tìm x: (10-4x) +120:2^3=17
tim x
a) 2/15-x=3/10 b)(10-4x)+120/23=17a) 2/15-x = 3/10
<=> 45 - 3x = 20
<=> 3x = 45 - 20
<=> 3x = 25
<=> x = 25 : 3
<=> x = 25/3
Vậy x = 25/3
b) ( 10 - 4x ) + 120/23 = 17
<=> ( 10 - 4x ) + 120/8 = 17
<=> ( 10 - 4x ) + 15 = 17
<=> 10 - 4x = 17 - 15
<=> 10 - 4x = 2
<=> 4x = 10 - 2
<=> 4x = 8
<=> x = 8 : 4
<=> x = 2
Vậy x = 2
tìm x biết:a, 72.5-(2x+1)=630:9 b, (10-4x)+120:23=17
72 x 5-(2x+1)=630:9
<=> 49 x 5-2x-1=70
<=> 245-2x-1=70
<=> -2x+244=70
<=> -2x=-174
<=> x=87
tìm x biết:
a, 72.5-(2x+1)=630:9
49.5-(2x+1)=70
245-(2x+1)=70
2x+1=245-70
2x+1=175
2x=175-1
2x=174
x=174:2
x=87
Vậy x=87
b, (10-4x)+120:23=17
(10-4x)+120:8=17
(10-4x)+15=17
10-4x=17-15
10-4x=2
4x=10-2
4x=8
x=8:4
x=2
Vậy x=2
a, 72.5-(2x+1)=630:9
\(\Leftrightarrow\) 49.5-(2x+1)=70
\(\Leftrightarrow\) 245 - (2x+1) = 70
\(\Leftrightarrow\) 2x + 1 = 245 - 70
\(\Leftrightarrow\) 2x + 1 = 175
\(\Leftrightarrow\) 2x = 175 - 1
\(\Leftrightarrow\) 2x = 174
\(\Leftrightarrow\) x = 174 : 2
\(\Leftrightarrow\) x = 87.
Vậy x = 87.
b, (10-4x)+120:23=17
\(\Leftrightarrow\) (10-4x)+120:8 = 17
\(\Leftrightarrow\) (10-4x)+15 = 17
\(\Leftrightarrow\) 10 - 4x = 17 - 15
\(\Leftrightarrow\) 10 - 4x = 2
\(\Leftrightarrow\) 4x = 10 - 2
\(\Leftrightarrow\) 4x = 8
\(\Leftrightarrow\) x = 8 : 4
\(\Leftrightarrow\) x = 2
Vậy x = 2.
# HOK TỐT #
Tìm x:
a, 52x-3-2.52=52.3
b, 740:(x+10)=102-2.13
c, 65-4x+2=20140
d, 120+2.(3x-17)=214
e, 41-2x+1=9
a) 52x - 3 - 2 . 52 = 52 . 3
x - 3/52 - 2 = 3
x = 3 + 2 + 3/52
x = 263/52
b) 740 / (x + 10) = 102 - 2 . 13
740 / (x + 10) = 76
x + 10 = 740 / 76
x + 10 = 185/19
x = 185/19 - 10
x = -5/19
c) 65 - 4x + 2 = 20140
65 - 4x = 20140 - 2
65 - 4x = 20138
4x = 65 - 20138
4x = -20073
x = -20073/4
d) 120 + 2 . (3x - 17) = 214
60 + 3 . x - 17 = 107
20 + x - 17/3 = 107/3
20 + x = 107/3 + 17/3
20 + x = 124/3
x = 124/3 - 20
x = 64/3
e) 41 - 2x + 1 = 9
42 - 2x = 9
21 - x = 9/2
x = 21 - 9/2
x = 33/2
(10-4x)+120 : 2^3=17
\(\left(10-4x\right)+120\div2^3=17\)
\(\left(10-4x\right)+120\div8=17\)
\(\left(10-4x\right)+15=17\)
\(10-4x=17-15\)
\(10-4x=2\)
\(4x=10-2\)
\(4x=8\)
\(x=8\div4\)
\(x=2\)
(10-4x)+120:2^3=17
(10-4x)+120= 17.2^3
(10-4x)+120=17.8
(10-4x)+120=136
10-4x= 136-120
10-4x= 16
4x= 10-16
4x=10+(-16)
4x=-6
x= -6:4
x=-1,5
(10-4x)+120 : 2^3=17
(10-4x)+120 : 8 =17
(10-4x)+120 =17.8
(10-4x)+120 =136
10-4x =136-120
10-4x =16
4x =10-16
4x = -6
x =-6:4
x = -1,5
nhớ tk cho mình vs nha
thank you
1. Tìm x biết
a. 8x +56 : 14 = 60
b. 52x-3- 2.52 = 52 . 3
c. 41- 2x+1=9
d.32x-4-x0= 8
g) 65-4x+2=20140
i. 120+ 2.(4x-17) =214
a) \(8x+56:14=60\)
\(\Rightarrow8x+4=60\)
\(\Rightarrow8x=56\)
\(\Rightarrow x=\dfrac{56}{8}\)
\(\Rightarrow x=7\)
b) Mình làm rồi nhé !
