tim cac gia tri nguyen cua x de gia tri bieu thuc y=2x^2+1/2x-1 la so nguyen
Tim cac gia tri nguyen cua x de cac gia tri bieu thuc sau la so nguyen
a, 9-2x/x-3
b,3x-5/x-2
c,-3/4-x
tim cac gia tri nguyen cua x de cac gia tri bieu thuc sau la so nguyen
a,9-2x/x-3
b,3x-5/x-2
c,-3/4-x
tim cac gia tri nguyen x sao cho bieu thuc p=2x-1/2x+1 nhan gia tri nguyen
bai 1
cho bieu thuc A = 5/n+1 voi N THUOC Z
a, de A la phan so thi n co dieu kien gi ?
b , tim tat ca cac gia tri nguyen cua n de gia tri A la 1 so nguyen ?
bai 2
cho bieu thuc M = 6/n-3 voi n thuoc Z .Co bao nhieu gia tri cua n de :
a, M ko phai la phan so
b , M la phan so va cp gia tri nguyen ?
bai 3 viet tap hop cacs so nguyen sao cho :
-12/4 < x <6/3
Bài 1:
a: Để A là phân số thì n+1<>0
hay n<>-1
b: Để A là số nguyên thì \(n+1\in\left\{1;-1;5;-5\right\}\)
hay \(n\in\left\{0;-2;4;-6\right\}\)
Cho cac bieu thuc :
\(A=\dfrac{\sqrt{x}+4}{\sqrt{x}+2},B=\left(\dfrac{\sqrt{x}}{\sqrt{x}+4}+\dfrac{4}{\sqrt{x}-4}\right):\dfrac{x+16}{\sqrt{x}+2}\)
a) Rut gon B ?
b) Tim cac gia tri nguyen cua x de cac gia tri cua bieu thuc B(A-1) la so nguyen.
Lần sau ghi dấu ra xíu nhé :v
a) Đặt \(\sqrt{x}=a\Rightarrow B=\left(\dfrac{a}{a+4}+\dfrac{4}{a-4}\right):\dfrac{a^2+16}{a+2}\)
Quy đồng,rút gọn : \(B=\dfrac{a+2}{a^2-16}\Rightarrow B=\dfrac{\sqrt{x}+2}{x-16}\)
b) \(B\left(A-1\right)=\dfrac{\sqrt{x}+2}{x-16}\left(\dfrac{\sqrt{x}+4}{\sqrt{x}+2}-1\right)=\dfrac{2}{x-16}\)
x - 16 là ước của 2 => \(x\in\left\{14;15;17;18\right\}\)
mới làm quen toán 9 ;v có gì k rõ ae chỉ bảo nhé :))
Cho cac bieu thuc
A=n+6 phan n-5 va B=3n-9 phan n-6
a/ Tim gia tri nguyen cua n de A, B la phan so ?
b/ Tim gia tri nguyen cua n de A, B co gia tri nguyen?
c/ Tim gia tri nguyen cua n de A, B co gia tri nguyen lon nhat?
1) Cho bieu thuc A=\(3+\frac{2}{x-1}\). Tinh gia tri cua bieu thuc A khi |2x-3|=1
2) Rut gon bieu thuc B=\(\frac{x}{x-1}\)-\(\frac{x-5}{x+1}\)-\(\frac{3-x}{1-x^2}\)
3) Tim cac gia tri nguyen cua x de bieu thuc \(\frac{B}{A}\)co gia tri nguyen duong
1) Cho bieu thuc: \(B=\left(\frac{\sqrt{x}}{\sqrt{x}+4}+\frac{4}{\sqrt{x}-4}\right):\frac{x+16}{\sqrt{x}+2}\left(x\ge0,x\ne16\right)\)
a) Cho bieu thuc A= \(\frac{\sqrt{x}+4}{\sqrt{x}+2}\) ; voi cac cua bieu thuc A va B da cho, hay tim cac gia tri cua x nguyen de gia tri cua bieu thuc B(A;-1) la so nguyen
tim cac gia tri nguyen cua x de bieu thuc sau nhan gia tri duong (x+1).(x-2)/x+6
\(\Rightarrow\)(x + 1) . (x - 2)\(⋮\)(x + 6)
\(\Rightarrow\)(x + 1) . (x -2)\(⋮\)x + 6
(x - 2) . (x+1) \(⋮\)x+ 6
(x - 2) . (x + 6 - 5)\(⋮\)x+ 6
x + 6 \(⋮\)x + 6
5\(⋮\)x + 6
( x -2 ) \(⋮\)6
6+x\(\in\)Ư (5) = ( 1 , 5) Vì biểu thức trên dương nên 6 + x cũng dương.
x + 6 = 1 x + 6 =5
x=-5 x=-1
Vậy x\(\in\)(-5, -1)