1: 

Độ dài cạnh còn lại là:

4/15:2/17=34/15(m)

Bài 2:

Thể tích nước trong bể chưa đầy chiếm:

1-2/5=3/5(bể)

Thời gian để bể đầy là:

3/5:1/5=3(giờ)

a: Ta có: \(\left|x+\dfrac{1}{2}\right|\ge0\forall x\)

\(\left|y-\dfrac{3}{4}\right|\ge0\forall y\)

\(\left|z-1\right|\ge0\forall z\)

Do đó: \(\left|x+\dfrac{1}{2}\right|+\left|y-\dfrac{3}{4}\right|+\left|z-1\right|\ge0\forall x,y,z\)

Dấu '=' xảy ra khi \(\left(x,y,z\right)=\left(-\dfrac{1}{2};\dfrac{3}{4};1\right)\)

c) \(\dfrac{\sqrt{x}-1}{3}\left(\dfrac{\sqrt{x}+1}{\sqrt{x}-2}-\dfrac{\sqrt{x}+2}{\sqrt{x}-1}\right)\)

\(=\dfrac{\sqrt{x}-1}{3}.\dfrac{\sqrt{x}+1}{\sqrt{x}-2}-\dfrac{\sqrt{x}-1}{3}.\dfrac{\sqrt{x}+2}{\sqrt{x}-1}\)

\(=\dfrac{x-1}{3\left(\sqrt{x}-2\right)}-\dfrac{\sqrt{x}+2}{3}\)

\(=\dfrac{x-1}{3\left(\sqrt{x}-2\right)}-\dfrac{\left(\sqrt{x}+2\right)\left(\sqrt{x}-2\right)}{3\left(\sqrt{x}-2\right)}\)

\(=\dfrac{x-1}{3\left(\sqrt{x}-2\right)}-\dfrac{x-4}{3\left(\sqrt{x}-2\right)}\)

\(=\dfrac{x-1-x+4}{3\left(\sqrt{x}-2\right)}\)

\(=\dfrac{3}{3\left(\sqrt{x}-2\right)}\)

\(=\dfrac{1}{\sqrt{x}-2}\)

bt trong dấu ngoặc bn nhân lên hợp ⇒ rút gọn ⇒ nhân với bt ngoài dấu ngoặc ⇒ rút gọn thôi á

mk gợi ý vậy thôi nha, chứ h giải ra thì lâu lắm=((

chúc bn làm bài tốt nka^3^

a: x=3/4-1/3=9/12-4/12=5/12

b: 1/3x=2/3-5/9=6/9-5/9=1/9

=>x=1/3

c: =>3x=6/5-3/4-7/4=6/5-5/2=12/10-25/10=-13/10

=>x=-13/30

d: =>x+2/5-2/3=5/3

=>x=5/3+2/3-3/5=7/3-3/5=35/15-9/15=26/15

e: =>1/4:x=2/5-3/4=8/20-15/20=-7/20

=>x=-1/4:7/20=-1/4*20/7=-20/28=-5/7

f: =>1/4x-3/4=1/2-25/4=2/4-25/4=-23/4

=>1/4x=-20/4

=>x=-20

Bài 3.4

a; \(\dfrac{36}{84}\) = \(\dfrac{42}{98}\) 

\(\dfrac{36}{84}\) = \(\dfrac{36:12}{84:12}\) = \(\dfrac{3}{7}\)

\(\dfrac{42}{98}\) = \(\dfrac{42:14}{98:14}\) = \(\dfrac{3}{7}\)

Vậy \(\dfrac{36}{84}\) = \(\dfrac{42}{98}\) (đpcm)

b; \(\dfrac{123}{237}\) = \(\dfrac{123123}{237237}\)  

  \(\dfrac{123123}{237237}\) = \(\dfrac{123123:1001}{237237:1001}\) = \(\dfrac{123}{237}\) (đpcm)