c) \(41-2^{x+1}=9\)
\(\Rightarrow2^{x+1}=41-9\)
\(\Rightarrow2^{x+1}=32\)
\(\Rightarrow2^{x+1}=2^5\)
\(\Rightarrow x+1=5\)
\(\Rightarrow x=4\)
d) \(3^{2x-4}-x^0=8\)
\(\Rightarrow3^{2x-4}-1=8\)
\(\Rightarrow3^{2x-4}=9\)
\(\Rightarrow3^{2x-4}=3^2\)
\(\Rightarrow2x-4=2\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=3\)
g) \(65-4^{x+2}=2014^0\)
\(\Rightarrow65-4^{x+2}=1\)
\(\Rightarrow4^{x+2}=64\)
\(\Rightarrow4^{x+2}=4^3\)
\(\Rightarrow x+2=3\)
\(\Rightarrow x=1\)
i) \(120+2\left(4x-17\right)=214\)
\(\Rightarrow2\left(4x-17\right)=214-120\)
\(\Rightarrow2\left(4x-17\right)=94\)
\(\Rightarrow4x-17=47\)
\(\Rightarrow4x=47+17\)
\(\Rightarrow4x=64\)
\(\Rightarrow x=16\)
a: \(8x+56:14=60\)
=>8x+4=60
=>8x=60-4=56
=>x=56/8=7
b: \(5^{2x-3}-2\cdot5^2=5^2\cdot3\)
=>\(5^{2x-3}=5^2\cdot3+2\cdot5^2=5^3\)
=>2x-3=3
=>2x=6
=>x=3
c: \(41-2^{x+1}=9\)
=>\(2^{x+1}=41-9=32\)
=>x+1=5
=>x=4
d: \(3^{2x-4}-x^0=8\)
=>\(3^{2x-4}-1=8\)
=>\(3^{2x-4}=8+1=9\)
=>2x-4=2
=>2x=6
=>x=3
g: \(65-4^{x+2}=2014^0\)
=>\(65-4^{x+2}=1\)
=>\(4^{x+2}=65-1=64\)
=>x+2=3
=>x=1
i: 120+2(4x-17)=214
=>2(4x-17)=214-120=94
=>4x-17=94/2=47
=>4x=64
=>\(x=\dfrac{64}{4}=16\)
tìm x : a. (10-4x )+120:8 b. 2/15-x=3/10
bài 7
4x3 + 12 = 120
b, ( x - 4 )2 = 64
c, ( x + 1 )3 - 2 = 52
d, 136 - ( x + 5)2 = 100
e, 4x = 16
f, 7x. 3 - 147 = 0
g, 2x+3 - 15 = 17
h, 52x-4. 4 = 102
i, (32 - 4x)(7 - x) = 0
k, ( 8 - x)(10 - 2x) = 0
m, 3x + 3x+1 = 108
n, 5x+2 + 5x+1 = 750
a: \(4x^3+12=120\)
=>\(4x^3=108\)
=>\(x^3=27=3^3\)
=>x=3
b: \(\left(x-4\right)^2=64\)
=>\(\left[{}\begin{matrix}x-4=8\\x-4=-8\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=12\\x=-4\end{matrix}\right.\)
c: (x+1)^3-2=5^2
=>\(\left(x+1\right)^3=25+2=27\)
=>x+1=3
=>x=2
d: 136-(x+5)^2=100
=>(x+5)^2=36
=>\(\left[{}\begin{matrix}x+5=6\\x+5=-6\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=1\\x=-11\end{matrix}\right.\)
