90 + x = 100

        x = 100 - 90

        x = 10

x - 10 = 90

      x = 90 + 10

     x = 100

x - 90 = 10

      x = 10 + 90

      x = 100

k 

90 + x = 100

x = 100 - 90

x = 10

x - 10 = 90

x = 90 + 10

x = 100

x - 90 = 10

x = 10 + 90

x = 100

90 + x = 100

x = 100 - 90

x = 10

x - 10 = 90

x = 10 + 90

x = 100

x - 90 = 10

x = 10 + 90

x = 100

Xong rùi k nhé

b)

`15-3(3x+18)=36`

`=> 3(3x+18)=15-36`

`=> 3(3x+18)=-21`

`=> 3x+18=-21:3`

`=> 3x+18=-7`

`=> 3x=-7-18`

`=> 3x=-25`

`=> x=-25:3`

`=> x=-25/3`

c)

`-12+(3-x)=25`

`=>-12+3-x=25`

`=>-x=25+12-3`

`=>-x=34`

`=>x=-34`

d)

`100-90xx(x:2-1)=-10`

`=>90xx(x:2-1)=100-(-10)`

`=>90xx(x:2-1)=110`

`=>x:2-1=110:90`

`=>x:2-1=11/9`

`=>x:2=11/9 +1`

`=> x:2=20/9`

`=> x=20/9 xx2`

`=> x=40/9`

1 + 90 x 3,14 = 283,6 

90 + 10 x 100 = 1090

~ Ko có gì đâu :) ~
#JH

1 + 90 x 3,14 = 283,6 

90 + 10 x 100 = 1090

~ Ko có gì đâu :) ~
#JH

1 + 90 x 3,14 = 283,6 

90 + 10 x 100 = 1090

~ Ko có gì đâu :) ~
#JH

\(x+90=100+10\)

\(x+90=110\)

\(x=110-90\)

\(x=20\)

x + 90 = 100 + 10

x + 90 = 110

        x = 110 - 90

        x = 20                              ai k mk,mk k lai

20 nha

Tính nhanh:

=250

Tìm x:

x=4

x=1000

x=2

k minh di minh k lai cho giup minh khoi phuc lai diem am nha!!!!!

Tính nhanh

10 + 10 + 10 + 10 + 10 + 1 + 9 + 100 + 90

= (10 x 5) + (1 + 9 + 90) + 100

= 50 + ( 1 + 9 + 90 )  + 100

= 50 + 100 + 100

= 150 + 100

= 250

Tìm x 

6x = 24

x = 24 : 6

x = 4

_____________________

x - 999 = 1

x = 1 + 999

x = 1000

_____________________

32 - x = 30

x = 32 - 30

x = 2

cau a 250

b=4

c=1000 d=2

a) \(\left(\dfrac{1}{2}+\dfrac{1}{6}+...+\dfrac{1}{90}\right)\cdot100-\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right]:\dfrac{1}{2}=89\)

\(\Rightarrow\left(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+...+\dfrac{1}{9\cdot10}\right)\cdot100-\left[\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)\right]:\dfrac{1}{2}=89\)

\(\Rightarrow\left(1-\dfrac{1}{2}+\dfrac{1}{2}-...+\dfrac{1}{9}-\dfrac{1}{10}\right)\cdot100-\left[\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)\right]:\dfrac{1}{2}=89\)

\(\Rightarrow\left(1-\dfrac{1}{10}\right)\cdot100-\left[\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)\right]:\dfrac{1}{2}=89\)

\(\Rightarrow\dfrac{9}{10}\cdot100-\left[\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)\right]:\dfrac{1}{2}=89\)

\(\Rightarrow90-\left[\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)\right]:\dfrac{1}{2}=89\)

\(\Rightarrow\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)=90-89\)

\(\Rightarrow\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)=1\)

\(\Rightarrow x+\dfrac{103}{50}=\dfrac{5}{2}\)

\(\Rightarrow x=\dfrac{11}{25}\)

b) \(x\cdot9,85+x\cdot0,15=0,1\)

\(\Rightarrow x\cdot\left(9,85+0,15\right)=0,1\)

\(\Rightarrow x\cdot10=0,1\)

\(\Rightarrow x=\dfrac{0,1}{10}\)

\(\Rightarrow x=0,01\)

c) \(\dfrac{2}{5}+2022x=\dfrac{4}{10}\)

\(\Rightarrow\dfrac{2}{5}+2022x=\dfrac{2}{5}\)

\(\Rightarrow2022x=\dfrac{2}{5}-\dfrac{2}{5}\)

\(\Rightarrow2022x=0\)

\(\Rightarrow x=\dfrac{0}{2022}\)

\(\Rightarrow x=0\)

a) \(\left(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+...+\dfrac{1}{90}\right).100-\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right]:\dfrac{1}{2}=89\left(1\right)\)

Ta có :

\(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+...+\dfrac{1}{90}\)

\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{9}-\dfrac{1}{10}\)

\(=1-\dfrac{1}{10}=\dfrac{9}{10}\)

\(\left(1\right)\Rightarrow\dfrac{9}{10}.100-\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right]:\dfrac{1}{2}=89\)

\(\Rightarrow90-\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right].2=89\)

\(\Rightarrow\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right].2=90-89\)

\(\Rightarrow\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)=\dfrac{1}{2}\)

\(\Rightarrow x+\dfrac{206}{100}=\dfrac{5}{2}:\dfrac{1}{2}\)

\(\Rightarrow x+\dfrac{103}{50}=\dfrac{5}{2}.\dfrac{2}{1}\)

\(\Rightarrow x+\dfrac{103}{50}=5\)

\(\Rightarrow x=5-\dfrac{103}{50}\)

\(\Rightarrow x=\dfrac{250}{50}-\dfrac{103}{50}\)

\(\Rightarrow x=\dfrac{147}{50}\)