2,8 : (1/5 - 3x) = 1 2/5
\(2,8:\left(\frac{1}{5}-3x\right)=1\frac{2}{5}\)
\(2.8:\left(\frac{1}{5}-3x\right)=1\frac{2}{5}\)
\(\frac{14}{5}:\left(\frac{1}{5}-3x\right)=\frac{7}{5}\)
\(\frac{1}{5}-3x=\frac{14}{5}:\frac{7}{5}\)
\(\frac{1}{5}-3x=2\)
\(3x=\frac{1}{5}-2\)
\(3x=-\frac{9}{5}\)
\(x=-\frac{3}{5}\)
\(2,8:\left(\frac{1}{5}-3x\right)=1\frac{2}{5}\Rightarrow\frac{14}{5}:\left(\frac{1}{5}-3x\right)=\frac{7}{5}\)
\(\Rightarrow\frac{1}{5}-3x=\frac{14}{5}:\frac{7}{5}\)
\(\Rightarrow\frac{1}{5}-3x=2\)
\(\Rightarrow\frac{1}{5}-2=3x\)
\(\Rightarrow3x=-\frac{9}{5}\)
\(\Rightarrow x=-\frac{9}{5}:3=-\frac{3}{5}\)
2,8:(1/5-3x)=7/5
Ta có: \(2,8:\left(\frac{1}{5}-3x\right)=\frac{7}{5}\)
\(\Leftrightarrow\frac{14}{5}:\left(\frac{1}{5}-3x\right)=\frac{7}{5}\)
\(\Leftrightarrow\frac{1}{5}-3x=2\)
\(\Leftrightarrow3x=\frac{1}{5}-2=\frac{9}{5}\)
hay \(x=\frac{3}{5}\)
Vậy: \(x=\frac{3}{5}\)
1 . Tìm x
2,8 :( 1/5 - 3x ) = \(1\frac{2}{5}\)
\(\Rightarrow\) 1/5-3x = 2/8 : 7/5 = 5/28
\(\Rightarrow\) 3x = 1/5 - 5/28 = 3/140
\(\Rightarrow\) x = 3/140 : 3 = 1/140
tìm x :
2,8:(3x-\(\frac{5}{8}\))=2\(\frac{2}{5}\)
\(2,8:\left(3.x-\frac{5}{8}\right)=2\frac{2}{5}\)
=>\(\frac{14}{5}:\left(3.x-\frac{5}{8}\right)=\frac{12}{5}\)
=>\(\frac{14}{5}:\frac{13}{5}=3.x-\frac{5}{8}\)
=>\(3.x-\frac{5}{8}=\frac{14}{13}\)
=>\(3.x=\frac{14}{13}+\frac{5}{8}\)
=>\(3.x=\frac{177}{104}\)
=>\(x=\frac{59}{104}\)
2,8 :( 3x -5/8)= 2/2/5
2,8:( 3x- 5,8)= 12/5
3x-5/8 = 2,8:12/5
3x -5/8 = 7/6
3x= 7/6 +5/8
3x= 43/ 24
x= 43/24 :3
x= 43/72
nha bn, mknghix vậy
\(2,8:\left(3x-\frac{5}{8}\right)=2\frac{2}{5}\)
\(\frac{14}{5}:\left(3x-\frac{5}{8}\right)=\frac{12}{5}\)
\(\left(3x-\frac{5}{8}\right)\)\(=\frac{14}{5}:\frac{12}{5}\)
\(\left(3x-\frac{5}{8}\right)\)\(=\frac{14}{5}.\frac{5}{12}\)
\(3x-\frac{5}{8}\) \(=\frac{7}{6}\)
\(3x\) \(=\frac{7}{6}+\frac{5}{8}\)
\(3x\) \(=\frac{28}{24}+\frac{15}{24}\)
\(3x\) \(=\frac{43}{24}\)
\(x\) \(=\frac{43}{24}:3\)
\(x\) \(=\frac{43}{24}.\frac{1}{3}\)
\(x\) \(=\frac{43}{72}\)
Vậy \(x\) \(=\frac{43}{72}\)
CHÚC BẠN HỌC TỐT
Bài 1: thực hiên phép tinh
A, -5/8÷(3/4-1/2)=
B, 4,1/2÷(5/2-3,3/4)+(-1/2)2=
C, 75 phần trăm -1,1/2×4/3+1,5÷-9/4×1/4=
Bai 2 tim x
A, 2,8÷(1/5-3x)=7/5 B, 4-(1/2x+3/4)=-1,5
C,|2/3x+1/5|=5/6
Bài 5 cho neN chung to răng phân so 14n+3/21n+5 là phân so tôi gian
Giúp mình voi ạ đang cần gap
1. Tìm giá trị lớn nhất của:
a) A = 1,7 + |3,4 - x |
b) B = |3x + 8,4| - 14,2
c) C = |x + 2,8| - 3,5
d) D = |x - 2/5 | + 3/7
Bài 2: Tìm x, biết:
a) \(-0,6.x-\dfrac{7}{3}=5,4\)
b) \(2,8:\left(\dfrac{1}{5}-3.x\right)=1\dfrac{2}{5}\)
a) \(-0,6x-\dfrac{7}{3}=5,4\Leftrightarrow-\dfrac{3}{5}x=5,4+\dfrac{7}{3}\Leftrightarrow x=\dfrac{116}{15}.\left(-\dfrac{5}{3}\right)=-\dfrac{116}{9}\).
