50²⁰ = 50 x 50 x 50 x ... x 50 x 50 (có 20 số)

= (50 x 50) x (50 x 50) x ... x (50 x 50)  (có 10 cặp)

= 2500 x 2500 x ... x 2500 (có 10 số)

= 2500¹⁰

Mà 2500¹⁰ < 2550¹⁰ => 50²⁰ < 2550¹⁰

ta có:

\(50^{20}=50^{2x10}=\left(50^2\right)^{10}=2500^{10}\)

Vì  \(2500< 2550=>2500^{10}< 2550^{10}=>50^{20}< 2550^{10}\)

Vậy \(50^{20}< 2550^{10}\)

\(50^{20}\)và  \(2550^{10}\)

Ta có : 

\(50^{20}=\left(50^2\right)^{10}=2500^{10}\)

Vì \(2500< 2550\)nên \(50^{20}< 2550^{10}\)

a/ ta co \(50^{20}=\left(50^2\right)^{10}\)

           \(\left(50^2\right)^{10}=2500^{10}< 2550^{10}\)

           Hay \(50^{20}< 2550^{10}\)

b/   ta có  \(3^{75}=\left(3^3\right)^{25}\)

              \(5^{50}=\left(5^2\right)^{25}\)

\(\Rightarrow\left(3^3\right)^{25}=27^{25}\)

\(\Rightarrow\left(5^2\right)^{25}=25^{25}\)

Vay \(3^{75}>5^{50}\)

a. Ta có: \(50^{20}=50^{2.10}=2500^{10}< 2550^{10}\)

Vậy \(5^{20}< 2550^{10}\)

Ý b làm tương tự, tách 10 thành 5.2 là được.

a) 50²⁰ và 2550¹⁰

ta có : 50²⁰=(50²)¹⁰=2500¹⁰

=> 2500¹⁰<2550¹⁰

vì 2500<2550 và 10=10

hay 50²⁰<2550¹⁰

Vậy 50²⁰<2550¹⁰

b)999¹⁰ và 999999⁵

Ta có : 999¹⁰ = (999²)⁵

          999999⁵ = (999.1001)⁵

Ta thấy : (999²)=999.999 

 999.999 < 999.1001 vì 999<1001

=> 999²<999.1001

=>(999²)⁵<(999.1001)5

hay 999¹⁰<999999⁵

 Vậy 999¹⁰< 999999⁵

Ta có 

\(2550^{10}=\left(51.50\right)^{10}=51^{10}.50^{10}>50^{10}.50^{10}=50^{20}\) 

Vậy\(50^{20}< 2550^{10}\)

50²⁰ và 2550¹⁰

50²⁰= (5²)¹⁰= 25¹⁰

Ta thấy 25¹⁰ và 2550¹⁰có cùng chung một số mũ nên 2550¹⁰ không cần phải tính nữa.

Vậy : 50²⁰< 2550¹⁰

Ta co :

50^20=(50²)¹⁰=2500¹⁰

Do 2500¹⁰<2550¹⁰

^Vay 50²⁰<2550¹⁰

a)Ta có:\(26^8\)<\(27^8\)=\(\left(3^3\right)^8\)=\(3^{24}\)

Mà \(9^{12}=\left(3^2\right)^{12}=3^{24}\)

\(\Rightarrow\)\(26^8< 9^{12}\)

b)Ta có: \(50^{20}=\left(50^2\right)^{10}=2500^{10}< 2550^{10}\)

\(\Rightarrow50^{20}< 2550^{10}\)

1,10²⁰và 90¹⁰

ta có:+,10²⁰=(10²)¹⁰=100¹⁰

        +,90¹⁰=90¹⁰

vì 100¹⁰>90¹⁰=>10²⁰>90¹⁰

2,(1/16)¹⁰ và (1/2)⁵⁰

ta có:+, (1/16)¹⁰=(1/16)¹⁰

         +,(1/2)⁵⁰=(1/2⁵)¹⁰=(1/32)¹⁰

vì (1/16)¹⁰>(1/32)¹⁰=>(1/16)¹⁰>(1/2)⁵⁰

k mik nhé

\(a,\)  \(10^{20}=10^{10+10}=10^{10}.10^{10}\)

        \(90^{10}=9^{10}.10^{10}\)

  Vì \(10^{10}.10^{10}>9^{10}.10^{10}\)

    \(\Rightarrow10^{20}>90^{10}\)

Vậy \(10^{20}>90^{10}\)

\(b,\)\(\left(\frac{1}{16}\right)^{10}=\frac{1^{10}}{16^{10}}=\frac{1}{\left(4^2\right)^{10}}=\frac{1}{4^{20}}\)

   \(\left(\frac{1}{2}\right)^{50}=\frac{1^{50}}{2^{50}}=\frac{1}{\left(2^2\right)^{25}}=\frac{1}{4^{25}}\)

Vì \(\frac{1}{4^{20}}>\frac{1}{4^{25}}\)

\(\Rightarrow\left(\frac{1}{16}\right)^{10}>\left(\frac{1}{2}\right)^{50}\)

Vậy \(\left(\frac{1}{16}\right)^{10}>\left(\frac{1}{2}\right)^{50}\)

                         ~~~~~~~~~~Hok tốt~~~~~~~~~~~

Bạn tham khảo nhé 

a )  Ta có : 

\(\left(-\frac{1}{5}\right)^{300}=\left(\frac{1}{5}\right)^{300}=\frac{1}{5^{300}}=\frac{1}{\left(5^3\right)^{100}}=\frac{1}{125^{100}}\)

\(\left(-\frac{1}{3}\right)^{500}=\left(\frac{1}{3}\right)^{500}=\frac{1}{3^{500}}=\frac{1}{\left(3^5\right)^{100}}=\frac{1}{243^{100}}\)

Do \(\frac{1}{125^{100}}>\frac{1}{243^{100}}\left(125^{100}< 243^{100}\right)\)

\(\Rightarrow\left(-\frac{1}{5}\right)^{300}>\left(-\frac{1}{3}\right)^{500}\)

b ) 

Ta có : 

\(2550^{10}=\left(50.51\right)^{10}=50^{10}.51^{10}\)

\(50^{20}=50^{10}.50^{10}\)

Do \(50^{10}.51^{10}>50^{10}.50^{10}\)

\(\Rightarrow50^{20}< 2550^{10}\)

c ) 

Ta có : 

\(2^{100}=\left(2^4\right)^{25}=16^{25}\)

\(3^{75}=\left(3^3\right)^{25}=27^{25}\)

\(5^{50}=\left(5^2\right)^{25}=25^{25}\)

Do \(16^{25}< 25^{25}< 27^{25}\)

\(\Rightarrow2^{100}< 5^{50}< 3^{75}\)

b)2550¹⁰>2500¹⁰=50²⁰

=>2550¹⁰>50²⁰

các câu khác chưa ra