Cho bieu thuc:
\(P=\frac{x+2}{x+3}-\frac{5}{x^2+x+6}+\frac{1}{2-x}\)voi \(x\ne-3;x\ne2\)
a, Rut gon P
b, tim x de \(P=\frac{-3}{4}\)
c,tim x nguyen de P dat gia tri nguyen
(mk dang can gap ai giai dung dau tien mk tick cho)
Những câu hỏi liên quan
cho bieu thuc:P=\(\frac{\sqrt{x}}{\sqrt{x}-3}\)+\(\frac{2\sqrt{x}}{\sqrt{x}-3}\)--\(\frac{3x+9}{x-9}\) voi x>= 0;x#9 .a; Rut gon bieu thuc P . b; Tinh gia tri cua bieu thuc voi \(x=4-2\sqrt{3}\)
Tim GTNN cua bieu thuc sau:
Q= \(\frac{-2\sqrt{3x}}{3+x}\) ( voi x≥0, x≠-3)
Đặt \(\sqrt{3x}=t\ge0\Rightarrow x=\frac{t^2}{3}\)
\(Q\left(t\right)=\frac{-2t}{3+\frac{t^2}{3}}=\frac{-6t}{t^2+9}\)
\(\Rightarrow Q'\left(t\right)=\frac{-6\left(t^2+9\right)+12t^2}{\left(t^2+9\right)^2}=\frac{6\left(t^2-9\right)}{\left(t^2+9\right)^2}\)
\(Q'\left(t\right)=0\Rightarrow t=3\)
\(Q\left(0\right)=0\) ; \(Q\left(3\right)=-1\)
Dựa vào BBT, ta thấy \(Q_{min}=-1\) khi \(t=3\Rightarrow x=3\)
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1) Cho bieu thuc A=\(3+\frac{2}{x-1}\). Tinh gia tri cua bieu thuc A khi |2x-3|=1
2) Rut gon bieu thuc B=\(\frac{x}{x-1}\)-\(\frac{x-5}{x+1}\)-\(\frac{3-x}{1-x^2}\)
3) Tim cac gia tri nguyen cua x de bieu thuc \(\frac{B}{A}\)co gia tri nguyen duong
I Cho bieu thucA ( frac{2x+1}{2x-1}- frac{2x-1}{2x+1}) : frac{8x}{3-6x}( voi x khac + - frac{1}{2}x khax 0 )a . Rut gon bieu thuc Ab . Tim x de A frac{3}{-4031}II Cho bieu thuc B ( frac{1}{1-x}+frac{2}{x+1}-frac{5-x}{1-x^2}) : frac{1-2x}{x^2-4}a . Rut gon bieu thuc Bb . Tìm giá trị nguyên của x để giá trị của biểu thức B là số nguyên
Đọc tiếp
I> Cho bieu thuc
A = ( \(\frac{2x+1}{2x-1}\)- \(\frac{2x-1}{2x+1}\)) : \(\frac{8x}{3-6x}\)( voi x khac + - \(\frac{1}{2}\)x khax 0 )
a . Rut gon bieu thuc A
b . Tim x de A = \(\frac{3}{-4031}\)
II> Cho bieu thuc
B = ( \(\frac{1}{1-x}\)+\(\frac{2}{x+1}\)-\(\frac{5-x}{1-x^2}\)) : \(\frac{1-2x}{x^2-4}\)
a . Rut gon bieu thuc B
b . Tìm giá trị nguyên của x để giá trị của biểu thức B là số nguyên
Cho bieu thuc:
P=\(\frac{1}{\sqrt{x}+2}-\frac{5}{x-\sqrt{x}-6}-\frac{\sqrt{x}-2}{3-\sqrt{x}}\)
a. Rut gon bieu thuc P
b.Tim GTLN cua P sau khi rut gon
đk: x>=0; x khác 3
a) \(P=\frac{\sqrt{x}-3}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-3\right)}-\frac{5}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-3\right)}+\frac{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}{\sqrt{x}-3}=\frac{\sqrt{x}-3-5+x-4}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-3\right)}=\frac{x+\sqrt{x}-12}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-3\right)}\)
\(P=\frac{\left(\sqrt{x}+4\right)\left(\sqrt{x}-3\right)}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-3\right)}=\frac{\sqrt{x}+4}{\sqrt{x}+2}\)
b) \(P=\frac{\sqrt{x}+2+2}{\sqrt{x}+2}=1+\frac{2}{\sqrt{x}+2}\)
ta có: \(x\ge0\Rightarrow\sqrt{x}\ge0\Leftrightarrow\sqrt{x}+2\ge2\Leftrightarrow\frac{2}{\sqrt{x}+2}\le1\Leftrightarrow1+\frac{2}{\sqrt{x}+2}\le2\Rightarrow MaxP=2\Rightarrow x=0\)
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1) Cho bieu thuc: \(B=\left(\frac{\sqrt{x}}{\sqrt{x}+4}+\frac{4}{\sqrt{x}-4}\right):\frac{x+16}{\sqrt{x}+2}\left(x\ge0,x\ne16\right)\)
a) Cho bieu thuc A= \(\frac{\sqrt{x}+4}{\sqrt{x}+2}\) ; voi cac cua bieu thuc A va B da cho, hay tim cac gia tri cua x nguyen de gia tri cua bieu thuc B(A;-1) la so nguyen
Cho bieu thuc \(A=\left(\frac{x+1}{x-1}-\frac{x-1}{x+1}+\frac{x^2-4x-1}{x^2-1}\right).\frac{x+2016}{x}\)
a, Voi gia tri nguyen nao cua x thi bieu thuc A co gia tri nguyen
b,Voi gia tri nao cua x thi A co gia tri duong
1. biết x2-2y2=xy,y\(\ne\)0,x+y\(\ne\)0. thì gia tri cua bieu thuc Q=\(\frac{x+y}{x-y}\)=
2.cho x\(\ne\)0,y\(\ne\)0 thoa man x+y=4 ;xy=2 .gia tri cua bieu thuc A=\(\frac{1}{x^3}+\frac{1}{y^3}\)la
3.gia tri cua bieu thuc A=\(\frac{81^8-1}{\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)}\)la
Bài 3:
Ta có:
\(81^8-1=\left(9^2\right)^8-1=\left[\left(3^2\right)^2\right]^8-1=3^{32}-1\)
\(=\left(3^4-1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)\)
Do đó:
\(A=3^4-1=80\)
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Cho bieu thuc: \(p=\left(\frac{1}{\sqrt{x}-\sqrt{x-1}}-\frac{x-3}{\sqrt{x-1}-\sqrt{2}}\right)\left(\frac{2}{\sqrt{2}-\sqrt{x}}-\frac{\sqrt{x}+\sqrt{2}}{\sqrt{2x}-x}\right)\)
a) Tim DKXD cua bieu thuc p
b) Rut gon bieu thuc p