b) \(2,8:\left(\dfrac{1}{5}-3x\right)=1\dfrac{2}{5}\Leftrightarrow\dfrac{1}{5}-3x=2,8:\dfrac{7}{5}\Leftrightarrow-3x=2-\dfrac{1}{5}\Leftrightarrow x=\dfrac{9}{5}:\left(-3\right)=-\dfrac{3}{5}\).
a] x: 0,15=[2,8+0,38] : 0,75
b] 5/12:x=[ 5/6-1/2]x5/4
a.x : 0,15 = (2,8 + 0,38) : 0,75
x : 0,15 =3,18 : 0,75
x : 0,15 = 4.24
x = 4,24 . 0,15
x = 0.636
b.5/12 : x = (5/6 - 1/2) . 5/4
5/12 : x = 1/3 . 5/4
5/12 : x = 5/12
x = 5/12 : 5/12
x = 1
Tìm x,y Biết :
a, | 2x | - | - 2,5 | = | -7,5|
b, | 3x | . | -3,5 | = | -2,8 |
c, ( 3x - 5 ) . ( \(\frac{3}{2}\)x + 2 ) . ( 0,5x - 10 ) = 0
a) \(\left|2x\right|-\left|-2,5\right|=\left|-7,5\right|\)
\(\Leftrightarrow\left|2x\right|-2,5=7,5\)
\(\Leftrightarrow\left|2x\right|=10\)
\(\Leftrightarrow\begin{cases}x\ge0\\2x=10\end{cases}\) hoặc \(\begin{cases}x< 0\\2x=-10\end{cases}\)
\(\Leftrightarrow\begin{cases}x\ge0\\x=5\left(tm\right)\end{cases}\) hoặc \(\begin{cases}x< 0\\x=-5\left(tm\right)\end{cases}\)
Vậy x={5;-5}
b)\(\left|3x\right|\cdot\left|-3,5\right|=\left|-2,8\right|\)
\(\Leftrightarrow\left|3x\right|\cdot3,5=2,8\)
\(\Leftrightarrow\left|3x\right|=\frac{4}{5}\)
\(\Leftrightarrow\begin{cases}x\ge0\\3x=\frac{4}{5}\end{cases}\) hoặc \(\begin{cases}x< 0\\3x=-\frac{4}{5}\end{cases}\)
\(\Leftrightarrow\begin{cases}x\ge0\\x=\frac{4}{15}\end{cases}\) hoặc \(\begin{cases}x< 0\\x=-\frac{4}{15}\end{cases}\)
Vậy x={4/15;-4/15}
c) \(\left(3x-5\right)\left(\frac{3}{2}x+2\right)\left(0,5x-10\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}3x-5=0\\\frac{3}{2}x+2=0\\0,5x-10=0\end{array}\right.\)\(\Leftrightarrow\left[\begin{array}{nghiempt}x=\frac{5}{3}\\x=-\frac{4}{3}\\x=20\end{array}\right.\)
a)|2x|-|-2,5|=|-7,5|
|2x|-2,5=7,5
|2x|=10
\(\Rightarrow\left[\begin{array}{nghiempt}2x=10\\2x=-10\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=5\\x=-5\end{array}\right.\)
Vậy x=5;-5
b)|3x|.|-3,5|=|-2,8|
|3x|.3,5=2,8
|3x|=0,8
\(\Rightarrow\left[\begin{array}{nghiempt}3x=0,8\\3x=-0,8\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=\frac{4}{15}\\x=-\frac{4}{15}\end{array}\right.\)
Vậy \(x=\frac{4}{15};-\frac{4}{15}\)
c, ( 3x - 5 ) . ( \(\frac{3}{2}x\) + 2 ) . ( 0,5x - 10 ) = 0
\(\left(3x^2+6x-\frac{15}{2}x-10\right)\left(0,5x-10\right)=0\)
\(\left(3x^2-\frac{3}{2}x-10\right)\left(0,5x-10\right)=0\)
\(1,5x^3-0,75x^2-5x-30x^2+15x+100=0\)
\(1,5x^3-30,75x^2+10x+100=0\)
\(1,5x^3-1,5x^2.20,5+10x+100=0\)
\(1,5x^2.\left(x-20,5\right)+10.\left(x+10\right)=0\)
Đến đây thì mk .......