space:nowrap; word-spacing:normal; word-wrap:normal" class="MathJax_CHTML mjx-chtml">S=200−(x−1)(x−200)≥0⇒Smin=200

x≤y⇒x≤100" role="presentation" style="border:0px; direction:ltr; display:inline-block; float:none; font-size:16.38px; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; padding:1px 0px; position:relative; white-space:nowrap; word-spacing:normal; word-wrap:normal" class="MathJax_CHTML mjx-chtml">x≤y⇒x≤100

S=100.101−(x−100)(x−101)≤100.101⇒Smax=100.101" role="presentation" style="border:0px; direction:ltr; display:inline-block; float:none; font-size:16.38px; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; padding:1px 0px; position:relative; white-space:nowrap; word-spacing:normal; word-wrap:normal" class="MathJax_CHTML mjx-chtml">S=100.101−(x−100)(x−101)≤100.101⇒Smax=100.101

A

Chọn A

(-12)x7+(-8)x7+4x(-25)+(-6)x(-25)=(-12-8)x7+(-25)(4x-6x)=7x(-20)+(-25)(-2x)=-140x+50x=-90x

\(a)\frac{11}{8}-\frac{7}{8}+\frac{3}{4}=\frac{4}{8}+\frac{3}{4}=\frac{2}{4}+\frac{3}{4}=\frac{5}{4}\)

\(b)\frac{24}{8}-\frac{5}{8}-3=(\frac{24}{8}-3)-\frac{5}{8}=3-3-\frac{5}{8}=-\frac{5}{8}\)

\(c)\)Tự làm

\(d)56\cdot78+8634=4368+8634=13002\)

= 1 - 1 3 + 1 3 - 1 5 + 1 5 - 1 7 + 1 7 - 1 11 + 1 11 = 1   - 1 11 = 10 11

\(\frac{8.15.42}{16.21.45}=\frac{8.15.21.2}{8.2.21.15.3}=\frac{1}{3}\)

\(\frac{25.33.60.7}{21.65.121.48}=\frac{5.5.11.2.12.5.7}{7.3.13.5.11.12.12.4}=\frac{25}{572}\)

Đề : Em muốn tham gia học ngoại khóa môn bơi lội  ở nhà văn hóa thiếu nhi tiinhr đồng nai. Em hãy viết lá đơn xin tham gia khóa học đó

làm hộ mình nhé 

\(\frac{8\cdot15\cdot42}{16\cdot21\cdot45}=\frac{8\cdot15\cdot21\cdot2}{2\cdot8\cdot21\cdot15\cdot3}=\frac{1}{3}\)

\(\frac{25\cdot33\cdot60\cdot7}{21\cdot65\cdot121\cdot48}=\frac{5\cdot5\cdot3\cdot11\cdot12\cdot5\cdot7}{3\cdot7\cdot13\cdot5\cdot11\cdot11\cdot12\cdot4}=\frac{5\cdot5}{13\cdot11\cdot4}=\frac{25}{572}\)

x⁷-26x⁶+27x⁵-47x⁴-77x³+50x²+x-24

=x⁷-25x⁶-x⁶+25x⁵+2x⁵-50x⁴+3x⁴-75x³-2x³+50x²+x-24

= x⁶(x+(-25))-x⁵(x-25)+2x⁴(x-25)+3x³(x-25)

-2x^2​(x-25)+x-24

Thay x=25 vào biểu thức :

=>25 -24=1

Vậy C=1