0,(6)=2/3

0,(24)=8/33

2,(1485)=217/101

0,6=2/3

0,24= 6/25

2,1485=217/101

a: \(-1,\left(3\right)=-\dfrac{4}{3}\)

b: \(0,\left(72\right)=\dfrac{8}{11}\)

a)

a, \(0,\left(6\right)=\frac{2}{3}\)

b, \(0,\left(24\right)=\frac{8}{33}\)

b) Chọn ý A

dep gai ko yeu tao di

\(0,75=\dfrac{75}{100}=\dfrac{75:25}{100:25}=\dfrac{3}{4}\\ 0,8=\dfrac{8}{10}=\dfrac{8:2}{10:2}=\dfrac{4}{5}\\ 2,15=\dfrac{215}{100}=\dfrac{215:5}{100:5}=\dfrac{43}{20}\)

A) \(0,75=\dfrac{75}{100}=\dfrac{75:25}{100:25}=\dfrac{3}{4}\)

B) \(0,8=\dfrac{8}{10}=\dfrac{8:2}{10:2}=\dfrac{4}{5}\)

C) \(2,15=\dfrac{215}{100}=\dfrac{215:5}{100:5}=\dfrac{43}{20}\)

a) \(0,75=\dfrac{3}{4}\)

b) \(0,8=\dfrac{4}{5}\)

c) \(2,15=\dfrac{43}{20}\)

0,6 = 6 / 10

0,26 = 26 / 100

3,1232 = 31232 / 10000

program Tong_Phan_So;

var

     tu_so1, mau_so1, tu_so2, mau_so2, tu_so_tong, mau_so_tong, ucln: integer;

begin

     write('Nhap tu so phan so 1: ');

     readln(tu_so1);

     write('Nhap mau so phan so 1: ');

     readln(mau_so1);

     write('Nhap tu so phan so 2: ');

     readln(tu_so2);

     write('Nhap mau so phan so 2: ');

     readln(mau_so2);

     tu_so_tong := tu_so1 * mau_so2 + tu_so2 * mau_so1;

     mau_so_tong := mau_so1 * mau_so2;

     ucln := gcd(tu_so_tong, mau_so_tong);

     tu_so_tong := tu_so_tong div ucln;

     mau_so_tong := mau_so_tong div ucln;

     writeln('Tong hai phan so la: ', tu_so_tong, '/', mau_so_tong);

end.

a) \(\dfrac{125}{100}\)

b) 0,25

c) 1/2

a: 125%=5/4

b: 1/4=0,25

c: 50%=1/2

a: 125%=5/4

b: 1/4=0,25

c: 50%=1/2

Ta có:

Chọn đáp án C