help me

Help me

\(=6\sqrt{2}+\sqrt{\dfrac{16}{3}}+\dfrac{9}{2}\cdot\sqrt{\dfrac{8}{3}}+6\sqrt{3}\)

\(=6\sqrt{2}+\dfrac{4}{3}\sqrt{3}+3\sqrt{6}+6\sqrt{3}\)

\(=6\sqrt{2}+3\sqrt{6}+\dfrac{22}{3}\sqrt{3}\)

a, \(5\sqrt{\dfrac{1}{5}}+\dfrac{1}{2}\sqrt{20}+\sqrt{5}\)

\(=\sqrt{5}+\dfrac{1}{2}.2\sqrt{5}+\sqrt{5}\)

\(=3\sqrt{5}\)

b, \(\sqrt{\dfrac{1}{2}}+\sqrt{4,5}+\sqrt{12,5}\)

\(=\sqrt{0,5}+3\sqrt{0,5}+5\sqrt{0,5}=9\sqrt{0,5}\)

c, \(\sqrt{20}-\sqrt{45}+3\sqrt{18}+\sqrt{72}\)

\(=2\sqrt{5}-3\sqrt{5}+3\sqrt{18}+2\sqrt{18}\)

\(=-\sqrt{5}+5\sqrt{18}\)

d, \(0,1.\sqrt{200}+2\sqrt{0,08}+0,4\sqrt{50}\)

\(=\sqrt{0,01.200}+0,2.\sqrt{2}+0,4.5\sqrt{2}\)

\(=\sqrt{2}+0,2\sqrt{2}+2\sqrt{2}=3,2\sqrt{2}\)

Chúc bạn học tốt!!!

a, \(3\sqrt{5}\)

b, \(\dfrac{9\sqrt{2}}{2}\)

c, \(15\sqrt{2}-\sqrt{5}\)

d, \(\dfrac{17\sqrt{2}}{5}\)

\(\left(\sqrt{4,5}-\frac{1}{2}.\sqrt{72}+5\sqrt{\frac{1}{2}}\right).\left(42\sqrt{\frac{25}{6}}-10\sqrt{\frac{3}{2}}-12\sqrt{\frac{98}{3}}\right)\)

=\(\left(\frac{3\sqrt{2}}{2}-3\sqrt{2}+\frac{5\sqrt{2}}{2}\right).\left(35\sqrt{6}-5\sqrt{6}-28\sqrt{6}\right)\)

=\(\left(\frac{3\sqrt{2}-6\sqrt{2}+5\sqrt{2}}{2}\right).2\sqrt{6}\)

=\(2\sqrt{2}.\sqrt{6}=4\sqrt{3}\)

TRẢ LỜI :

\(=\sqrt{5}+\sqrt{5}+\sqrt{5}=3\sqrt{5}\)

c) √20 - √45 + 3√18 + √72

= √4.5 - √9.5 + 3√9.2 + √36.2

= 2√5 - 3√5 + 9√2 + 6√2

= -√5 + 15√2

a) 3√5                                           b) 9√2 / 2

c) -√5 + 15√2                                d)
3,4√2

 

a) 3 \sqrt{5}35​.

b) \dfrac{9}{\sqrt{2}}2​9​ hay \dfrac{9 \sqrt{2}}{2}292​​.

c) 15 \sqrt{2}-\sqrt{5}152​−5​.

d) 3,4 \cdot \sqrt{2}3,4⋅2​.

Câu c là 2/5+1-4/5=

5-1/3-4/5=58/15

2-3/5-4/5=3/5

2+1-4/5=11/5

A.\(\frac{1}{6}\)

B.\(\frac{11}{5}\)

C.\(\frac{3}{5}\)