A=\(\frac{9^2\times5^3\times2^3}{2^3\times9}\)=\(\frac{9\times5^3}{1}\)=1125

B= 24.325+24x276+24.389 = 24x(325+276+389) = 24x990 = 23760

\(=24.325+276.24+24.399\)

\(=24.\left(325+276+399\right)\)

\(=24.1000=24000\)

 Câu a, chịu

Câu b

= ( 2.12) .325 + 4.69.24 + ( 3.8 ) .389

= 24. 325 + 276 .24 + 24. 389

= 24.( 325 + 276 + 389)

= 24. 990

= 23 760

Cứ thấy đề bài sai sai sao í

Ta thấy :

2 . 12 = 3 . 8 = 24

( 24 . 325 + 24 . 389 ) + 4 . 286

= [ 24 . ( 325 + 389 ) ] + 4 . 286

= [ 24 . 714 ] + 4 . 286

.....

59.289

Tính giá trị biểu thức:

1.2004+2.2003+3.2002+...+2004.1 / 1.2+2.3+3.4+...+2004.2005

TK

24000

24000

=24.325+276.24+24.399

=24.(325+276+399)

=24.1000

=24000

2 . 325 . 12 + 4 . 69 . 24 + 3 . 399 . 8

= 24 . ( 325 + 276 + 399 )

= 24 . 1000

= 24000

Ủng hộ nha

2 x 325 x 12 + 4 x 69 + 24 + 3 x 399 x 8

= 24 x 325 + 276 x 24 + 24 x 399

= 24 x ( 325 + 276 + 399 )

= 24 x 1000

= 24 000

= 24 . 325 + 24. 276 + 24 . 399

= 24 . (325 + 276 + 399)

= 24 . 1000

= 24000

b:\(=\dfrac{3^3\cdot2^3+3\cdot2^2\cdot3^2+3^3}{-13}=\dfrac{3^3\left(2^3+2^2+1\right)}{-13}=-3^3=-27\)

a: \(=\dfrac{5^5\cdot4^5\cdot5^{10}}{10^{20}}=\dfrac{5^{15}\cdot2^{10}}{5^{20}\cdot2^{20}}=\dfrac{1}{5^5\cdot2^{10}}\)

b) \(\dfrac{6^3+3.6^2+3^3}{-13}=\dfrac{2^3.3^3+3.3^2.2^2+3^3}{-13}=\dfrac{3^3\left(2^3+2^2+1\right)}{-13}\)

\(=\dfrac{3^3.\left(8+4+1\right)}{-13}=\dfrac{3^3.13}{-13}=\dfrac{27}{-1}=-27\)

a)\(\dfrac{20^5.5^{10}}{100^5}=\dfrac{20^5.5^{10}}{20^5.5^5}=\dfrac{5^5}{1}=3125\)