F=4/7.3+6/7.4+9/10.41+7/10.57+13/57.14
tính giá trị biểu thúc sau
Những câu hỏi liên quan
A=4/7.31+6/7.41+9/10.41+7/10.57+13/57.14
`Answer:`
\(A=\frac{4}{7.31}+\frac{6}{7.41}+\frac{9}{10.41}+\frac{7}{10.57}\)
\(=\frac{5.4}{5.\left(7.31\right)}+\frac{5.6}{5.\left(7.41\right)}+\frac{5.9}{5.\left(10.41\right)}+\frac{5.17}{5.\left(10.57\right)}\)
\(=\frac{20}{35.31}+\frac{30}{35.41}+\frac{45}{50.41}+\frac{35}{50.57}\)
\(=5.\left(\frac{4}{35.31}+\frac{6}{35.41}+\frac{9}{50.41}+\frac{7}{50.57}\right)\)
\(=5.\left(\frac{1}{31}-\frac{1}{35}+\frac{1}{35}-\frac{1}{41}+\frac{1}{41}-\frac{1}{50}+\frac{1}{50}-\frac{1}{57}\right)\)
\(=5.\left(\frac{1}{31}-\frac{1}{57}\right)\)
\(=5.\frac{26}{1767}\)
\(=\frac{130}{1767}\)
Tính B=\(\frac{4}{7.31}+\frac{6}{7.41}+\frac{9}{10.41}+\frac{7}{10.57}+\frac{13}{57.14}\)
Đây là toán lớp 6.
=>1/5B= 4/7.5.31 +6/7.5.41+9/5.10.41+7/5.10.57+13/57.5.14
=>1/5B=4/31.35+6/35.41+....+13/57.70
=>1/5B=1/31-1/35+1/35-1/41+...+1/57-1/70
=>1/5B=1/31-1/70
=>1/5B=39/2170
=>B=39/2170:1/5
=>B=39/424
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Ta có:
\(\frac{B}{5}=\frac{4}{35.31}+\frac{6}{35.41}+\frac{9}{50.41}+\frac{7}{50.57}+\frac{13}{57.70}\)
\(=\frac{35-31}{35.31}+\frac{41-35}{35.41}+\frac{50-41}{50.41}+\frac{57-50}{50.57}+\frac{70-57}{57.70}\)
\(=\frac{1}{31}-\frac{1}{35}+\frac{1}{35}-\frac{1}{41}+\frac{1}{41}-\frac{1}{50}+\frac{1}{50}-\frac{1}{57}+\frac{1}{57}-\frac{1}{70}\)
\(=\frac{1}{31}-\frac{1}{70}\)
\(\rightarrow B=5\cdot\left(\frac{1}{31}-\frac{1}{70}\right)\)
\(=5\cdot\frac{39}{2170}\)
\(=\frac{39}{434}\)
Vậy B=\(\frac{39}{434}\)
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Ta có:
\(\frac{B}{5}=\frac{4}{35.31}+\frac{6}{35.41}+\frac{9}{50.41}+\frac{7}{50.57}+\frac{13}{57.70}\)
\(=\frac{1}{31}-\frac{1}{35}+\frac{1}{35}-\frac{1}{41}+\frac{1}{41}-\frac{1}{50}+\frac{1}{50}-\frac{1}{57}+\frac{1}{57}-\frac{1}{70}\)
\(=\frac{1}{31}-\frac{1}{70}\)
\(\Rightarrow B=5\left(\frac{1}{31}-\frac{1}{70}\right)\)
\(=\frac{39}{434}\)
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\(B=\frac{4}{7.31}+\frac{6}{7.41}+\frac{9}{10.41}+\frac{7}{10.57}+\frac{13}{57.14}\)
Các cậu giúp tớ bài này với, tớ nghĩ mãi ko ra
\(B=\frac{20}{35.31}+\frac{30}{35.41}+\frac{45}{50.41}+\frac{35}{50.57}+\frac{65}{57.70}\)
\(B=5.\left(\frac{4}{35.31}+\frac{6}{35.41}+\frac{9}{50.41}+\frac{7}{50.57}+\frac{13}{57.70}\right)\)
\(B=5.\left(\frac{1}{31}-\frac{1}{35}+\frac{1}{35}-\frac{1}{41}+\frac{1}{41}-\frac{1}{50}+\frac{1}{50}-\frac{1}{57}+\frac{1}{57}-\frac{1}{70}\right)\)
\(B=5.\left(\frac{1}{31}-\frac{1}{70}\right)\)
\(B=5.\frac{39}{2170}\)
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A=4/19.31+6/7.41 +9/10.41+ 7/10.57
Tính A
Cho A=4/7.31+6/7.41+9/10.41+7/10.57+1958/57.403
B=7/19.31+5/19.43+3/23.43+13/23.59+1957/29.2015
Tính 82A/5B
Cho 2 biểu thức:
A= 4/7.31 + 6/7.41 + 9/10.41 + 7/10.57
B= 7/19.31 + 5/19.43 + 3/23.43 + 11/23.57
Tính A/B
Bài 5: Thực hiện phép tính \(\dfrac{4}{7.31}+\dfrac{6}{7.41}+\dfrac{9}{10.41}+\dfrac{7}{10.57}\)
=4/217+6/287+9/410+7/570
=130/1767
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Cho A =4/7.31+6/7.41+9/10.41+7/10.57+13/14.57 ; B=7/19.31+5/19.43+3/23.43+11/23.57+17/57.35.Tính tỉ số A/B.\(\)
C = 4 / 31 .7 + 6/ 7.41 + 9/10.41 + 7/10.57