e: \(4^x=16\)
=>\(4^x=4^2\)
=>x=2
f: \(7^x\cdot3-147=0\)
=>\(3\cdot7^x=147\)
=>\(7^x=49\)
=>x=2
g: \(2^{x+3}-15=17\)
=>\(2^{x+3}=32\)
=>x+3=5
=>x=2
h: \(5^{2x-4}\cdot4=10^2\)
=>\(5^{2x-4}=\dfrac{100}{4}=25\)
=>2x-4=2
=>2x=6
=>x=3
i: (32-4x)(7-x)=0
=>(4x-32)(x-7)=0
=>4(x-8)*(x-7)=0
=>(x-8)(x-7)=0
=>\(\left[{}\begin{matrix}x-8=0\\x-7=0\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}x=8\\x=7\end{matrix}\right.\)
k: (8-x)(10-2x)=0
=>(x-8)(x-5)=0
=>\(\left[{}\begin{matrix}x-8=0\\x-5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=8\\x=5\end{matrix}\right.\)
m: \(3^x+3^{x+1}=108\)
=>\(3^x+3^x\cdot3=108\)
=>\(4\cdot3^x=108\)
=>\(3^x=27\)
=>x=3
n: \(5^{x+2}+5^{x+1}=750\)
=>\(5^x\cdot25+5^x\cdot5=750\)
=>\(5^x\cdot30=750\)
=>\(5^x=25\)
=>x=2
Tìm x,biết:
a,72,5-(2x+1)=630:9
b,(10-4x)+120:23=17
c,[124-(20-4x):30+7=11
d,/2x-5/=1
a) 72,5 - (2x + 1) = 630 : 9
⇒ 72,5 - (2x + 1) = 70
⇒ 2x + 1 = 2,5
⇒ 2x = 1,5
⇒ x = 0,75
b) (10 - 4x) + 120 : 23 = 17
⇒ (10 - 4x) + 120 : 8 = 17
⇒ (10 - 4x) + 15 = 17
⇒ 10 - 4x = 2
⇒ 4x = 8
⇒ x = 2
Vậy x = 2
c) [124 - (20 - 4x)] : 30 + 7 = 11
⇒ [124 - (20 - 4x)] : 30 = 4
⇒ 124 - (20 - 4x) = 120
⇒ 20 - 4x = 4
⇒ 4x = 16
⇒ x = 4
Vậy x = 4
Tìm x ∈ N, biết (10 – 4x) + 120 : 23 = 1 + 42
TBR, Ta có:
(100 – 4x) + 120 : 23 = 1 + 42
\(\Rightarrow\) 10 – 4x + 15 = 17
= 25 – 4x = 17 \(\Rightarrow\) 4x = 25 – 17 \(\Rightarrow\) 4x = 25 – 17
\(\Rightarrow\) 4x = 8 \(\Rightarrow\)x = 8 : 4 = 2
\(\left(10-4x\right)+120:2^3=1+4^2\)
\(\Rightarrow\) \(\left(10-4x\right)+120:8=17\)
\(\Rightarrow\) \(\left(10-4x\right)+15=17\)
\(\Rightarrow\) \(10-4x=2\)
\(\Rightarrow\) \(4x=8\)
\(\Rightarrow\) \(x=2\)
(10 - 4x) + 120 : 23 = 1 + 42
(10 - 4x) + 120 : 23 = 1 + 16 = 17
(10 - 4x) + 120 : 8 = 17
(10 - 4x) + 15 = 17
10 - 4x = 17 - 15 = 2
4x = 10 - 2 = 8
x = 8 : 4
x = 2
Vậy x = 2
Good Luck!